文字列をPostScriptの配列に分割する方法

Question

文字列を文字列に分割する最も簡単な方法は何ですか？たとえば、スペース上で分割して単語の配列を作る。文字列のすべての文字の配列を作ることさえできます。

私が考えることのできる唯一の方法は、ループ内でsearchを使用することです。すべての言語にはこの目的のための機能があるので、私はPostScriptの機能が不足していると思います。

Answer 1

あなたはsearchオペレータで正しい軌道に乗っています。文字列の検索とマッチングを行うのが目的です。

search string seek search post match pre true (if found) 
     string false (if not found) 

     looks for the first occurrence of the string seek within string and 
     returns results of this search on the operand stack. The topmost 
     result is a boolean that indicates if the search succeeded. 

     If search finds a subsequence of string whose elements are equal 
     to the elements of seek, it splits string into three segments: 
     pre, the portion of string preceding the match; match, the portion 
     of string that matches seek; and post, the remainder of string. It 
     then pushes the string objects post, match, and pre on the operand 
     stack, followed by the boolean true. All three of these strings are 
     substrings sharing intervals of the value of the original string. 

     If search does not find a match, it pushes the original string 
     and the boolean false. 

     Example: 

      (abbc) (ab) search ==> (bc) (ab) () true 
      (abbc) (bb) search ==> (c) (bb) (a) true 
      (abbc) (bc) search ==>() (bc) (ab) true 
      (abbc) (B) search ==> (abbc) false 

Answer 2

%! 

%(string) (delimiter) split [(s)(t)(r)(i)(n)(g)] 
/split {    % str del 
    [ 3 1 roll  % [ str del 
    {     % [ ... str del 
     search {  % [ ... post match pre 
      3 1 roll % [ ... pre post match %ie. [ ... pre str' del 
     }{   % [ ... str 
      exit  % [ ... str %% break-from-loop 
     }ifelse 
    }loop    % [ ... 
    ]     % [ ... ] 
} def 

(string of words separated by spaces)()split == 
%-> [(string) (of) (words) (separated) (by) (spaces)] 

(string.of.words.separated.by.dots)(.)split == 
%-> [(string) (of) (words) (separated) (by) (dots)]