私のコメントで述べたように、keybd_event()
は非推奨であり、SendInput()
で置き換えられました。しかし、PInvokeStackImbalance
例外を受け取っている理由は、関数宣言の最後の2つのパラメーターが間違っているためです。
ほとんどすべてDeclare...Lib
VB6以下の例があります。たとえば、Long
はVB.NETのLong
と同じではありません。 いつもに連絡してください。DllImport
attributeを使ってP/Invokeスニペットを探してください。 VB.NETバージョンが見つからない場合は、C#スニペットを探して、オンラインコンバータを使用して変換できます。
最後の2つのパラメータは、UInteger
とUIntPtr
である必要があります。私が言ったように
Public Declare Sub keybd_event Lib "user32" (ByVal bVk As Byte, ByVal bScan As Byte, ByVal dwFlags As UInteger, ByVal dwExtraInfo As UIntPtr)
しかし、DllImport
に固執することをお勧めします:あなたは/ Pのためpinvoke.netをチェックスニペットを呼び出すことができます
<DllImport("user32.dll")> _
Public Shared Sub keybd_event(bVk As Byte, bScan As Byte, dwFlags As UInteger, dwExtraInfo As UIntPtr)
End Function
。例えば
Imports System.Runtime.InteropServices
Public NotInheritable Class InputHelper
Private Sub New()
End Sub
#Region "Methods"
#Region "PressKey()"
''' <summary>
''' Virtually presses a key.
''' </summary>
''' <param name="Key">The key to press.</param>
''' <param name="HardwareKey">Whether or not to press the key using its hardware scan code.</param>
''' <remarks></remarks>
Public Shared Sub PressKey(ByVal Key As Keys, Optional ByVal HardwareKey As Boolean = False)
If HardwareKey = False Then
InputHelper.SetKeyState(Key, False)
InputHelper.SetKeyState(Key, True)
Else
InputHelper.SetHardwareKeyState(Key, False)
InputHelper.SetHardwareKeyState(Key, True)
End If
End Sub
#End Region
#Region "SetKeyState()"
''' <summary>
''' Virtually sends a key event.
''' </summary>
''' <param name="Key">The key of the event to send.</param>
''' <param name="KeyUp">Whether to push down or release the key.</param>
''' <remarks></remarks>
Public Shared Sub SetKeyState(ByVal Key As Keys, ByVal KeyUp As Boolean)
Key = ReplaceBadKeys(Key)
Dim KeyboardInput As New KEYBDINPUT With {
.wVk = Key,
.wScan = 0,
.time = 0,
.dwFlags = If(KeyUp, KEYEVENTF.KEYUP, 0),
.dwExtraInfo = IntPtr.Zero
}
Dim Union As New INPUTUNION With {.ki = KeyboardInput}
Dim Input As New INPUT With {
.type = INPUTTYPE.KEYBOARD,
.U = Union
}
SendInput(1, New INPUT() {Input}, Marshal.SizeOf(GetType(INPUT)))
End Sub
#End Region
#Region "SetHardwareKeyState()"
''' <summary>
''' Virtually sends a key event using the key's scan code.
''' </summary>
''' <param name="Key">The key of the event to send.</param>
''' <param name="KeyUp">Whether to push down or release the key.</param>
''' <remarks></remarks>
Public Shared Sub SetHardwareKeyState(ByVal Key As Keys, ByVal KeyUp As Boolean)
Key = ReplaceBadKeys(Key)
Dim KeyboardInput As New KEYBDINPUT With {
.wVk = 0,
.wScan = MapVirtualKeyEx(CUInt(Key), 0, GetKeyboardLayout(0)),
.time = 0,
.dwFlags = KEYEVENTF.SCANCODE Or If(KeyUp, KEYEVENTF.KEYUP, 0),
.dwExtraInfo = IntPtr.Zero
}
Dim Union As New INPUTUNION With {.ki = KeyboardInput}
Dim Input As New INPUT With {
.type = INPUTTYPE.KEYBOARD,
.U = Union
}
SendInput(1, New INPUT() {Input}, Marshal.SizeOf(GetType(INPUT)))
End Sub
#End Region
#Region "ReplaceBadKeys()"
''' <summary>
''' Replaces bad keys with their corresponding VK_* value.
