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以下私は書いた基数58の変換のための私のプロジェクトのコードを持っています。 2つの小さな数字の残りの部分はうまくいきますが、例えば、1.03475761285374E + 33のように2つの大きな数字の残りの部分を取得しようとすると、0が返されます。倍を分割して余りを得る方法はありますか?倍精度を返す0
Function Base58Value(sInput As String) As String
'reverse the input
sInput = StrReverse(sInput)
'get the length of the input string
Dim inputLen As Long
inputLen = Len(sInput)
'set up an array for each character
Dim sCharacter() As Integer
ReDim sCharacter(inputLen)
'set up an array for step 2 - index times 8 to the 2nd power
Dim sStep2() As Double
ReDim sStep2(inputLen)
'set up an array or step 3
Dim sStep3() As Double
ReDim sStep3(inputLen)
Dim sFinalNumber As Double
For x = 1 To inputLen
curchar$ = Mid(sInput, x, 1)
sCharacter(x) = Asc(curchar)
sStep2(x) = 2^((x - 1) * 8)
sStep3(x) = sCharacter(x) * sStep2(x)
sFinalNumber = sFinalNumber + sStep3(x)
Next x
Dim sRemainder() As Integer
ReDim sRemainder(0)
Dim sValue As Double
sValue = sFinalNumber
Dim sNextValue As Double
Dim sIter As Long
sIter = 0
Do Until Fix(sValue) = 0
DoEvents
ReDim Preserve sRemainder(sIter + 1)
sRemainder(sIter) = sMod(Fix(sValue), 58)
sValue = Fix(sValue/58)
sIter = sIter + 1
Loop
Dim ConversionTable$
ConversionTable = "123456789ABCDEFGHJKLMNPQRSTUVWXYZabcdefghijkmnopqrstuvwxyz"
Dim addValues As String
addValues = ""
Dim xI As Integer
For xI = 0 To UBound(sRemainder) - 1
DoEvents
List1.AddItem (sRemainder(xI))
addValues = addValues + Mid(ConversionTable, sRemainder(xI) + 1, 1)
Next xI
Base58Value = StrReverse(addValues)
End Function
Public Function sMod(a, b)
Dim x As Variant
x = a/b
x = x - Fix(x)
x = x * b
sMod = x
End Function
両方の大きな数値の縮尺を、例えば1E20で除算し、その結果に同じ値を乗じて変更します。 –