高度なMySQLのクエリ（ソートグループ化と）

Question

http://sqlfiddle.com/#!9/3a4d84/1/0

を見てください私は、この表に

CREATE TABLE IF NOT EXISTS `data` (
    `id` int(11) NOT NULL, 
    `mdate` char(10) DEFAULT NULL, 
    `customer_id` int(11) NOT NULL, 
    `category` varchar(64) NOT NULL, 
    `quantity` double NOT NULL, 
    `sales` double NOT NULL 
) ENGINE=InnoDB DEFAULT CHARSET=utf8; 

INSERT INTO `data` (`id`, `mdate`, `customer_id`, `category`, `quantity`, `sales`) VALUES 
(2, '2015-02-01', 10720, 'Category1', 84.35, 894.24), 
(3, '2015-01-02', 15570, 'Category1', 1000, 1325), 
(4, '2015-01-02', 15570, 'Category6', 1000, 1325), 
(5, '2015-01-05', 17090, 'Category1', 9600, 11671.76), 
(6, '2015-01-05', 10360, 'Category2', 12110, 3981.6), 
(7, '2015-01-05', 10360, 'Category1', 10150, 4828.95), 
(8, '2015-01-06', 16460, 'Category3', 24000, 19656), 
(9, '2015-01-05', 18260, 'Category3', 24000, 17688), 
(10, '2015-01-05', 18260, 'Category2', 25200, 8129.02), 
(11, '2015-01-05', 12570, 'Category1', 500, 6833.5), 
(12, '2015-01-05', 11360, 'Category1', 2000, 1000), 
(13, '2015-01-05', 11360, 'Category6', 23700, 8977.5), 
(14, '2015-01-05', 15740, 'Category2', 26320, 9738.4), 
(15, '2015-01-05', 10170, 'Category2', 24720, 9994.79), 
(16, '2015-01-05', 12220, 'Category1', 4000, 2120), 
(17, '2015-01-05', 13380, 'Category4', 24000, 44880), 
(18, '2015-01-08', 13420, 'Category1', 23959, 23479.82), 
(19, '2015-01-06', 10310, 'Category2', 24900, 13310.54), 
(20, '2015-01-06', 17090, 'Category1', 6100, 2440), 
(21, '2015-01-06', 17090, 'Category2', 2000, 1020), 
(22, '2015-01-06', 17090, 'Category3', 2980, 1281.4), 
(23, '2015-01-06', 17090, 'Category4', 2000, 1707.48), 
(24, '2015-01-06', 10170, 'Category2', 25560, 12141), 
(25, '2015-01-06', 13060, 'Category2', 24440, 9238.32), 
(26, '2015-01-06', 10450, 'Category1', 3000, 2571.07), 
(27, '2015-01-06', 11800, 'Category5', 9000, 163800), 
(28, '2015-01-06', 18260, 'Category2', 25560, 8245.14), 
(29, '2015-01-06', 10170, 'Category2', 25180, 11960.5), 
(30, '2015-01-07', 10280, 'Category3', 21980, 16441.04), 
(31, '2015-01-06', 19230, 'Category2', 17760, 9835.98), 
(32, '2015-01-06', 19470, 'Category1', 6005, 13211), 
(33, '2015-01-06', 18640, 'Category5', 1000, 18200), 
(34, '2015-01-07', 10170, 'Category2', 26060, 12378.5), 
(35, '2015-01-07', 18640, 'Category5', 1000, 18200), 
(36, '2015-01-07', 13880, 'Category5', 500, 2303.93), 
(37, '2015-01-07', 18260, 'Category2', 25360, 8180.63), 
(38, '2015-01-05', 17040, 'Category2', 25080, 10784.4), 
(39, '2015-01-02', 17040, 'Category2', 23340, 10036.2), 
(40, '2015-01-02', 17040, 'Category3', 25500, 10965), 
(41, '2015-01-02', 17040, 'Category7', 24960, 10732.8), 
(42, '2015-01-08', 10720, 'Category1', 25000, 22375), 
(43, '2015-01-07', 10680, 'Category1', 1000, 695), 
(44, '2015-01-08', 16460, 'Category3', 24000, 20136), 
(45, '2015-01-06', 10130, 'Category6', 500, 2950), 
(46, '2015-01-08', 13880, 'Category2', 24000, 41280), 
(47, '2015-01-07', 15180, 'Category3', 2000, 2500), 
(48, '2015-01-06', 11060, 'Category3', 22000, 18480), 
(49, '2015-01-06', 19450, 'Category6', 2000, 11400), 
(50, '2015-01-07', 18150, 'Category4', 19748, 34756.48), 
(51, '2015-01-06', 18690, 'Category1', 1000, 13128.98); 

を持っていると私はこのクエリ

SELECT 
    customer_id, 
    category, 
    sum(quantity) as quantity, 
    sum(sales) as sales 
FROM `data` 
GROUP BY customer_id, category 

を使用するときに私のような結果を得ますこの

customer_id  category quantity sales 
10130 Category6 500  2950 
10170 Category2 101520 46474.79 
10280 Category3 21980 16441.04 
10310 Category2 24900 13310.54 
10360 Category1 10150 4828.95 
... 

