PythonでConwayのゲームのルールが正しく動作しない

Question

Python 3.5.2でアドオンやリストのリストを使わずにConwayのゲームのリストベースの実装をしようとしています。私が今実行している問題は、各ポイントにある「隣人」の数が間違っていることです。私は以下のコードで私のprintステートメントを残しました。この例では、占有セルは「○」で示され、空でないセルは「。」で示される。

#Determine how many neighbors are surrounding the provided point  
def getNeighbors(board, index, columns): 
    neighbors = 0 
    try: 
     if(board[index + 1] == "o"): 
      neighbors += 1 
    except: 
     pass 
    try: 
     if(board[index - 1] == "o"): 
      neighbors += 1 
    except: 
     pass 
    try: 
     if(board[index + columns] == "o"): 
      neighbors += 1 
    except: 
     pass 
    try: 
     if(board[index - columns] == "o"): 
      neighbors += 1 
    except: 
     pass 
    try: 
     if(board[index - columns + 1] == "o"): 
      neighbors += 1 
    except: 
     pass 
    try: 
     if(board[index - columns - 1] == "o"): 
      neighbors += 1 
    except: 
     pass 
    try: 
     if(board[index + columns + 1] == "o"): 
      neighbors += 1 
    except: 
     pass 
    try: 
     if(board[index + columns - 1] == "o"): 
      neighbors += 1 
    except: 
     pass 
    return neighbors 

#Creates the game board in a list of lists 
def mkBoard(rows,columns): 
    board = ["."] * rows * columns 
    return board 

#Used to edit a point on the game board 
def editPoint(x,y,board,columns): 
    i = 0 
    i = x + ((y - 1) * columns) - 1 
    if(board[i] == "o"): 
     board[i] = "." 
    elif(board[i] == "."): 
     board[i] = "o" 
    return board 


#Simulates the next step in the game 
def nextTurn(board, columns): 
    prevBoard = board 
    i = 0 
    for index in prevBoard: 
     neighbors = 0 
     if(index == 'o'): 
      neighbors = getNeighbors(prevBoard, i, columns) 
      print(neighbors) 
      if(neighbors == 0 or neighbors == 1): 
       board[i] = "." 
      elif(neighbors >= 4): 
       board[i] = "." 
     elif(index == "."): 
      neighbors = getNeighbors(prevBoard, i, columns) 
      print(neighbors) 
      if(neighbors == 3): 
       board[i] = "o" 
     i += 1 
    return board 

#Prints the board to the screen to show the user what is happening 
def printBoard(board, columns): 
    counter = 0 
    for cell in board: 
     print(cell,end=" ") 
     counter += 1 
     if(counter == columns): 
      print('\n') 
      counter = 0 

print("======Conway's Game of Life======") 

#Take user input for number of rows and columns for the board and converts them into integers 
rows = input('Enter the number of rows:') 
rows = int(rows) 
columns = input('Enter the number of columns:') 
columns = int(columns) 

#Create the board and show it to the user 
board = mkBoard(rows,columns) 
printBoard(board,columns) 

choice = 0 

#If the user wants to add points to the board they can, otherwise they can begin the game 
while(1 != 3): 
    choice = input('Make a choice:\n1) Change a point\n2) Continue the game\n3) Quit\n') 
    if(choice =='1'): 
     x = input('Enter the x coordinate of the point to negate: ') 
     x = int(x) 
     y = input('Enter the y coordinate of the point to negate: ') 
     y = int(y) 
     board = editPoint(x,y,board, rows) 
     printBoard(board,columns) 
    elif(choice =='2'): 
     board = nextTurn(board, columns) 
     printBoard(board,columns) 
    elif(choice == '3'): 
     break 

Answer 1

私は2つのミスが見つかりました：あなたはcolumns代わりのrowsを渡す必要がありboard = editPoint(x,y,board, rows)で

1. を。

2. nextTurnには、prevBoard = boardはあなたの考えをしません。割り当てによってリストのコピーが作成されることはありません。どちらの変数も同じリストオブジェクトを参照しています。この例を参照してください：

   >>> a= [0,1]

   >>> b= a

   >>> a[0]= 9

   >>> b # output: [9, 1]

   prevBoard= board[:]を使用し、リストのコピーを作成します。