私はこのようになりパイソンストリーム処理コードを有する

Question

が想定ジェネレータのシーケンスを並列化：

def F1(stream): 
    for x in stream: 
     yield f1(x) 

def F2(stream): 
    for x in stream: 
     yield f2(x) 

def F3(stream): 
    for x in stream: 
     yield f3(x) 

def F4(stream): 
    for x in stream: 
     yield f4(x) 


for x in F4(F3(F2(F1(range(1000000))))): 
    print(x) 

これは、UNIX（rangeコマンドを想定）にrange 1000000 | F1 | F2 | F3 | F4とほぼ同等であるが、中にUnixの各工程におけるパイプは平行して走る。

Pythonコードを簡単に並列化する方法はありますか？

Answer 1

パイプとblackmagicが必要ですが、Pythonには両方があります。

from multiprocessing import Process, Pipe 


def F1(stream): 
    for x in stream: 
     yield str(x)+'a' 

def F2(stream): 
    for x in stream: 
     yield x+'b' 

def F3(stream): 
    for x in stream: 
     yield x+'c' 

def F4(stream): 
    for x in stream: 
     yield x+'d' 



class PIPE_EOF: 
    pass 

class IterableConnection(object): 
    def __init__(self, pipe): 
     self.pipe = pipe 

    def __iter__(self): 
     return self 

    def __next__(self): 
     try: 
      ret = self.pipe.recv() 
      if ret == PIPE_EOF: 
       raise StopIteration 
      return ret 
     except EOFError: 
      raise StopIteration 

    def next(self): 
     return self.__next__() 


def parallel_generator_chain(*args, **kwargs): 
    if 'data' in kwargs: 
     data = kwargs['data'] 
    else: 
     raise RuntimeError('Missing "data" argument.') 

    def decorator(func, _input, _output): 
     def wrapper(*args, **kwargs): 
      for item in func(_input): 
       _output.send(item) 
      _output.send(PIPE_EOF) 
     return wrapper 

    for func in args: 
     in_end, out_end = Pipe(duplex = False) 
     in_end = IterableConnection(in_end) 
     func = decorator(func, data, out_end) 
     p = Process(target = func) 
     p.start() 
     data = in_end 

    for output in data: 
     yield output 



if 'xrange' not in globals(): 
    xrange = range 


if __name__ == '__main__': 
    for x in parallel_generator_chain(xrange, F1, F2, F3, F4, data=100000000): 
     print(x) 

#for x in F4(F3(F2(F1(range(1000000))))): 
# print(x)