XとRの空間線データフレームに変換データフレーム、YX、Y coordintates

Question

IがRのデータフレームを有し、列の一方が形の線に沿った点の座標が含まれています

x,y x,y x,y x,y 

したがって全体データフレームが

id dist speed coord 
1 45 6  1.294832,54.610240 -1.294883,54.610080 -1.294262,54.6482757 
2 23 34 2.788732,34.787940 6.294883,24.567080 -5.564262,-45.7676757 

ように見える私は、空間線データ・フレームにこれを変換したいと思い、私は拳のステップから2つの列に座標を分離するであろうと仮定：

x, x, x, x 
y, y, y, y 

しかし、私はどのように進むのかは分かりません。それを私は何をして終わるしたいことは、各行のためのものであることを、あなたのデータフレームの列であると信じて、実際のファイルのdput

> finalsub <- final[final$rid <3,] 
> dput(finalsub) 
structure(list(rid = c(1, 2), start_id = c(1L, 1L), start_code = c("E02002536", 
"E02002536"), end_id = c(106L, 106L), end_code = c("E02006909", 
"E02006909"), strategy = c("fastest", "quietest"), distance = c(12655L, 
12909L), time_seconds = c(2921L, 3422L), calories = c(211L, 201L 
), document.id = c(1L, 1L), array.index = 1:2, start = c("Geranium Close", 
"Geranium Close"), finish = c("Hylton Road", "Hylton Road"), 
    startBearing = c(0, 0), startSpeed = c(0, 0), start_longitude = c(-1.294832, 
    -1.294832), start_latitude = c(54.610241, 54.610241), finish_longitude = c(-1.249478, 
    -1.249478), finish_latitude = c(54.680691, 54.680691), crow_fly_distance = c(8362, 
    8362), event = c("depart", "depart"), whence = c(1473171787, 
    1473171787), speed = c(20, 20), itinerary = c(419956, 419957 
    ), clientRouteId = c(0, 0), plan = c("fastest", "quietest" 
    ), note = c("", ""), length = c(12655, 12909), time = c(2921, 
    3422), busynance = c(42172, 17242), quietness = c(30, 75), 
    signalledJunctions = c(3, 4), signalledCrossings = c(2, 0 
    ), west = c(-1.300074, -1.294883), south = c(54.610006, 54.609851 
    ), east = c(-1.232447, -1.232447), north = c(54.683814, 54.683814 
    ), name = c("Geranium Close to Hylton Road", "Geranium Close to Hylton Road" 
    ), walk = c(0, 0), leaving = c("2016-09-06 15:23:07", "2016-09-06 15:23:07" 
    ), arriving = c("2016-09-06 16:11:48", "2016-09-06 16:20:09" 
    ), coordinates = c("-1.294832,54.610240 -1.294883,54.610080 -1.294262,54.610016 -1.294141,54.610006 -1.293710,54.610038 -1.293726,54.610142 -1.293742,54.610247 -1.293510,54.610262 -1.293368,54.610258 -1.292816,54.610195 -1.292489,54.610152 -1.292298,54.610667 -1.292205,54.610951 -1.292182,54.611063 -1.292183,54.611153 -1.292239,54.611341 -1.292305,54.611447 -1.292375,54.611534 -1.292494,54.611639 -1.292739,54.611830 -1.292909,54.611980 -1.293010,54.612107 -1.293111,54.612262 -1.293192,54.612423 -1.293235,54.612546 -1.293267,54.612684 -1.293279,54.612818 -1.293510,54.612813 -1.293732,54.612790 -1.294324,54.612691 -1.295086,54.612568 -1.295313,54.612539 -1.295379,54.612543 -1.295889,54.612645 -1.295945,54.612648 -1.296006,54.612642 -1.297154,54.612414 -1.297502,54.612895 -1.297733,54.612847 -1.297990,54.612796 -1.298292,54.612747 -1.298515,54.612727 -1.299088,54.612681 -1.299564,54.612669 -1.299798,54.612663 -1.300006,54.612660 -1.300057,54.612809 -1.300056,54.613335 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    "-1.294832,54.610240 -1.294883,54.610080 -1.294262,54.610016 -1.294141,54.610006 -1.293710,54.610038 -1.293726,54.610142 -1.293742,54.610247 -1.293510,54.610262 -1.293368,54.610258 -1.292816,54.610195 -1.292489,54.610152 -1.292298,54.610667 -1.292167,54.610651 -1.291371,54.610562 -1.291240,54.610556 -1.291107,54.610564 -1.290983,54.610581 -1.290467,54.610665 -1.290253,54.610690 -1.290017,54.610689 -1.289770,54.610665 -1.289500,54.610620 -1.289281,54.610570 -1.289124,54.610514 -1.288957,54.610440 -1.288611,54.610277 -1.288420,54.610222 -1.287445,54.610110 -1.287259,54.610664 -1.286758,54.610611 -1.285446,54.610462 -1.285308,54.610459 -1.283356,54.610475 -1.283159,54.610475 -1.283156,54.610324 -1.283153,54.610119 -1.282818,54.610118 -1.282560,54.610114 -1.282110,54.610131 -1.281962,54.610153 -1.281788,54.610200 -1.281639,54.610257 -1.281298,54.609964 -1.281196,54.609851 -1.280586,54.610008 -1.280272,54.610054 -1.279816,54.610091 -1.279480,54.610104 -1.279112,54.610121 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-1.234300,54.681119 -1.234362,54.681549 -1.234427,54.681771 -1.234560,54.682172 -1.234782,54.682824 -1.236530,54.682837 -1.236725,54.682829 -1.237133,54.682813 -1.238813,54.683143 -1.241021,54.683814 -1.241819,54.683771 -1.242854,54.683717 -1.242946,54.683718 -1.243082,54.683716 -1.244694,54.683772 -1.244658,54.683077 -1.245038,54.682805 -1.245047,54.681990 -1.245011,54.681238 -1.245220,54.680975 -1.247056,54.680601 -1.248019,54.680404 -1.249478,54.680691" 
    ), grammesCO2saved = c(2359, 2406), calories = c(211, 201 
    ), type = c("route", "route")), .Names = c("rid", "start_id", 
"start_code", "end_id", "end_code", "strategy", "distance", "time_seconds", 
"calories", "document.id", "array.index", "start", "finish", 
"startBearing", "startSpeed", "start_longitude", "start_latitude", 
"finish_longitude", "finish_latitude", "crow_fly_distance", "event", 
"whence", "speed", "itinerary", "clientRouteId", "plan", "note", 
"length", "time", "busynance", "quietness", "signalledJunctions", 
"signalledCrossings", "west", "south", "east", "north", "name", 
"walk", "leaving", "arriving", "coordinates", "grammesCO2saved", 
"calories", "type"), row.names = 1:2, class = "data.frame") 
> 

