0
UPDATEステートメントがFOREIGN KEY制約 "FK__STANDARDS__S_ID__38996AB5"と競合しました。競合はデータベース "SAMPLE_1"、テーブル "dbo.SCHOOL"、列 'S_ID'で発生しました。 ステートメントが終了しました。これは、PLS MEUPDATEステートメントがFOREIGN KEY制約と競合しました
SCHOOL.ASPX
<%@ Page Language="C#" AutoEventWireup="true" CodeBehind="SCHOOL_1.aspx.cs" Inherits="WebApplication1.SCHOOL_1" %>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head id="Head1" runat="server">
<title></title>
</head>
<body>
<form id="form1" runat="server">
<div>
<asp:Label ID="Label1" runat="server" Text="SCHOOL NAME"></asp:Label>
<asp:TextBox ID="TextBox1" runat="server"></asp:TextBox>
<br />
<br />
<br />
<br />
<asp:Label ID="Label2" runat="server" Text="NO_OF_STANDARDS"></asp:Label>
<asp:TextBox ID="TextBox2" runat="server"></asp:TextBox>
<br />
<br />
<asp:Button ID="Button1" runat="server" onclick="Button1_Click" Text="SUBMIT" />
<br />
<br />
<br />
<br />
<br />
<asp:GridView ID="GridView1" runat="server" Height="190px"
Width="266px"
DataSourceID="sql1">
</asp:GridView>
<asp:SqlDataSource ID="sql1" runat="server"
ConnectionString="<%$ ConnectionStrings:ApplicationServices_1 %>"
SelectCommand="SELECT S_ID,S_NAME,NO_OF_STANDARD FROM [SCHOOL]">
</asp:SqlDataSource>
<br />
<asp:Button ID="Button2" runat="server" onclick="Button2_Click" Text="Back" />
<br />
<br />
</div>
</form>
</body>
</html>
SCHOOL.ASPX.CS
using System;
using System.Collections.Generic;
using System.Linq;
using System.Web;
using System.Web.UI;
using System.Web.UI.WebControls;
using System.Data;
using System.Data.SqlClient;
namespace WebApplication1
{
public partial class SCHOOL_1 : System.Web.UI.Page
{
protected void Page_Load(object sender, EventArgs e)
{
}
protected void Button1_Click(object sender, EventArgs e)
{
SqlConnection con = new SqlConnection(@"Data Source=CSI60-PC\SQLEXPRESS;Initial Catalog=SAMPLE_1;Integrated Security=True");
SqlCommand cmd = new SqlCommand("insert into school values('" + TextBox1.Text + "' ,'" + TextBox2.Text + "')", con);
SqlDataAdapter da = new SqlDataAdapter();
da.SelectCommand = cmd;
DataSet ds = new DataSet();
da.Fill(ds, "school");
}
protected void Button2_Click(object sender, EventArgs e)
{
Response.Redirect("HOME_1.aspx");
}
}
}
STANDARDS.ASPX
<%@ Page Language="C#" AutoEventWireup="true" CodeBehind="STANDARDS_1.aspx.cs" Inherits="WebApplication1.STANDARDS_1" %>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head id="Head1" runat="server">
<title></title>
</head>
<body>
<form id="form1" runat="server">
<div>
<asp:Label ID="Label1" runat="server" Text="CLASS"></asp:Label>
<asp:TextBox ID="TextBox1" runat="server"></asp:TextBox>
<br />
<br />
<br />
SCHOOL NAME
<asp:DropDownList ID="DropDownList1" runat="server"
DataSourceID="SqlDataSource1" DataTextField="S_NAME" DataValueField="S_ID">
</asp:DropDownList>
<asp:SqlDataSource ID="SqlDataSource1" runat="server"
ConnectionString="<%$ ConnectionStrings:ApplicationServices_1 %>"
SelectCommand="SELECT [S_ID], [S_NAME] FROM [SCHOOL]">
</asp:SqlDataSource>
<br />
<br />
