空リストを取得する - いいえアイデアなぜですか？

Question

私はこのコードを使用します

from __future__ import division 
from __future__ import print_function 

in_file = open("s:/Personal Folders/Andy/Python Projects/People Cancelled/Analyze Authorize Truncated.csv") 
text = in_file.readlines() 
in_file.close() 

header = text[0:1] 
text = text[1:] 

for index, line in enumerate(text): 
    text[index] = line.split(",") 

name = text 
dates = text 

for index, line in enumerate(name): 
    name[index] = line[3:5] 

for stuff, area in enumerate(dates): 
    dates[stuff] = area[7:8] 

print(name) 
print(dates) 

をそして、私はこの出力を得る：

[[], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], []] 
[[], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], []] 

任意のアイデアなぜですか？何らかの理由で、forループの2つの間に何らかの干渉があるようです。私がどちらかを行うと、私が望む結果が得られます。

ありがとうございます！この2行で

Answer 1

ルック：はないは名前とを指すように、日付のテキストのコピーを

name = text 
date = text 

これらのラインを作るのです。むしろ、名前と日付の両方を本質的にテキストの代替名にするように設定します。したがって、3番目のforループの後に（name[index] = line[3:5]のボディでは、textの各行は2つの項目になります（textとnameは同じリストです）。実際には、nameとdateの両方をtext最初は、意図した結果がnameと新しい、空のリストに等しいdateを作り、textに基づいてそれらの項目を追加することによって簡単に達成することができ