SQLクエリ、私はトラブルにこれをワークアウトを抱えているほとんどのプロパティ

Question

を持つ人々を表示します所有者：

ownerno | fname | lname | telno 
_________________________________ 
B6  | John | g  | 67869 
_________________________________ 
B5  | Tom | f  | 46876 
_________________________________ 
B4  | Sally | s  | 23456 
_________________________________ 
B3  | Ann | a  | 23786 

Propertyowned：

propertyno | ownerno 
_____________________ 
BH5  | B6 
_____________________ 
BG6  | B5 
_____________________ 
BJ7  | B6 
_____________________ 
BF5  | B5 
_____________________ 
BD4  | B4 

は、あなたが私を助けることを願って おかげ

Answer 1

これが何をすべき：

SELECT 
    count(p.propertyno) as numproperties, 
    o.fcname, 
    o.lname, o.telno 
FROM 
    property p, 
    owner o 
WHERE 
    o.ownerno = p.ownerno 
GROUP BY 
    o.ownerno 
ORDER BY 
    numproperties desc 
LIMIT 1 

Answer 2

SELECT 
    o.fname, 
    o.lname, 
    o.telno, 
    count(p.propertyno) as property_count 
FROM 
    owners o 
    INNER JOIN 
    Propertyowned p 
    ON p.ownerno = o.ownerno 
GROUP BY 
    o.fname, 
    o.lname, 
    o.telno 
ORDER BY 
    count(p.propertyno) DESC