Sqlite目的関数cの挿入エラー

Question

sqliteを使用していて、sqliteデータベースにデータを挿入しようとしました。これは動作しません。私は名前がLabUpdateある一つのテーブルを持っていますが、私はこのようないくつかのエラーがあります。このような

2012-04-02 08:49:58.158 SqliteDeneme[361:207] Failed from sqlite3_prepare_v2. Error is: no such column: deneme 
2012-04-02 08:49:58.159 SqliteDeneme[361:207] Compiled Statement has error code:1:INSERT INTO LabUpdate (IsSuccess, ProducerId, Latitude, Longitude, Altitude, Slope, SampleDate, PackageNo, Status, Description) VALUES(1,1,0.100000,0.100000,0.100000,0.100000,deneme,1,1,deneme) 
2012-04-02 08:49:58.160 SqliteDeneme[361:207] ExecuteNonQuery has error 
2012-04-02 08:49:58.160 SqliteDeneme[361:207] Failed from sqlite3_step. Error is: library routine called out of sequence 

マイコード：

- (IBAction)buttonClick:(id)sender { 

NSFileManager *fileMgr = [NSFileManager defaultManager]; 
NSString *dbPath = [[[NSBundle mainBundle] resourcePath ]stringByAppendingPathComponent:@"SqliteTestDb.sqlite"]; 
BOOL success = [fileMgr fileExistsAtPath:dbPath]; 
if(!success) 
{ 
    NSLog(@"Cannot locate database file '%@'.", dbPath); 
} 
if(!(sqlite3_open([dbPath UTF8String], &cruddb) == SQLITE_OK)) 
{ 
    NSLog(@"An error has occured."); 
} 

if(sqlite3_open([dbPath UTF8String], &cruddb) ==SQLITE_OK){ 

int str1 =1; 
int str2 =1; 
float str3 =0.1; 
float str4 =0.1; 
float str5 =0.1; 
float str6 =0.1; 
NSString *str7 =@"deneme"; 
int str8 =1; 
int str9 =1; 
NSString *str10=@"deneme"; 

NSString* SQL = [NSString stringWithFormat:@"INSERT INTO LabUpdate (IsSuccess, ProducerId, Latitude, Longitude, Altitude, Slope, SampleDate, PackageNo, Status, Description) VALUES(%i,%i,%f,%f,%f,%f,%@,%i,%i,%@)",str1,str2,str3,str4,str5,str6,str7,str8,str9,str10]; 

stmt = [self prepare:SQL]; 

    sqlite3_step(stmt); 
    sqlite3_finalize(stmt); 
    sqlite3_close(cruddb); 

if (sqlite3_step(stmt) != SQLITE_DONE) 
{ 
    NSLog(@"ExecuteNonQuery has error"); 
    NSLog(@"Failed from sqlite3_step. Error is: %s", sqlite3_errmsg(cruddb)); 

} 
else 
{ 
    int rowsaffected = sqlite3_changes(cruddb); 
    NSLog(@" rowsaffected %i",rowsaffected); 
} 

} 
} 

-(sqlite3_stmt*)prepare:(NSString*)query 
{ 
sqlite3_stmt *queryHandle; 


const char *sqlStatement = (const char *) [query UTF8String]; 

if(sqlite3_prepare_v2(cruddb, sqlStatement, -1, &queryHandle, NULL) != SQLITE_OK) 
{ 
    int error = sqlite3_prepare_v2(cruddb, sqlStatement, -1, &queryHandle, NULL); 

    NSLog(@"Failed from sqlite3_prepare_v2. Error is: %s", sqlite3_errmsg(cruddb)); 

    NSLog(@"Compiled Statement has error code:%i:%@",error,query); 
} 

return queryHandle; 
} 

問題は何ですか？これをどうすれば解決できますか？お返事をありがとうございます。

Answer 1

SQL文を実行しようとすると、数値ではないものはすべて引用符で囲む必要があります。

INSERT INTO foo (column1, column2) VALUES ('bar' , 'baz'); 
             // ^^^^^ ^^^^^ string values quoted. 

しかし、私は強く直接SQL文に書式設定値の代わりにsqlite3_bindを使用することをお勧めし。