SQLiteを使用してWebサーバーからJSON値をデータベースに保存する

Question

私のアプリでは、JSONレスポンスからいくつかのデータを取得しました。私はそれらを表示することもできます。

 @Override 
     public void onResponse(JSONArray response) { 
      Log.d("Theo", response.toString()); 
      //I use i=1 to bypass the first JSON object which doesn't contain the object member. 
      //If i set i=0,then I will get an exception. 
      for(int i = 1;i<response.length();i++){ 


       try { 

        //Here I read the 4 objects. 
        JSONObject jsonObject = response.getJSONObject(i); 

         //I get the members array for JSON object 
         JSONArray teamMembersArray = jsonObject.getJSONArray("members"); 


         for(int j=0;j<teamMembersArray.length();j++) { 

          //The model class which contains the setters/getters 
          //in order to "deserialize" the JSON objects into string objects. 
          Model m = new Model(); 


          JSONObject teamObject = teamMembersArray.getJSONObject(j); 
          //I am searching if the teamLead object exists.If yes 
          //then set it to true by reading it! If not then read 
          //the next members! 
          if (teamObject.has("teamLead") && (!teamObject.isNull("teamLead"))) { 
           m.setTeamLead(teamObject.getBoolean("teamLead")); 
          }else { 
           //Default value 
           m.setTeamLead(false); 

          } 
          m.setId(teamObject.getInt("id")); 
          m.setProfileImageURL(teamObject.getString("profileImageURL")); 
          m.setFirstName(teamObject.getString("firstName")); 
          m.setLastName(teamObject.getString("lastName")); 
          m.setRole(teamObject.getString("role")); 

          //Finally I am adding the string objects into an ArrayList. 
          modelArrayList.add(m); 

          int id = Integer.parseInt(teamObject.getString("id")); 
          String fname = teamObject.getString("firstName"); 
          String lname = teamObject.getString("lastName"); 
          String role = teamObject.getString("role"); 
          String proImage = teamObject.getString("profileImageURL"); 
          saveToDB(id,fname,lname,role,proImage); 
         } 
       } catch (JSONException e) { 
        e.printStackTrace(); 
       } 

      } 

インターネットに接続していない場合にはsaveToDB方法は

private void saveToDB(int id,String firstName,String lastName,String role,String image){ 

    //myMovie.setContent(descriptionText.getText().toString()); 

    dba.addMembers(id,firstName,lastName,role,image); 
    dba.close(); 

} 

次のステップは、SQLiteのの助けを借りて、それらを格納することです。だから私は最初に私の応答からJSONから変換された文字列を取ります。

int id = Integer.parseInt(teamObject.getString("id")); 
         String fname = teamObject.getString("firstName"); 
         String lname = teamObject.getString("lastName"); 
         String role = teamObject.getString("role"); 
         String proImage = teamObject.getString("profileImageURL"); 
         saveToDB(id,fname,lname,role,proImage); 

次に、それらをDatabaseHandlerクラスのaddMembers（...）メソッドに渡します。

public class DatabaseHandler extends SQLiteOpenHelper { 
private final ArrayList<SQLiteModel> membersList = new ArrayList<>(); 
public DatabaseHandler(Context context) { 
    super(context, Constants.DATABASE_NAME, null, Constants.DATABASE_VERSION); 
} 

@Override 
public void onCreate(SQLiteDatabase db) { 
    String CREATE_TEST_TABLE = "CREATE TABLE " + Constants.TABLE_NAME + 
      "(" + Constants.MEMBER_ID + " INTEGER PRIMARY KEY, " + Constants.FIRST_NAME + 
      " TEXT, " + Constants.LAST_NAME + " TEXT, " + Constants.JOB_ROLE + " TEXT, " + 
      Constants.PROFILE_IMAGE + " TEXT);"; 
    db.execSQL(CREATE_TEST_TABLE); 
} 


@Override 
public void onUpgrade(SQLiteDatabase db, int oldVersion, int newVersion) { 
    db.execSQL("DROP TABLE IF EXISTS " + Constants.TABLE_NAME); 
} 
//add content to table 
public void addMembers(int id,String firstName,String lastName,String role,String image) { 
    SQLiteDatabase db = this.getWritableDatabase(); 

    ContentValues values = new ContentValues(); 
    values.put(Constants.MEMBER_ID,id); 
    values.put(Constants.FIRST_NAME, firstName); 
    values.put(Constants.LAST_NAME,lastName); 
    values.put(Constants.JOB_ROLE,role); 
    values.put(Constants.PROFILE_IMAGE,image); 





    db.insert(Constants.TABLE_NAME, null, values); 

    db.close(); 

    Log.v("DB","heeeey!data saved"); 
} 

//get all folders 
public ArrayList<SQLiteModel> getMembersDetails() { 
    //I am stuck in this part. Boolean variables are not recognized 
    //in SQLite. So I have to make the getTeamLead() method from 
    //Model class,to return an int. But this will mess up my 
    //my recycler view. 


    SQLiteDatabase db = this.getReadableDatabase(); 

    Cursor cursor = db.query(Constants.TABLE_NAME, new String[]{ 
      Constants.MEMBER_ID, Constants.FIRST_NAME,Constants.LAST_NAME,Constants.JOB_ROLE,Constants.PROFILE_IMAGE}, null, null, null, null, Constants.MEMBER_ID + " DESC"); 


    if (cursor.moveToFirst()) { 
     do { 

      SQLiteModel sqLiteModel = new SQLiteModel(); 
      sqLiteModel.setSqlId(Integer.parseInt(cursor.getString(cursor.getColumnIndex(Constants.MEMBER_ID)))); 

      sqLiteModel.setSqlFirstName(cursor.getString(cursor.getColumnIndex(Constants.FIRST_NAME))); 
      sqLiteModel.setSqlLastName(cursor.getString(cursor.getColumnIndex(Constants.LAST_NAME))); 
      sqLiteModel.setSqlRole(cursor.getString(cursor.getColumnIndex(Constants.JOB_ROLE))); 
      sqLiteModel.setSqlProfileImageURL(cursor.getString(cursor.getColumnIndex(Constants.PROFILE_IMAGE))); 


      membersList.add(sqLiteModel); 
     }while(cursor.moveToNext()); 


    } 
    return membersList; 
} 

} 

私のアプリを実行すると、このエントリはlogcat出力となります。

06-22 07:30:22.831 17732-17732/testing.theo.androidtestproject  
E/SQLiteDatabase: 
Error inserting lastName=Corke firstName=Hannah 
profileImageURL=http://developers.mub.lu/resources/profilePlaceholder.png 
id=24 role=Designer                   
android.database.sqlite.SQLiteConstraintException: UNIQUE constraint failed: 
testdb.id (code 1555) 

なぜこのようなことが起こりますか？

ありがとうございます。

Answer 1

db.insertWithOnConflict()機能を使用する必要があります。ドキュメントを確認してくださいhere