Python：ランダム変数をリフレッシュする方法

Question

私はこのコードを持っています。もし私がこれらの変数をすべて取り除くことができれば知りたいのですが、目的ごとに1つしか持たないでください。私のコードは、3つの異なるパスワード強度を持つパスワードジェネレータです。コードはこれがなくても動作しますが、設計上は小さくしたいと思っています。私はそれらの機能を作ろうとしましたが、うまくいきませんでした。私はおそらく明白な何かを欠いているでしょう：

import time 
import random 
import string 

ps = "" 
name = "" 
ans1 = "" 
list_s = ["!","£","~","%","*","(","}","#",";","@","/",":","-"] 
list_w = ["mouse","human","dog","tree","boom","thief","killer","dealer","feeler","man","woman","death"] 
list_w2 =["help","yelp","empire","squire","lier","fryer","kitchen","bed","matress", "criminal","drug"] 

rc1 = random.choice(string.ascii_lowercase) 
rc2 = random.choice(string.ascii_lowercase) 
rc3 = random.choice(string.ascii_lowercase) 
rc4 = random.choice(string.ascii_lowercase) 
rc5 = random.choice(string.ascii_uppercase) 
rc6 = random.choice(string.ascii_uppercase) 
rc7 = random.randrange(10) 
rc8 = random.randrange(10) 
rc9 = random.randrange(10) 
rc10 = random.choice(list_s) 
rc11 = random.choice(list_s) 
rc12 = random.choice(list_w) 
rc13 = random.choice(list_w2) 

while name == "": 
    name = str(input("Welcome to password64, before we begin enter your name:")) 
while ans1 == "": 
    ans1 = str(input("Have you used password64 before " + name + " ?")) 

ans1 = ans1[0].lower() 

if ans1 == "n": 
    print ("Thank you for trying password64 for the first time " + name + " !") 
    time.sleep(4) 
    print ("I will ask you the strength of the password you want, there will be three options: Strong, Medium or Weak") 
    time.sleep(6) 
    print ("A strong password is a mix of random numbers, letters and symbols") 
    time.sleep(3) 
print ("A medium password will be a couple of words with random numbers and symbols") 
    time.sleep(3) 
    print ("A weak password will be a couple of words with a number") 
elif ans1 == "y": 
    print ("Thank you for reusing password64 " + name + " !") 
    time.sleep(2) 
    print ("Let's get straight on with it then") 


while ps == "": 
    ps = str(input("Do you with to generate a strong, medium or weak password?")) 
    ps = ps[0].lower() 

if ps == "s": 
    a = [rc1 , rc2, rc3, rc4, rc5, rc6, rc7, rc8, rc9, rc10, rc11] 
elif ps == "m": 
    a = [rc12, rc13, rc7, rc8, rc10, rc11] 
elif ps == "w": 
    a = [rc12, rc13, rc7] 
else: 
    print ("You did not enter a valid password strength") 
    exit() 

random.shuffle(a,random.random) 

print ("Your password is generating....") 

for i in range(0,len(a)): 
    time.sleep(1) 
    print (a[i], end="") 
print ("") 
print ("Your password is ready to be used " + name + ". Thank you for using password64") 

Answer 1

なぜ機能にランドームを入れませんか？

f.e.

# -*- coding: cp1252 -*- 
import string 
import random 
import time 

random_type = ("lower","upper","digit","strange","wordlist1","wordlist2") 

list_s = ["!","£","~","%","*","(","}","#",";","@","/",":","-"] 
list_w = ["mouse","human","dog","tree","boom","thief","killer","dealer","feeler","man","woman","death"] 
list_w2 =["help","yelp","empire","squire","lier","fryer","kitchen","bed","matress", "criminal","drug"] 

def random_part(which_type): 
    if which_type == "lower": 
     return random.choice(string.ascii_lowercase) 
    elif which_type == "upper": 
     return random.choice(string.ascii_uppercase) 
    elif which_type == "digit": 
     return str(random.randrange(10)) 
    elif which_type == "digit": 
     return str(random.randrange(10)) 
    elif which_type == "strange": 
     return random.choice(list_s) 
    elif which_type == "wordlist1": 
     return random.choice(list_w) 
    else: 
     return random.choice(list_w2) 

def generate_pw(password_strength): 
    if password_strength == 'w': 
     l = ['wordlist1','wordlist2','digit'] 
    elif password_strength == 'm': 
     l = ['wordlist1','wordlist2','digit','digit','strange','strange'] 
    else: 
     l = ['wordlist1','wordlist2','digit','digit','strange','strange','lower','upper'] #whatever you want to 

    result = [] 
    for x in l: 
     result.append(random_part(x)) 
    return result 

print generate_pw('s') 

ところで、リストからChosen値を削除する場合は、単語リストを1つのみ使用できます。パスワードに2単語以上使用することができます。奇妙な文字でも同じことができるので、すべての文字は一度しか表示されません。 そして、あなたは結果をシャッフルできます。 それはあなたの決断です