<asp:GridView ID="GridView1" runat="server" Height="214px" Width="255px" DataSourceID="sql2"
AutoGenerateColumns="false" AutoGenerateEditButton="true"
AllowSorting="True" AllowPaging="True" DataKeyNames="STD_ID" >
<Columns>
<asp:BoundField ReadOnly="True" HeaderText="std_id"
DataField="std_id" SortExpression="std_id"></asp:BoundField>
<asp:BoundField HeaderText="class" DataField="class"
SortExpression="class"></asp:BoundField>
<asp:TemplateField HeaderText="S_NAME" SortExpression="S_NAME">
<EditItemTemplate>
<asp:DropDownList ID="DropDownList2" runat="server" DataSourceID="Sql3" DataTextField="S_NAME" DataValueField="S_ID">
</asp:DropDownList>
</EditItemTemplate>
<ItemTemplate>
<asp:Label ID="Label1" runat="server" Text='<%# Bind("S_NAME") %>'></asp:Label>
</ItemTemplate>
</asp:TemplateField>
</Columns>
</asp:GridView>
<asp:SqlDataSource ID="sql2" runat="server"
ConnectionString="<%$ ConnectionStrings:ApplicationServices_1 %>"
SelectCommand="select STANDARDS.STD_ID,STANDARDS.CLASS,SCHOOL.S_NAME
from STANDARDS
left join SCHOOL
on STANDARDS.S_ID=SCHOOL.S_ID"
UpdateCommand="update [STANDARDS] set [CLASS][email protected],[S_ID][email protected]_ID where [STD_ID][email protected]_ID">
<UpdateParameters>
<asp:Parameter Type="Int16" Name="CLASS" />
<asp:Parameter Type="Int16" Name="STD_ID" />
</UpdateParameters>
</asp:SqlDataSource>
<br />
<br />
<br />
<br />
<br />
<br />
<asp:Button ID="Button1" runat="server" onclick="Button1_Click" Text="SUBMIT" />
</div>
<asp:SqlDataSource ID="Sql3" runat="server"
ConnectionString="<%$ ConnectionStrings:ApplicationServices_1 %>"
SelectCommand="SELECT DISTINCT [S_NAME] FROM [SCHOOL]">
</asp:SqlDataSource>
</form>
</body>
</html>
STANDARDS.ASPX.CS
using System;
using System.Collections.Generic;
using System.Linq;
using System.Web;
using System.Web.UI;
using System.Web.UI.WebControls;
using System.Data;
using System.Data.SqlClient;
namespace WebApplication1
{
public partial class STANDARDS_1 : System.Web.UI.Page
{
protected void Page_Load(object sender, EventArgs e)
{
}
protected void Button1_Click(object sender, EventArgs e)
{
SqlConnection con = new SqlConnection(@"Data Source=CSI60-PC\SQLEXPRESS;Initial Catalog=SAMPLE_1;Integrated Security=True");
SqlCommand cmd = new SqlCommand("insert into STANDARDS values('" + TextBox1.Text + "' ,'" + DropDownList1.SelectedValue + "')", con);
SqlDataAdapter da = new SqlDataAdapter();
da.SelectCommand = cmd;
DataSet ds = new DataSet();
da.Fill(ds, "STANDARDS");
}
}
}
** SQLのテーブル構造** SCHOOL表
*CREATE TABLE SCHOOL(
[S_ID] [int] IDENTITY (1000,1) NOT NULL PRIMARY KEY ,
[S_NAME] [varchar](255) NULL,
[NO_OF_STANDARD] [int] NULL,
)*
STANDARDS TABLE
*CREATE TABLE STANDARDS(
[STD_ID] [int] IDENTITY (100,1) NOT NULL PRIMARY KEY,
[CLASS] [int] NULL,
[S_ID] [int] NULL FOREIGN KEY REFERENCES SCHOOL(S_ID),
)*
ようこそスタックオーバーフロー！ [最小限で完全で検証可能なサンプルを作成する方法]（http://stackoverflow.com/help/mcve）をお読みください。 –
あなたの質問は何ですか？誤差は非常に明確である：新しいIAMは親切に私を助けてくださいので、唯一の助け を求めて、私のエラー を修正することができませんでしたIAMに動作するので、外部キーエラーが、無効な値 –
@Ricardo Pontual屋エラーで更新しようとすると、 明らかです。 ... –