オーディオデータを含むバイト配列を渡して使用する正しい方法は何ですか？

Question

私は、オーディオを含むバイト配列を返すWepAPI C＃RESTサービスを作成しようとしています（この場合はAWS PollyのTTSサービスによって生成されます）。私はjavascriptクライアントで配列をどのように消費するかについて迷っています。次のように

マイWebAPIのサービスは、私は、オブジェクトを返すいた理由は、私は他のメタデータを添付したいということです...

var client = new AmazonPollyClient("secret", "secret", Amazon.RegionEndpoint.USWest2); 

var ssreq = new SynthesizeSpeechRequest(); 
ssreq.Text = "hello world"; 
ssreq.VoiceId = VoiceId.Nicole; 

var ttsresp = new TTSResp(); 

//// mp3 request 
ssreq.OutputFormat = OutputFormat.Mp3; 
var ssresp1 = client.SynthesizeSpeechAsync(ssreq).GetAwaiter().GetResult(); 
var ms = new MemoryStream(); 
ssresp1.AudioStream.CopyTo(ms); 
var bytes = ms.ToArray(); 
ttsresp.Audio = ms.ToArray(); 

return Ok(ttsresp); 

です。次のように

私のjavascriptのクライアントがあり、次のように...私のオーディオが返されたバイト

var context; // Audio context 
var buf;  // Audio buffer 

window.onload = function() { 
    context = new AudioContext(); 
} 

function getSound() { 

    $.ajax({ 
     url: 'api/test', 
     success: function (data) { 
      console.log('success', data); 

      var u8a = new Uint8Array(data.Audio.length); 
      u8a.set(new Uint8Array(data.Audio), 0); 

      //error here - DOMException: Unable to decode audio data 
      context.decodeAudioData(u8a.buffer, play); 
     }, 
     fail: function (err) { 
      console.log('fail', err); 
     } 
    }); 
} 

function play(audioBuffer) { 
    var source = context.createBufferSource(); 
    source.buffer = audioBuffer; 
    source.connect(context.destination); 
    source.start(0); 
} 

は...

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大歓迎任意のヘルプ...

Answer 1

あなたは、受信したデータはbase64エンコードです。実際にオーディオとして再生するには、まずバイト配列にbase64デコードする必要があります。 （私はこれを行い、質問に添付されたデータは保存後mpga/mp3ファイルです）。