T-SQL：列の値を行の値に移動

Question

ケース・ステートメント（または提案するもの）に複数の結果が生成され、それらの複数の結果が出力に反映されます。しかし、下の例を使用すると、私は望みの結果を得られません。前もって感謝します。現在

：

探し

ID Phase Total Hours Team1 Team2 Team3 
1 Test  50  25  10 15 
2 QA  60  20  20 20 
3 Impl  40  0  20 20 

：

ID Phase Total Hours Team Name Team Hour 
1 Test  50  Team 1  25 
1 Test  50  Team 2  10 
1 Test  50  Team 3  15 
2 QA  60  Team 1  20 
2 QA  60  Team 2  20 
2 QA  60  Team 3  20 
3 Impl  40  Team 2  20 
3 Impl  40  Team 3  20 



Select ID, Phase, Total Hours, 
case 
When Team1 is not null and Team1 is >0 then 'Team1' 
When Team2 is not null and Team2 is >0 then 'Team2' 
When Team3 is not null and Team3 is >0 then 'Team3' 
end as 'Team Name', 

case 
When Team1.Hrs is not null and Team1.Hrs is >0 then Team1.Hrs 
When Team2.Hrs is not null and Team2.Hrs is >0 then Team2.Hrs 
When Team3.Hrs is not null and Team3.Hrs is >0 then Team3.Hrs 
end as 'Team Hours' 

From DB.DBNAME 

Answer 1

醜い、しかし...

SELECT ID, Phase, [Total Hours], 'Team1' AS Team, Team1 AS [Team Hours] 
FROM DB.DBNAME 

UNION 

SELECT ID, Phase, [Total Hours], 'Team2' AS Team, Team2 AS [Team Hours] 
FROM DB.DBNAME 

UNION 

SELECT ID, Phase, [Total Hours], 'Team3' AS Team, Team3 AS [Team Hours] 
FROM DB.DBNAME 

どれでもあなたがあなたのクエリは次のように返す必要が理由、とcouldn」に定期的なクエリを行い、クライアント側のデータを再配置しないでください。

Answer 2

UNPIVOTを使用してください。例：

;WITH t AS(
SELECT * FROM (VALUES(1,'Test',50,25,10,15),(2,'QA',60,20,20,20),(3,'Impl',40,0,20,20) 
      )x(ID, Phase, [Total Hours], Team1, Team2, Team3) 
) 
SELECT ID,Phase, [Total Hours], [Team Name], [Team Hour] 
FROM t 
UNPIVOT 
    ([Team Hour] FOR [Team Name] IN (Team1, Team2, Team3)) AS unpvt 
WHERE [Team Hour] > 0