SQLヘルプ - 結合から重複を返す

Question

私のSQLクエリが複数のテーブルに加わるため、複数の結果が表示されています。私はSELECT DISTINCTについて知っていますが、フィールドの1つ（ 'Account.Name'）はときどき異なるので、このレコードを新しい行として扱います。何か案は？ここに私のSQLがあります：

SELECT DISTINCT 
         d.ID, ISNULL(d.OnHold, 0) AS 'OnHold', d.OnHoldReason AS 'On Hold Reason', d.LegacyID AS 'Consignment#', d.IntConNo AS 'Consignment Ref', 
         CASE WHEN JobType = 'O' THEN 'Outward' ELSE 'Collection' END AS 'Job Type', d.TripDate AS 'Delivery Date', d.DeliveryTown AS 'Delivery Town', 
         d.DeliveryPostcode AS 'Delivery Postcode', d.VehicleReg AS 'Vehicle Reg', d.RequiredCollectionDate AS 'Req. Collection Date', 
         d.VehicleReg AS 'Vehicle Registration', CASE WHEN d .DeliveryStatus = 2 THEN 'OK' END AS 'Delivery Status', d.ItemsignedBy AS 'POD Signed By', 
         d.BaseRate AS 'Base Rate', d.FuelSurcharge AS 'Fuel Surcharge', d.AdditionalCharges AS 'Additional Charges', 
         d.BaseRate + d.FuelSurcharge + d.AdditionalCharges AS 'Value', CASE WHEN InvoiceNumber IS NULL THEN CONVERT(bit, 0) ELSE CONVERT(bit, 1) 
         END AS Tagged, CASE WHEN di.Total = di.Delivered THEN 'Recieved' ELSE 'Not Recieved' END AS 'Items', Account.Name 
FROM   Deliveries AS d LEFT OUTER JOIN 
          (SELECT  Consignment, COUNT(*) AS Total, COUNT(CASE WHEN Status = 2 THEN 1 END) AS Delivered 
          FROM   Items 
          GROUP BY Consignment) AS di ON d.ID = di.Consignment INNER JOIN 
         Account ON d.Customer = Account.InvoiceAccount 
WHERE  (d.InvoiceNumber IS NULL) AND (d.TripDate > 29/11/2010) 
ORDER BY 'Consignment#' 

Answer 1

最も簡単な解決策は、DISTINCTをGROUP BYに置き換えることです。 dowsideは、1つのaccountnameだけが返されるということです。

他のソリューションは、連結アカウント名

が

SELECT d.ID 
     , ISNULL(d.OnHold, 0) AS 'OnHold' 
     , d.OnHoldReason AS 'On Hold Reason' 
     , d.LegacyID AS 'Consignment#' 
     , d.IntConNo AS 'Consignment Ref' 
     , CASE WHEN JobType = 'O' THEN 'Outward' ELSE 'Collection' END AS 'Job Type' 
     , d.TripDate AS 'Delivery Date' 
     , d.DeliveryTown AS 'Delivery Town' 
     , d.DeliveryPostcode AS 'Delivery Postcode' 
     , d.VehicleReg AS 'Vehicle Reg' 
     , d.RequiredCollectionDate AS 'Req. Collection Date' 
     , d.VehicleReg AS 'Vehicle Registration' 
     , CASE WHEN d .DeliveryStatus = 2 THEN 'OK' END AS 'Delivery Status', d.ItemsignedBy AS 'POD Signed By' 
     , d.BaseRate AS 'Base Rate' 
     , d.FuelSurcharge AS 'Fuel Surcharge' 
     , d.AdditionalCharges AS 'Additional Charges' 
     , d.BaseRate + d.FuelSurcharge + d.AdditionalCharges AS 'Value' 
     , CASE WHEN InvoiceNumber IS NULL THEN CONVERT(bit, 0) ELSE CONVERT(bit, 1) END AS Tagged 
     , CASE WHEN di.Total = di.Delivered THEN 'Recieved' ELSE 'Not Recieved' END AS 'Items' 
     , MIN(Account.Name) 
FROM Deliveries AS d 
     LEFT OUTER JOIN (
      SELECT Consignment 
        , COUNT(*) AS Total 
        , COUNT(CASE WHEN Status = 2 THEN 1 END) AS Delivered 
      FROM Items 
      GROUP BY 
        Consignment 
     ) AS di ON d.ID = di.Consignment 
     INNER JOIN Account ON d.Customer = Account.InvoiceAccount 
WHERE (d.InvoiceNumber IS NULL) 
     AND (d.TripDate > 29/11/2010) 
GROUP BY 
     d.ID 
     , ISNULL(d.OnHold, 0) 
     , d.OnHoldReason 
     , d.LegacyID 
     , d.IntConNo 
     , CASE WHEN JobType = 'O' THEN 'Outward' ELSE 'Collection' END 
     , d.TripDate 
     , d.DeliveryTown 
     , d.DeliveryPostcode 
     , d.VehicleReg 
     , d.RequiredCollectionDate 
     , d.VehicleReg 
     , CASE WHEN d .DeliveryStatus = 2 THEN 'OK' END AS 'Delivery Status', d.ItemsignedBy 
     , d.BaseRate 
     , d.FuelSurcharge 
     , d.AdditionalCharges 
     , d.BaseRate + d.FuelSurcharge + d.AdditionalCharges 
     , CASE WHEN InvoiceNumber IS NULL THEN CONVERT(bit, 0) ELSE CONVERT(bit, 1) END 
     , CASE WHEN di.Total = di.Delivered THEN 'Recieved' ELSE 'Not Recieved' END 
ORDER BY 
     'Consignment#' 

によってのみ1名のグループを使用して

を返すために、サブ選択を使用して返す関数を

• を作成することができ