MySQL：集計関数：結合変数によるグループ

Question

私はこれを持っていると思っていましたが、何か間違っているように見えます。

更新：エラーは、customerテーブルとorder_detailsテーブルの間の接続に関係していると思います。確かにそれがまだ何であるか分からないが、どんな洞察力も素晴らしいだろう！

エラーは表示されません。ただ表示されません。それは構文ですか？変なことが起こっていますか？それとも、私のテーブルの組織ですか？

SELECT customers.ship_state as 'State', 
     SUM(ROUND(products.product_cost * order_details.quantity_purchased, 2)) as 'Total Sales' 
FROM customers 
JOIN order_details on order_details.customer_id = customers.customer_id 
JOIN products on products.product_id = order_details.product_id 
GROUP BY customers.ship_state 
ORDER BY customers.ship_state ASC; 

THESEに問題が

ステートメントは、CREATE TABLE文を、次のとおりです。

CREATE TABLE customers 
(
customer_ID    int(4)    UNIQUE, 
credit_card_ID   int(10)    NOT NULL, 
cus_fname    varchar(35)   NOT NULL, 
cus_lname    varchar(35)   NOT NULL, 
company_name   varchar(35)   NOT NULL, 
company_phone   varchar(15)   NOT NULL, 
ship_street    varchar(50)   NOT NULL, 
ship_city    varchar(25)   NOT NULL, 
ship_state    varchar(2), 
ship_zip    int(10)    NOT NULL, 
PRIMARY KEY (customer_id), 
FOREIGN KEY (credit_card_ID) REFERENCES credit_cards (credit_card_ID) 
); 

CREATE TABLE products 
(
product_ID    int(10)    UNIQUE, 
product_name   varchar(30)   NOT NULL,   
quantity_stocked  int(5), 
product_cost   dec(8,2)   NOT NULL, 
PRIMARY KEY (product_ID) 
); 

CREATE TABLE order_details 
(
order_ID    int(10)    UNIQUE, 
customer_ID    int(10)    NOT NULL, 
product_ID    int(10)    NOT NULL, 
quantity_purchased  int(5), 
PRIMARY KEY (order_ID), 
FOREIGN KEY (order_ID)  REFERENCES orders (order_ID), 
FOREIGN KEY (customer_ID) REFERENCES customers (customer_ID), 
FOREIGN KEY (product_ID) REFERENCES products (product_ID) 
); 

は、これらは、INSERTのステートメントです：

INSERT INTO customers VALUES 
(100,1,'Sarah','Jones','Sports Authority','6197254829','1324 River Road','Cincinnati','OH',45225), 
(101,2,'Desmond','Lowell','Sport Chalet','7023468547','3467 W Shaw Ave #103','Fresno','CA',93711), 
(102,3,'Mark','Jefferson','24 HR Fitness','8005557000','3433 E Widget Ave','Palo Alto','CA',92711), 
(103,4,'Jaime','Evans','Crash Athlete','2125554800','828 S Broadway','Tarrytown','NY',10591); 

INSERT INTO products VALUES 
(452,'Nike SS Pro Top',418, 22.99), 
(861,'Nike LunarGlide 7',1082, 74.99), 
(453,'Nike LS Pro Top',654, 64.99), 
(454,'Nike SS Pro Top',720, 64.99), 
(451,'Nike Pro Tank',480, 45.99), 
(485,'Nike 5k Run Short',1402, 24.99), 
(582,'Nike Fit Capri',750, 29.99), 
(591,'Nike Be Fast Tight',1948, 39.99), 
(847,'Nike Legend Tee',120, 34.99), 
(277,'Nike Miller v-neck',1920, 44.99), 
(135,'Adidas Soccer Pant',630, 34.99), 
(456,'Adidas SS Breathe Top',754, 19.99), 
(457,'Adidas Pro Cleat',626, 44.99), 
(214,'Adidas Slide',902, 19.99), 
(054,'Underarmor SL Top',854,54.99), 
(059,'Undersarmor LS High Neck',1021,54.99), 
(574,'Underarmor TR Short',746,24.99), 
(421,'Underarmor TR Balance Shoe',858,84.99); 

INSERT INTO order_details VALUE 
(213,1,452,218), 
(214,2,452,200), 
(215,3,861,300), 
(216,4,861,260), 
(217,1,456,600), 
(218,2,054,430), 
(219,3,421,430), 
(220,4,421,428), 
(221,1,214,500), 
(222,3,582,450), 
(223,2,451,480), 
(224,4,861,300), 
(225,3,591,800), 
(226,2,277,400), 
(227,1,591,800), 
(228,4,054,300), 
(229,2,059,500), 
(230,3,059,521), 
(231,1,574,200), 
(232,2,574,200), 
(233,4,574,200), 
(234,1,135,420), 
(235,2,277,400), 
(236,2,277,400); 

Answer 1

私はあなたのテーブルや外観をコピー顧客テーブルで！顧客IDは100に入っています。あなたの注文の詳細では、あなたの顧客IDは1になっています。

クエリが正しいです。 customersテーブルのcustomer IDがorder_detailsテーブルのcustomer IDと一致することを確認するだけです。

SELECT customers.ship_state as 'State', 
    SUM(ROUND(products.product_cost * order_details.quantity_purchased, 2)) as 'Total Sales' 
FROM customers 
JOIN order_details on order_details.customer_id = customers.credit_card_id 
JOIN products on products.product_id = order_details.product_id 
GROUP BY customers.ship_state 
ORDER BY customers.ship_state ASC;