を選択し、この選択:SQLは、私が持っている
SELECT
*,
(SELECT some_value FROM other_table) as a1,
(SELECT some_value FROM other_table2) as a2
FROM some_table;
a2の値A1を使用して、このように彼らと仕事をする方法はありますか?
SELECT
*,
(SELECT some_value FROM other_table) as a1,
(SELECT some_value FROM other_table2) as a2,
a1+a2,
a1/a2
FROM some_table;
私はこれをしなければならない場合、それは良いではありませんので、これらのサブクエリはかなり大きいです:
SELECT
*,
(SELECT some_value FROM other_table) as a1,
(SELECT some_value FROM other_table2) as a2,
(SELECT some_value FROM other_table)+(SELECT some_value FROM other_table),
SELECT some_value FROM other_table)/(SELECT some_value FROM other_table2)
FROM some_table;