出席要約レポート

Question

会社の方針のために、私が実際に使っている質問はできませんが、内訳と一般的な考えがあります。従業員が勤務しているかどうか、従業員がどこで働いているかを記録した出席登録があります。私はこれと、従業員が5シフトしたその日との間にこれを要約するようにしています。私が座っている問題は、特定の従業員が職場Aで2日間働いてから職場Bに移されたことです。職場Bで数日後、従業員は職場Aに戻ります。

私の結果私の試みは、従業員が1月1日から職場Aで働き始め、2月10日に仕事シフトが2回しかないことを示しています。私は働く場所にグループを持っており、開始日と終了日は最小と最大の選択です。

SELECT att.Employee, att.Workplace, dte.BeginDate, dte.EndDate, shf.WorkShift FROM 
(SELECT * FROM Attendance WHERE WorkDate BETWEEN '1-Jan' AND '30-Jan') att 
CROSS APPLY (SELECT COUNT(Shift) WorkShift FROM Attendance WHERE WorkDate BETWEEN '1-Jan' AND '30-Jan' AND Employee = att.Employee AND WorkPlace = att.WorkPlace AND Shift = 'Worked') shf 
CROSS APPLY (SELECT MAX(WorkDate) BeginDate, MIN(WorkDate) EndDate FROM Attendance WHERE WorkDate BETWEEN '1-Jan' AND '30-Jan' AND Employee = att.Employee AND WorkPlace = att.WorkPlace) dte 

ので、レコードは次のように表示されます。この従業員

（私は非常に悪いグリッドの申し訳ありませんが、私はそれはかなり見えるようにする方法がわからない、あなたはそれが良く見えるように編集することが歓迎以上のもの）

| Name | Workplace | beginDate | endDate | WorkShift | 
| Jane | WorkPlaceA | 1-Jan  | 2-Jan | 2   | 
| Jane | WorkPlaceB | 3-Jan  | 8-Jan | 5   | 
| Jane | WorkPlaceA | 9-Jan  | 10-Jan | 2   | 

出欠表には、私はあなたがCTEのを使ってこれを実現することができると信じて、この

| Name | Workplace | Date | Shift | 
| Jane | WorkplaceA | 1-Jan | Worked | 
| Jane | WorkplaceA | 2-Jan | Worked | 
| Jane | WorkplaceB | 3-Jan | Worked | 
| Jane | WorkplaceB | 4-Jan | Worked | 
| Jane | WorkplaceB | 5-Jan | Worked | 
| Jane | WorkplaceA | 6-Jan | Absent | 
| Jane | WorkplaceA | 7-Jan | Absent | 
| Jane | WorkplaceA | 8-Jan | Worked | 
| Jane | WorkplaceB | 9-Jan | Worked | 
| Jane | WorkplaceB | 10-Jan | Worked | 

Answer 1

ようになります。期待値を示すサンプルコードです。

;WITH CTE1 AS (
SELECT Employee, WorkPlace, TransactionDate, 
    ROW_NUMBER() OVER(PARTITION BY WorkPlace ORDER BY TransactionDate) AS WP, 
    ROW_NUMBER() OVER(ORDER BY TransactionDate) AS RN FROM Attendance WHERE Shift = 'Worked'), 
    CTE2 AS (SELECT Employee, WorkPlace, TransactionDate, WP, RN, WP-RN AS GB FROM CTE1), 
    CTE3 AS (SELECT Employee, WorkPlace, MIN(TransactionDate) AS TransactionDate, COUNT(1) AS Shifts FROM CTE2 GROUP BY Employee, WorkPlace, GB) 

SELECT Employee, WorkPlace, TransactionDate AS [Start Date], DATEADD(DAY,Shifts - 1,TransactionDate) AS [End Date], Shifts FROM CTE3 ORDER BY TransactionDate ASC 

Answer 2

あなたの出力が間違っていると思います。

私はあなたがテーブルを埋める方法が間違っていると思います。

私のクエリを確認し、それがさらにoptmizeすることができ、それが不在の日に、私は今、編集を行った

declare @t table(Name varchar(100),Workplace varchar(100), AttnDate date ,Shifts varchar(100)) 
insert into @t values 
('Jane','WorkplaceA',' 1-Jan-16','Worked') 
,('Jane','WorkplaceA',' 2-Jan-16','Worked') 
,('Jane','WorkplaceB',' 3-Jan-16','Worked') 
,('Jane','WorkplaceB',' 4-Jan-16','Worked') 
,('Jane','WorkplaceB',' 5-Jan-16','Worked') 
,('Jane','WorkplaceA',' 6-Jan-16','Absent') 
,('Jane','WorkplaceA',' 7-Jan-16','Absent') 
,('Jane','WorkplaceA',' 8-Jan-16','Worked') 
,('Jane','WorkplaceB',' 9-Jan-16','Worked') 
,('Jane','WorkplaceB','10-Jan-16','Worked') 

DECLARE @Name VARCHAR(100) = 'Jane' 
DECLARE @FromDate DATE = '01-Jan-16' 
DECLARE @ToDate DATE = '31-Jan-16'; 

WITH CTE 
AS (
    SELECT * 
     ,row_number() OVER (
      ORDER BY attndate 
      ) rn 
    FROM @t 
    WHERE NAME = @Name 
     AND (
      AttnDate BETWEEN @FromDate 
       AND @ToDate 
      ) 
    ) 
    ,CTE1 
AS (
    SELECT A.NAME 
     ,A.workplace 
     ,A.AttnDate 
     ,Shifts 
     ,rn 
     ,1 RN1 
    FROM cte A 
    WHERE rn = 1 

    UNION ALL 

    SELECT a.NAME 
     ,a.workplace 
     ,a.AttnDate 
     ,a.Shifts 
     ,CASE 
      WHEN a.workplace = b.workplace 
       THEN b.rn 
      ELSE b.rn + 1 
      END rn 
     ,RN1 + 1 
    FROM CTE A 
    INNER JOIN CTE1 b ON a.attndate > b.attndate 
    WHERE a.rn = RN1 + 1 
    ) 
    ,CTE2 
AS (
    SELECT NAME 
     ,Workplace 
     ,AttnDate beginDate 
     ,(
      SELECT max(AttnDate) 
      FROM CTE1 b 
      WHERE b.rn = a.rn 
      ) endDate 
     ,(
      SELECT count(*) 
      FROM CTE1 b 
      WHERE b.rn = a.rn 
       AND Shifts = 'Worked' 
      ) WorkShift 
     ,rn 
     ,ROW_NUMBER() OVER (
      PARTITION BY rn ORDER BY rn 
      ) rn3 
    FROM cte1 a 
    ) 
SELECT NAME 
    ,workplace 
    ,beginDate 
    ,endDate 
    ,WorkShift 
FROM cte2 
WHERE rn3 = 1