tic tac toe app

Question

の結果を表示しています。私は現在、ゲームtic tac toeを作成するプログラムを作成しています。アプリは現在、2人のプレイヤーが行と列の番号を交互に入れてプレイしています。私がこのプログラムで抱えている主な問題は、1人が勝ったのか失ったのか、両方のプレーヤーが結んだのかの結果を表示することができないということです。もし誰かが私がこれをどのように解決できるかに関して何か提案があれば、それはすばらしいことになるでしょう。あなたの時間をもう一度ありがとう。

import java.util.Scanner; 

public class ticTacToeApp { 
    // 1. GAME CONSTANTS 
    static final int WIN = 1; 
    static final int LOSE = 0; 
    static final int TIE = 2; 
    static final int GAME_IN_PROGRESS = 3; 
    static final String PLAYER = "X"; 
    static final String OPPONENT = "O"; 
    static final String EMPTY = " "; 
    // 2. INPUT STREAM 
    static Scanner in; 

    public static void main(String[] args) { 
     // 3. BUILD THE TIC TAC TOE 3X3 BOARD OF STRINGS 
     String[][] board = { { EMPTY, EMPTY, EMPTY }, { EMPTY, EMPTY, EMPTY },{EMPTY, EMPTY, EMPTY } }; 
     // 4. INSTANTIATE THE SCANNER FOR INPUT 
     in = new Scanner(System.in); 
     // 5. GAME ENGINE 
     drawBoard(board); 
     int moveResult = GAME_IN_PROGRESS; // STATUS OF THE GAME AND AFTER A 
              // MOVE 
     while (moveResult == GAME_IN_PROGRESS) { 
      // PLAYER MOVES AND BOARD IS CHECKED FOR A RESULT 
      getMove(board, PLAYER, in); 
      drawBoard(board); 
      if (moveResult != GAME_IN_PROGRESS) 
       break; 

      // OPPONENT MOVES AND THE BOARD IS CHECKED FOR A RESULT 
      getMove(board, OPPONENT, in); 
      drawBoard(board); 
      moveResult = boardResults(board); 
     } 
     // 6. ONCE THE GAME HAS ENDED, DISPLAY IT IS AS A WIN, LOSE, OR TIE. 
     if (moveResult == WIN) 
      System.out.println("You win."); 
     else if (moveResult == LOSE) 
      System.out.println("You lost."); 
     else 
      System.out.println("You tied."); 
    } 

    public static int boardResults(String[][] board) { 
     // TASK 1: BUILD AN ARRAY CONTAINING ALL THE ROW, COLUMN, AND 
     // DIAGONAL STRING ARRANGEMENTS ON THE CURRENT 
     // TIC TAC TOE BOARD. 
     String[] waysToWin = new String[8]; 
     int i = 0; // INDEX TO wayToWin 
     for (int r = 0; r < 3; r++) { 
      String str = " ", stc = " "; 
      for (int c = 0; c < 3; c++) { 
       str += board[r][c]; 
       stc += board[c][r]; 
      } 
      waysToWin[i++] = str; 
      waysToWin[i++] = stc; 

      // ADD 2 DIAGONALS 
      waysToWin[i++] = board[0][0] + board[1][1] + board[2][2]; 
      waysToWin[i++] = board[0][2] + board[1][1] + board[2][0]; 
      // TASK 2. CHECK IF ANY OF THESE ARRANGEMENTS CONTAIN A WINNING 
      // "XXX" OR 
      // "OOO" 
      // NOTE: AN "XXX" IS WIN AND AN "OOO" IS LOSE. 
      for (int p = 0; p < 8; p++) { 
       if (waysToWin[p].equals("XXX")) 
        return WIN; 
       if (waysToWin[p].equals("OOO")) 
        return LOSE; 
       // TASK 3. CHECK IF THE BOARD IS FULL (TIE) OR IF THE GAME IS 
       // STILL IN 
       // PROGRESS 
       if (board[0][0] == EMPTY || board[0][1] == EMPTY || board[0][2] == EMPTY || board[1][0] == EMPTY 
         || board[1][1] == EMPTY || board[1][2] == EMPTY || board[2][0] == EMPTY || board[2][1] == EMPTY 
         || board[2][2] == EMPTY) 
        return GAME_IN_PROGRESS; 

      } 
     } 
     return i; 

    } 

    public static void drawBoard(String[][] board) { 
     for (int row = 0; row < board.length; row++) { 
      System.out.println("___________"); 
      for (int col = 0; col < board[row].length; col++) { 
       System.out.print("|" + board[row][col] + " "); 
      } 
      System.out.println("| "); 
     } 
     System.out.println("___________"); 
    } 

    public static void getMove(String[][] board, String whoseMove, Scanner in) { 
     int[] xy = new int[2]; 
     for (;;) { 
      System.out.print("You are " + whoseMove + ". "); 
      System.out.println("Enter the row and column of your move: "); 
      xy[0] = in.nextInt(); 
      xy[1] = in.nextInt(); 
      if (board[xy[0]][xy[1]].equals(EMPTY)) 
       break; 
      System.out.println("You must choose an empty space."); 
     } 
     board[xy[0]][xy[1]] = whoseMove; 
    } 
} 

Answer 1

私はボードに1次元配列を使用して、ボードにインデックスを付ける入賞組み合わせの配列を作成します。勝ち組をループし、XとOを数えます。 3つある場合は、勝者を宣言します。

public class ticTacToeApp { 
    static final String X = "X"; 
    static final String O = "O"; 
    static final String N = " "; 

    public static void main(String[] args) { 
    String[] board = { X,X,O, 
     N,O,N, 
     O,N,N }; 

    // combinations to win: 
    int[][] wins = { {0,1,2}, {3,4,5}, {6,7,8}, {0,3,6}, {1,4,7}, {2,6,8}, {0,4,8}, {2,4,6} }; 

    // count x's and o's to win 
    int x=0, o=0; 

    // find the winner by indexing the board array from the combinations to win array 
    // In each combination to win, if all 3 are X's or O's, declare a winner 

    for(int i=0; i<8; i++) { 
     x=0; o=0; 
     for(int j=0;j<3;j++) { 
     if (board[wins[i][j]] == X) x++;   
     if (board[wins[i][j]] == O) o++;  
     } 
     if (o==3 || x==3) 
     System.out.println(((x==3) ? "X" : "O") + " wins"); 
    } 
    } 
}