Answer 1

を要求する人のために

EDIT

x.coordおよびy.coord列のリスト（またはデータフレーム）。それを達成するために、我々はdplyrでtidyrからunnestとnestを使用することができます。

library(dplyr) 
library(tidyr) 
result <- finalsub %>% mutate(coordinates = strsplit(coordinates,split=" ",fixed=TRUE)) %>% 
         unnest(coordinates) %>% 
         mutate(coordinates = strsplit(coordinates,split=",",fixed=TRUE), 
           x.coord = as.numeric(unlist(coordinates)[c(TRUE,FALSE)]), 
           y.coord = as.numeric(unlist(coordinates)[c(FALSE,TRUE)])) %>% 
         select(-coordinates) %>% 
         nest(x.coord,y.coord,.key=coordinates) 

注：

1. 最初mutateそれぞれを分離し、その結果x,yを調整する" "してcoordinates列に文字ベクトルを分割これらのうちlist。
2. unnestは、このリストを行に分けます。
3. 第2のmutateでは、最初にx,yの各座標を","で分割し、各座標をxとyに分けました。次に、これらを保持するために別々のx.coordとy.coordの列を作成します。ここでは数値への変換に注意してください。
4. 最後に、およびy.coordの列をcoordinatesという列の下のリストとして収集するために、nestを使用します。最初に元のcoordinates列を削除する必要があることに注意してください。

あなたdputデータ、印刷のみcoordinates列を使用して結果を：

print(result$coordinates) 
##[[1]] 
### A tibble: 284 x 2 
##  x.coord y.coord 
##  <dbl> <dbl> 
##1 -1.294832 54.61024 
##2 -1.294883 54.61008 
##3 -1.294262 54.61002 
##4 -1.294141 54.61001 
##5 -1.293710 54.61004 
##6 -1.293726 54.61014 
##7 -1.293742 54.61025 
##8 -1.293510 54.61026 
##9 -1.293368 54.61026 
##10 -1.292816 54.61019 
### ... with 274 more rows 
## 
##[[2]] 
### A tibble: 322 x 2 
##  x.coord y.coord 
##  <dbl> <dbl> 
##1 -1.294832 54.61024 
##2 -1.294883 54.61008 
##3 -1.294262 54.61002 
##4 -1.294141 54.61001 
##5 -1.293710 54.61004 
##6 -1.293726 54.61014 
##7 -1.293742 54.61025 
##8 -1.293510 54.61026 
##9 -1.293368 54.61026 
##10 -1.292816 54.61019 
### ... with 312 more rows 

Answer 2

df1 <- data.frame(id= c(1,2), dist =c(45,23), speed = c(6,24) ,do.call(rbind,strsplit(df$cord,split = " "))) 

library(reshape2) 

df1 <- melt(df1,id=c("id","dist","speed")) 

df2<- data.frame(do.call(rbind,strsplit(df1$value, split=","))) 
df1$value <- NULL 
df1 <- cbind(df1,df2) 
names(df1)[5:6] <- c("x","y") 
id dist speed variable   x   y 
1 1 45  6  X1 1.294832 54.610240 
2 2 23 24  X1 2.788732 34.787940 
3 1 45  6  X2 -1.294883 54.610080 
4 2 23 24  X2 6.294883 24.567080 
5 1 45  6  X3 -1.294262 54.6482757 
6 2 23 24  X3 -5.564262 -45.7676757