''' </summary>
''' <remarks></remarks>
Private Shared Function ReplaceBadKeys(ByVal Key As Keys) As Keys
Dim ReturnValue As Keys = Key
If ReturnValue.HasFlag(Keys.Control) Then
ReturnValue = (ReturnValue And Not Keys.Control) Or Keys.ControlKey 'Replace Keys.Control with Keys.ControlKey.
End If
If ReturnValue.HasFlag(Keys.Shift) Then
ReturnValue = (ReturnValue And Not Keys.Shift) Or Keys.ShiftKey 'Replace Keys.Shift with Keys.ShiftKey.
End If
If ReturnValue.HasFlag(Keys.Alt) Then
ReturnValue = (ReturnValue And Not Keys.Alt) Or Keys.Menu 'Replace Keys.Alt with Keys.Menu.
End If
Return ReturnValue
End Function
#End Region
#End Region
#Region "WinAPI P/Invokes"
<DllImport("user32.dll", SetLastError:=True)>
Private Shared Function SendInput(ByVal nInputs As UInteger, <MarshalAs(UnmanagedType.LPArray)> ByVal pInputs() As INPUT, ByVal cbSize As Integer) As UInteger
End Function
<DllImport("user32.dll")> _
Private Shared Function MapVirtualKeyEx(uCode As UInteger, uMapType As UInteger, dwhkl As IntPtr) As UInteger
End Function
<DllImport("user32.dll")> _
Private Shared Function GetKeyboardLayout(idThread As UInteger) As IntPtr
End Function
#Region "Enumerations"
Private Enum INPUTTYPE As UInteger
MOUSE = 0
KEYBOARD = 1
HARDWARE = 2
End Enum
<Flags()> _
Private Enum KEYEVENTF As UInteger
EXTENDEDKEY = &H1
KEYUP = &H2
SCANCODE = &H8
UNICODE = &H4
End Enum
#End Region
#Region "Structures"
<StructLayout(LayoutKind.Explicit)> _
Private Structure INPUTUNION
<FieldOffset(0)> Public mi As MOUSEINPUT
<FieldOffset(0)> Public ki As KEYBDINPUT
<FieldOffset(0)> Public hi As HARDWAREINPUT
End Structure
Private Structure INPUT
Public type As Integer
Public U As INPUTUNION
End Structure
Private Structure MOUSEINPUT
Public dx As Integer
Public dy As Integer
Public mouseData As Integer
Public dwFlags As Integer
Public time As Integer
Public dwExtraInfo As IntPtr
End Structure
Private Structure KEYBDINPUT
Public wVk As UShort
Public wScan As Short
Public dwFlags As UInteger
Public time As Integer
Public dwExtraInfo As IntPtr
End Structure
Private Structure HARDWAREINPUT
Public uMsg As Integer
Public wParamL As Short
Public wParamH As Short
End Structure
#End Region
#End Region
End Class
:
は廃止、などですkeybd_event`
If condition = True Then
InputHelper.SetKeyState(Keys.Scroll, False) 'Key down.
Else
InputHelper.SetKeyState(Keys.Scroll, True) 'Key up.
End If
''宣言
は本日方法
SendInput()
推奨使用するには、私のInputHelper
クラスを利用することができます。 ..Lib'。キーボード/マウスイベントを送信する現在の方法は、[** 'SendInput()' **](https://msdn.microsoft.com/en-us/library/windows/desktop/ms646310(v = vs。 85).aspx)。私のキーボード入力ラッパーを参照してください[**この回答**](http://stackoverflow.com/questions/39809095/why-do-some-applications-not-accept-some-sendkeys-at-some-times/39811061 #39811061)。 –この例を見てください: https://msdn.microsoft.com/en-us/library/windows/desktop/ms646304(v=vs.85).aspx これはnumloc用ですが、あなたはKEYEVENTF_EXTENDEDKEYを使うべきです。 2番目:COnditionの後ろに何がありますか?それは次のようなものです: GetKeyboardState((LPBYTE)&keyState);例えば。現在のキー状態を取得するには? keybg_eventが代わりに – Kiko
になっているので、keybg_eventの代わりにSetInputを使用することができます。関数が正しく宣言されていれば、エラーはまったくないはずです。例外が処理されてもアプリケーションが中断されるため、[Thrown]チェックボックスにはデフォルトで何も選択されていないはずです。 –