は、PHPで、私はあなたが一列に一人の顧客のためのすべてのカテゴリquanityと販売を見ることができます。この

 | Category1  | Category2  | Category3   
     | quantity | sales | quantity | sales | quantity | sales ... 
------+----------+-------+----------+-------+----------+-------------- 
10360 | 10150 | 4828 |   |  |   | 
10310 |   |  | 24900 | 13310 |   | 
1890 | 80150 | 9828 |   |  | 84822 | 2310 

のようなテーブルを構築します。 しかし、今は "分類1の数量"の後など、テーブルを並べ替えることができません。

カスタマーごとにこのフォーマット（「カテゴリ1数量」、 「カテゴリ1販売」、「カテゴリ2数量」、「カテゴリ2販売」...）を取得するmysqlクエリを作成したいと考えています。だから私は順序でテーブルをソートすることができます...

それは可能ですか？私はそれをどう実現するかについてはあまりよく分かりません。 Maybee私は このDistinct（）のすべてのカテゴリを見つけ、PHPと 多くのsubselects ...またはクエリを作成できますか？

ありがとうございました。よろしくベン

---

更新、オーケーは今、私はこの「恐怖」クエリ

SELECT 
    e.customer_id, 
    (SELECT SUM(s.quantity) FROM `data` as s WHERE s.category = 'Category1' AND s.customer_id = e.customer_id) as quantity1, 
    (SELECT SUM(s.sales) FROM `data` as s WHERE s.category = 'Category1' AND s.customer_id = e.customer_id) as sales1, 
    (SELECT SUM(s.quantity) FROM `data` as s WHERE s.category = 'Category2' AND s.customer_id = e.customer_id) as quantity2, 
    (SELECT SUM(s.sales) FROM `data` as s WHERE s.category = 'Category2' AND s.customer_id = e.customer_id) as sales2, 
    (SELECT SUM(s.quantity) FROM `data` as s WHERE s.category = 'Category3' AND s.customer_id = e.customer_id) as quantity3, 
    (SELECT SUM(s.sales) FROM `data` as s WHERE s.category = 'Category3' AND s.customer_id = e.customer_id) as sales3, 
    (SELECT SUM(s.quantity) FROM `data` as s WHERE s.category = 'Category4' AND s.customer_id = e.customer_id) as quantity4, 
    (SELECT SUM(s.sales) FROM `data` as s WHERE s.category = 'Category4' AND s.customer_id = e.customer_id) as sales4, 
    (SELECT SUM(s.quantity) FROM `data` as s WHERE s.category = 'Category5' AND s.customer_id = e.customer_id) as quantity5, 
    (SELECT SUM(s.sales) FROM `data` as s WHERE s.category = 'Category5' AND s.customer_id = e.customer_id) as sales5, 
    (SELECT SUM(s.quantity) FROM `data` as s WHERE s.category = 'Category6' AND s.customer_id = e.customer_id) as quantity6, 
    (SELECT SUM(s.sales) FROM `data` as s WHERE s.category = 'Category6' AND s.customer_id = e.customer_id) as sales6, 
    (SELECT SUM(s.quantity) FROM `data` as s WHERE s.category = 'Category7' AND s.customer_id = e.customer_id) as quantity7, 
    (SELECT SUM(s.sales) FROM `data` as s WHERE s.category = 'Category7' AND s.customer_id = e.customer_id) as sales7 
FROM `data` as e 
Group by e.customer_id 
Order by quantity1 

はこれを避けるために、それは可能ですか？ :)ありがとう

Answer 1

私が理解しているように、category行の値を列に変換するテーブルをピボットしようとしています。残念ながら、MySQLにはT-SQLのような機能はありません。しかし、それはよくある問題です。それについては十分に議論されていますhere。だから私はこのようなサブクエリの代わりにCASEを使ってあなたのクエリを書き直すだろう：

SELECT 
    e.customer_id, 
    (SUM(CASE WHEN e.category = 'Category1' THEN e.quantity END)) as quantity1, 
    (SUM(CASE WHEN e.category = 'Category1' THEN e.sales END)) as sales1, 
    (SUM(CASE WHEN e.category = 'Category2' THEN e.quantity END)) as quantity2, 
    (SUM(CASE WHEN e.category = 'Category2' THEN e.sales END)) as sales2, 
    (SUM(CASE WHEN e.category = 'Category3' THEN e.quantity END)) as quantity3, 
    (SUM(CASE WHEN e.category = 'Category3' THEN e.sales END)) as sales3, 
    (SUM(CASE WHEN e.category = 'Category4' THEN e.quantity END)) as quantity4, 
    (SUM(CASE WHEN e.category = 'Category4' THEN e.sales END)) as sales4 
    # and so on 
FROM `data` as e 
Group by e.customer_id 
Order by quantity1