あなたは、たとえば、結果のデータを保持するために、「辞書の辞書」を使用することができます
// Building ID ↓ ↓ Improvement ID
var data = new Dictionary<int, Dictionary<int, Result>>();
これは、あなたがすぐに特定の建物のための改善点を見つけてみましょうでしょう。
しかし、特定の改善を含む建物を見つけるには、すべての建物を繰り返し処理する必要があります。ここではいくつかのサンプルコードです:
using System;
using System.Linq;
using System.Collections.Generic;
namespace Demo
{
sealed class Result
{
public double Data;
}
sealed class Building
{
public int Id;
public int Value;
}
sealed class Improvement
{
public int Id;
public int Value;
}
class Program
{
void run()
{
// Building ID ↓ ↓ Improvement ID
var data = new Dictionary<int, Dictionary<int, Result>>();
for (int buildingKey = 1000; buildingKey < 2000; ++buildingKey)
{
var improvements = new Dictionary<int, Result>();
for (int improvementKey = 5000; improvementKey < 5030; ++improvementKey)
improvements.Add(improvementKey, new Result{ Data = buildingKey + improvementKey/1000.0 });
data.Add(buildingKey, improvements);
}
// Aggregate data for all improvements for building with ID == 1500:
int buildingId = 1500;
var sum = data[buildingId].Sum(result => result.Value.Data);
Console.WriteLine(sum);
// Aggregate data for all buildings with a given improvement.
int improvementId = 5010;
sum = data.Sum(improvements =>
{
Result result;
return improvements.Value.TryGetValue(improvementId, out result) ? result.Data : 0.0;
});
Console.WriteLine(sum);
}
static void Main()
{
new Program().run();
}
}
}
(与えられたIDを持つすべての改善のためのデータを合計するための)第2の集約をスピードアップするために、我々は第二の辞書を使用することができます。
// Improvment ID ↓ ↓ Building ID
var byImprovementId = new Dictionary<int, Dictionary<int, Result>>();
あなたは余分な辞書を持っているでしょう維持するが、それほど複雑ではない。このようにいくつかのネストされた辞書を持つと、あまりにも多くのメモリを取るかもしれませんが、考慮する価値があります。
以下のコメントに記載されているように、IDと辞書自体の型を定義する方が良いでしょう。一緒にそれを置くことはできます:
using System;
using System.Linq;
using System.Collections.Generic;
namespace Demo
{
sealed class Result
{
public double Data;
}
sealed class BuildingId
{
public BuildingId(int id)
{
Id = id;
}
public readonly int Id;
public override int GetHashCode()
{
return Id.GetHashCode();
}
public override bool Equals(object obj)
{
var other = obj as BuildingId;
if (other == null)
return false;
return this.Id == other.Id;
}
}
sealed class ImprovementId
{
public ImprovementId(int id)
{
Id = id;
}
public readonly int Id;
public override int GetHashCode()
{
return Id.GetHashCode();
}
public override bool Equals(object obj)
{
var other = obj as ImprovementId;
if (other == null)
return false;
return this.Id == other.Id;
}
}
sealed class Building
{
public BuildingId Id;
public int Value;
}
sealed class Improvement
{
public ImprovementId Id;
public int Value;
}
sealed class BuildingResults : Dictionary<BuildingId, Result>{}
sealed class ImprovementResults: Dictionary<ImprovementId, Result>{}
sealed class BuildingsById: Dictionary<BuildingId, ImprovementResults>{}
sealed class ImprovementsById: Dictionary<ImprovementId, BuildingResults>{}
class Program
{
void run()
{
var byBuildingId = CreateTestBuildingsById(); // Create some test data.
var byImprovementId = CreateImprovementsById(byBuildingId); // Create the alternative lookup dictionaries.
// Aggregate data for all improvements for building with ID == 1500:
BuildingId buildingId = new BuildingId(1500);
var sum = byBuildingId[buildingId].Sum(result => result.Value.Data);
Console.WriteLine(sum);
// Aggregate data for all buildings with a given improvement.
ImprovementId improvementId = new ImprovementId(5010);
sum = byBuildingId.Sum(improvements =>
{
Result result;
return improvements.Value.TryGetValue(improvementId, out result) ? result.Data : 0.0;
});
Console.WriteLine(sum);
// Aggregate data for all buildings with a given improvement using byImprovementId.
