JSONオブジェクトのリストをDjangoモデルの不一致に変換する

Question

JSONオブジェクトにJSONオブジェクトの膨大な配列があります。いくつかのオブジェクトは他のものより多くのキーを持っていますが、それらは私が持っているモデルクラスのフィールドであるすべてのキーです。私は、オブジェクトが含まれていない任意のフィールドのnull値を作成して、そのオブジェクトからのデータを含むモデルインスタンスを作成するために、各JSONオブジェクトを繰り返し処理する最良の方法は何か？

minerals.json（スニペット）

[ 
    { 
     "name": "Abelsonite", 
     "image filename": "240px-Abelsonite_-_Green_River_Formation%2C_Uintah_County%2C_Utah%2C_USA.jpg", 
     "image caption": "Abelsonite from the Green River Formation, Uintah County, Utah, US", 
     "category": "Organic", 
     "formula": "C<sub>31</sub>H<sub>32</sub>N<sub>4</sub>Ni", 
     "strunz classification": "10.CA.20", 
     "crystal system": "Triclinic", 
     "unit cell": "a = 8.508 Å, b = 11.185 Åc=7.299 Å, α = 90.85°β = 114.1°, γ = 79.99°Z = 1", 
     "color": "Pink-purple, dark greyish purple, pale purplish red, reddish brown", 
     "crystal symmetry": "Space group: P1 or P1Point group: 1 or 1", 
     "cleavage": "Probable on {111}", 
     "mohs scale hardness": "2–3", 
     "luster": "Adamantine, sub-metallic", 
     "streak": "Pink", 
     "diaphaneity": "Semitransparent", 
     "optical properties": "Biaxial", 
     "group": "Organic Minerals" 
    }, 
    { 
     "name": "Abernathyite", 
     "image filename": "240px-Abernathyite%2C_Heinrichite-497484.jpg", 
     "image caption": "Pale yellow abernathyite crystals and green heinrichite crystals", 
     "category": "Arsenate", 
     "formula": "K(UO<sub>2</sub>)(AsO<sub>4</sub>)·<sub>3</sub>H<sub>2</sub>O", 
     "strunz classification": "08.EB.15", 
     "crystal system": "Tetragonal", 
     "unit cell": "a = 7.176Å, c = 18.126ÅZ = 4", 
     "color": "Yellow", 
     "crystal symmetry": "H-M group: 4/m 2/m 2/mSpace group: P4/ncc", 
     "cleavage": "Perfect on {001}", 
     "mohs scale hardness": "2.5–3", 
     "luster": "Sub-Vitreous, resinous, waxy, greasy", 
     "streak": "Pale yellow", 
     "diaphaneity": "Transparent", 
     "optical properties": "Uniaxial (-)", 
     "refractive index": "nω = 1.597 – 1.608nε = 1.570", 
     "group": "Arsenates" 
    }, 
    { 
     "name": "Abhurite", 
     "image filename": "240px-Abhurite_-_Shipwreck_Hydra%2C_South_coast_of_Norway.jpg", 
     "image caption": "Brownish tabular crystals of abhurite from Shipwreck \"Hydra\", South coast of Norway", 
     "category": "Halide", 
     "formula": "Sn<sub>21</sub>O<sub>6</sub>(OH)<sub>14</sub>Cl<sub>16</sub>", 
     "strunz classification": "03.DA.30", 
     "crystal symmetry": "Trigonal", 
     "group": "Halides" 
    }, 
] 

models.py

from django.db import models 

class Mineral(models.Model): 
    name = models.CharField(max_length=300, null=True, blank=True) 
    category = models.CharField(max_length=300, null=True, blank=True) 
    formula = models.CharField(max_length=300, null=True, blank=True) 
    crystal_system = models.CharField(max_length=300, null=True, blank=True) 
    unit_cell = models.CharField(max_length=300, null=True, blank=True) 
    color = models.CharField(max_length=300, null=True, blank=True) 
    cleavage = models.CharField(max_length=300, null=True, blank=True) 
    crystal_symmetry = models.CharField(max_length=300, null=True, blank=True) 
    mohs_scale = models.CharField(max_length=300, null=True, blank=True) 
    image_caption = models.CharField(max_length=300, null=True, blank=True) 
    image_filename = models.CharField(max_length=300, null=True, blank=True) 
    strunz_classification = models.CharField(max_length=300, null=True, blank=True) 

    def __str__(self): 
     return self.name 

Answer 1

hasattrとsetattrはあなたの問題を解決するために非常に便利です。 （docs）

def convert(jsonObject, model): 
    modelObject = model() 
    for key in jsonObject: 
     if hasattr(modelObject, key): 
      setattr(modelObject, key, jsonObject[key]) 

    return modelObject 

converted = list() 
for item in jsonArray: 
    mineral = convert(item, Mineral) 
    mineral.save() 
    converted.append(mineral)