変数を設定するためのPHP構文

コードをPHPに変換するJSスクリプトがありますが、PHPスクリプトでJSのこのコードと同じ構文を作成することに固執しています：変数を設定するためのPHP構文

var sdata = { 
      "13":{ 
       "22":["618","22","1","1","0","0","0"], 
       "21":["617","22","1","1","0","0","0"] 
      },    
      "14":{ 
       "22":["619","22","1","1","0","0","0"], 
       "20":["622","22","1","1","0","0","0"] 
      },  
      "15":{ 
       "20":["623","22","1","1","0","0","0"] 
    } 
};

アイデア？

出典

2012-05-07 Sir

あなたがPHPで同じオブジェクトを変換したい場合は、HTTPを使用：//www.phpを。 net/manual/ja/function.json-decode.phpそれ以外の場合は、mataの回答を参照してください。 –

ラッパーはオブジェクトであり、最初のレベルもオブジェクトであり、その子は配列です。まったく同じ構造を望んでいますか、あるいは単にデータレイヤーを同じにしたいのですか？ –

@tpaksu私は答えたようなマタを望んでいました:)変数の結果を解析していません - 私はスクリプト全体を書き直しています:) – Sir

$sdata = array(
      "13" => array(
       "22" => array("618","22","1","1","0","0","0"), 
       "21" => array("617","22","1","1","0","0","0") 
      ),    
      "14" => array(
       "22" => array("619","22","1","1","0","0","0"), 
       "20" => array("622","22","1","1","0","0","0") 
      ),  
      "15" => array(
       "20" => array("623","22","1","1","0","0","0") 
    ) 
);

出典

2012-05-07 21:04:03 mata

ああ、ありがとう！結局のところ非常に似ています！ – Sir