// This will be much faster than the above Linq.
sum = byImprovementId[improvementId].Sum(result => result.Value.Data);
Console.WriteLine(sum);
}
static BuildingsById CreateTestBuildingsById()
{
var byBuildingId = new BuildingsById();
for (int buildingKey = 1000; buildingKey < 2000; ++buildingKey)
{
var improvements = new ImprovementResults();
for (int improvementKey = 5000; improvementKey < 5030; ++improvementKey)
{
improvements.Add
(
new ImprovementId(improvementKey),
new Result
{
Data = buildingKey + improvementKey/1000.0
}
);
}
byBuildingId.Add(new BuildingId(buildingKey), improvements);
}
return byBuildingId;
}
static ImprovementsById CreateImprovementsById(BuildingsById byBuildingId)
{
var byImprovementId = new ImprovementsById();
foreach (var improvements in byBuildingId)
{
foreach (var improvement in improvements.Value)
{
if (!byImprovementId.ContainsKey(improvement.Key))
byImprovementId[improvement.Key] = new BuildingResults();
byImprovementId[improvement.Key].Add(improvements.Key, improvement.Value);
}
}
return byImprovementId;
}
static void Main()
{
new Program().run();
}
}
}
は最後に、ここでは、特定の改善のための建物/改善の組み合わせのすべてのインスタンスのデータを集計するのにかかる時間を決定し、辞書でタプルの辞書の結果を比較して修正されたバージョンです辞書の任意のデバッガ外で実行リリースビルドのための
マイ結果:
Dictionary of dictionaries took 00:00:00.2967741
Dictionary of tuples took 00:00:07.8164672
これは、辞書の辞書を使用するために非常に高速ですが、あなたはこれらの集計の多くを行うつもり場合にのみ重要です。
using System;
using System.Diagnostics;
using System.Linq;
using System.Collections.Generic;
namespace Demo
{
sealed class Result
{
public double Data;
}
sealed class BuildingId
{
public BuildingId(int id)
{
Id = id;
}
public readonly int Id;
public override int GetHashCode()
{
return Id.GetHashCode();
}
public override bool Equals(object obj)
{
var other = obj as BuildingId;
if (other == null)
return false;
return this.Id == other.Id;
}
}
sealed class ImprovementId
{
public ImprovementId(int id)
{
Id = id;
}
public readonly int Id;
public override int GetHashCode()
{
return Id.GetHashCode();
}
public override bool Equals(object obj)
{
var other = obj as ImprovementId;
if (other == null)
return false;
return this.Id == other.Id;
}
}
sealed class Building
{
public BuildingId Id;
public int Value;
}
sealed class Improvement
{
public ImprovementId Id;
public int Value;
}
sealed class BuildingResults : Dictionary<BuildingId, Result>{}
sealed class ImprovementResults: Dictionary<ImprovementId, Result>{}
sealed class BuildingsById: Dictionary<BuildingId, ImprovementResults>{}
sealed class ImprovementsById: Dictionary<ImprovementId, BuildingResults>{}
class Program
{
void run()
{
var byBuildingId = CreateTestBuildingsById(); // Create some test data.
var byImprovementId = CreateImprovementsById(byBuildingId); // Create the alternative lookup dictionaries.
var testTuples = CreateTestTuples();
ImprovementId improvementId = new ImprovementId(5010);
int count = 10000;
Stopwatch sw = Stopwatch.StartNew();
for (int i = 0; i < count; ++i)
byImprovementId[improvementId].Sum(result => result.Value.Data);
Console.WriteLine("Dictionary of dictionaries took " + sw.Elapsed);
sw.Restart();
for (int i = 0; i < count; ++i)
testTuples.Where(result => result.Key.Item2.Equals(improvementId)).Sum(item => item.Value.Data);
Console.WriteLine("Dictionary of tuples took " + sw.Elapsed);
}
static Dictionary<Tuple<BuildingId, ImprovementId>, Result> CreateTestTuples()
{
var result = new Dictionary<Tuple<BuildingId, ImprovementId>, Result>();
for (int buildingKey = 1000; buildingKey < 2000; ++buildingKey)
for (int improvementKey = 5000; improvementKey < 5030; ++improvementKey)
result.Add(
new Tuple<BuildingId, ImprovementId>(new BuildingId(buildingKey), new ImprovementId(improvementKey)),
new Result
{
Data = buildingKey + improvementKey/1000.0
});
return result;
}
static BuildingsById CreateTestBuildingsById()
{
var byBuildingId = new BuildingsById();
for (int buildingKey = 1000; buildingKey < 2000; ++buildingKey)
{
var improvements = new ImprovementResults();
for (int improvementKey = 5000; improvementKey < 5030; ++improvementKey)
{
improvements.Add
(
new ImprovementId(improvementKey),
new Result
{
Data = buildingKey + improvementKey/1000.0
}
);
}
byBuildingId.Add(new BuildingId(buildingKey), improvements);
}
return byBuildingId;
}
static ImprovementsById CreateImprovementsById(BuildingsById byBuildingId)
{
var byImprovementId = new ImprovementsById();
foreach (var improvements in byBuildingId)
{
foreach (var improvement in improvements.Value)
{
if (!byImprovementId.ContainsKey(improvement.Key))
byImprovementId[improvement.Key] = new BuildingResults();
byImprovementId[improvement.Key].Add(improvements.Key, improvement.Value);
}
}
return byImprovementId;
}
static void Main()
{
new Program().run();
}
}
}
他の答えはとても役に立ちましたが、ここで私自身の答えを受け入れるのはちょっと難しいですが、結局は別の方法で問題を解決しなければなりませんでした。うまくいけば、彼らの答えは似たような状況で他の誰かを助けることができます:) –