は1つがnewValにあり、他方が定義origValで、differnce

Question

私は2つの配列を持っているを見つけるために、下線付きのオブジェクトの2つの配列を比較

ORIG：

[ 
{"ListingId":1762276,"Rating":3,"ListPrice":7411828,"PropertyType":"Residential"}, 
{"ListingId":1826692,"Rating":3,"ListPrice":650000,"PropertyType":"Residential"}, 
{"ListingId":1833283,"Rating":4,"ListPrice":950000,"PropertyType":"Residential"}, 
{"ListingId":1832134,"Rating":3,"ListPrice":850000,"PropertyType":"Residential"}, 
{"ListingId":1829932,"Rating":4,"ListPrice":750000,"PropertyType":"Residential"}, 
{"ListingId":1827548,"Rating":5,"ListPrice":650000,"PropertyType":"Residential"} 
] 

新しい：

[ 
{"ListingId":1762276,"Rating":2,"ListPrice":7411828,"PropertyType":"Residential"}, 
{"ListingId":1826692,"Rating":3,"ListPrice":650000,"PropertyType":"Residential"}, 
{"ListingId":1833283,"Rating":4,"ListPrice":950000,"PropertyType":"Residential"}, 
{"ListingId":1832134,"Rating":3,"ListPrice":850000,"PropertyType":"Residential"}, 
{"ListingId":1829932,"Rating":4,"ListPrice":750000,"PropertyType":"Residential"}, 
{"ListingId":1827548,"Rating":5,"ListPrice":650000,"PropertyType":"Residential"} 
] 

新しい評価の中の1つを変更した場合、その変更をどのように検出して、変更されたオブジェクトを取得できますか？

私は重要ではないと考えていますが、一度に1つの変更しかありません。 FYI

：これらの配列はAnjularjsのwatchcollection

$scope.$watchCollection('items', function (new, old) { 

}, true); 

から生産されているが順序が変更されない場合は、単純な反復処理はそれを行います スティーブン

Answer 1

はこれに見てみましょう：

var a = [ 
{"ListingId":1762276,"Rating":3,"ListPrice":7411828,"PropertyType":"Residential"}, 
{"ListingId":1826692,"Rating":3,"ListPrice":650000,"PropertyType":"Residential"}, 
{"ListingId":1833283,"Rating":4,"ListPrice":950000,"PropertyType":"Residential"}, 
{"ListingId":1832134,"Rating":3,"ListPrice":850000,"PropertyType":"Residential"}, 
{"ListingId":1829932,"Rating":4,"ListPrice":750000,"PropertyType":"Residential"}, 
{"ListingId":1827548,"Rating":5,"ListPrice":650000,"PropertyType":"Residential"} 
]; 

var b = [ 
{"ListingId":1762276,"Rating":2,"ListPrice":7411828,"PropertyType":"Residential"}, 
{"ListingId":1826692,"Rating":3,"ListPrice":650000,"PropertyType":"Residential"}, 
{"ListingId":1833283,"Rating":4,"ListPrice":950000,"PropertyType":"Residential"}, 
{"ListingId":1832134,"Rating":3,"ListPrice":850000,"PropertyType":"Residential"}, 
{"ListingId":1829932,"Rating":4,"ListPrice":750000,"PropertyType":"Residential"}, 
{"ListingId":1827548,"Rating":5,"ListPrice":650000,"PropertyType":"Residential"} 
] 

var difference = function(array){ 
    var rest = Array.prototype.concat.apply(Array.prototype, Array.prototype.slice.call(arguments, 1)); 

    var containsEquals = function(obj, target) { 
    if (obj == null) return false; 
    return _.any(obj, function(value) { 
     return _.isEqual(value, target); 
    }); 
    }; 

    return _.filter(array, function(value){ return ! containsEquals(rest, value); }); 
}; 

console.log(JSON.stringify(difference(b, a))); 
> [{"ListingId":1762276,"Rating":2,"ListPrice":7411828,"PropertyType":"Residential"}] 

コードアンダースコアから、元の関数differenceに基づいて、それはisEqualを使用して、オブジェクト間の深い比較を行います。およそ

Answer 2

、ありがとうございます。アンダースコアは、このタスクのためにfind methodを提供しています。

var changedObj = _.find(newVal, function(obj, index) { 
    return obj.Rating != oldVal[index].Rating; 
}); 

Answer 3

方法：

const current = [{name:'a'},{name:'b'},{name:'c'}] 
const update = [{name:'x'},{name:'a'},{name:'b'},{name:'f'}] 
const records = current.concat(update); 
const diff = {}; 
diff.in = [] 
diff.out = []; 
records.forEach(item => { 
    if(!current.find(cur => item.name == cur.name))diff.in.push(item) 
    if(!update.find(up => item.name == up.name))diff.out.push(item) 
})