POSTリクエストからパーソナライズされた応答を取得する（Android）

Question

私はサーバーにPOSTリクエストを正しく行うアクティビティを持っています。私はPHPからアプリケーションに返信したいと思います。たとえば、データベースに何も投稿されていない場合は、次のようになります。

if(affected_rows=0){ 
. 
. 
$response = "No changes in the database" 
} 

どうすればいいですか？

私のAndroidのコードは以下の通りです：

public class SendPostRequest extends AsyncTask<String, Void, String> { 

protected void onPreExecute(){} 

protected String doInBackground(String... arg0) { 

    try { 

     URL url = new URL("https://www.wp.com/login_app.php"); // here is your URL path 

     JSONObject postDataParams = new JSONObject(); 
     postDataParams.put("user", user); 
     postDataParams.put("pass", pass); 
     postDataParams.put("texto", edit_text_value); 
     Log.e("params",postDataParams.toString()); 

     HttpURLConnection conn = (HttpURLConnection) url.openConnection(); 
     conn.setReadTimeout(15000 /* milliseconds */); 
     conn.setConnectTimeout(15000 /* milliseconds */); 
     conn.setRequestMethod("POST"); 
     conn.setDoInput(true); 
     conn.setDoOutput(true); 

     OutputStream os = conn.getOutputStream(); 
     BufferedWriter writer = new BufferedWriter(
     new OutputStreamWriter(os, "UTF-8")); 
     writer.write(getPostDataString(postDataParams)); 

     writer.flush(); 
     writer.close(); 
     os.close(); 

     int responseCode=conn.getResponseCode(); 

     if (responseCode == HttpsURLConnection.HTTP_OK) { 

      BufferedReader in=new BufferedReader(new 
      InputStreamReader(
      conn.getInputStream())); 

      StringBuffer sb = new StringBuffer(); 
      String line=""; 

      while((line = in.readLine()) != null) { 

       sb.append(line); 
       break; 
      } 

      in.close(); 
      return sb.toString(); 


     } 
     else { 
      return new String("false : "+responseCode); 
     } 
    } 
    catch(Exception e){ 
     return new String("Exception: " + e.getMessage()); 
    } 

} 

} 

public String getPostDataString(JSONObject params) throws Exception { 

    StringBuilder result = new StringBuilder(); 
    boolean first = true; 

    Iterator<String> itr = params.keys(); 

    while(itr.hasNext()){ 

     String key= itr.next(); 
     Object value = params.get(key); 

     if (first) 
      first = false; 
     else 
      result.append("&"); 

     result.append(URLEncoder.encode(key, "UTF-8")); 
     result.append("="); 
     result.append(URLEncoder.encode(value.toString(), "UTF-8")); 

    } 
    return result.toString(); 
} 

はお時間をありがとうございました。

Answer 1

使用あなたのSendPostRequest.classでこのコード

public class SendPostRequest extends AsyncTask<String, Void, String> { 
OnAsyncRequestComplete caller; 
List<NameValuePair> parameters = null; 

public SendPostRequest (List<NameValuePair> groupsParams){ 
    parameters = groupsParams 
} 

public interface OnAsyncRequestComplete { 
    public void asyncResponse(String response); 
} 

public String doInBackground(String... urls) { 
     String address = urls[0]; 
     return post(address); 
} 

private String post(String address) { 
    try { 
     HttpClient client = new DefaultHttpClient(); 
     HttpPost post = new HttpPost(address); 
     if (parameters != null) { 
      post.setEntity(new UrlEncodedFormEntity(parameters)); 
     } 
     HttpResponse response = client.execute(post); 
     String resultObj = stringifyResponse(response); 

     return resultObj; 
     } catch (ClientProtocolException e) { 
     // TODO Auto-generated catch block 
     } catch (IOException e) { 
     // TODO Auto-generated catch block 
     } 

    return null; 
} 

public void onPostExecute(String response) { 
caller.asyncResponse(response); 
} 


@SuppressWarnings("deprecation") 
private String stringifyResponse(HttpResponse response) { 
    BufferedReader in; 
    try { 
     in = new BufferedReader(new InputStreamReader(response.getEntity().getContent())); 
     StringBuffer sb = new StringBuffer(""); 
     String line = ""; 
     while ((line = in.readLine()) != null) { 
      sb.append(line); 
     } 
     in.close(); 

     return sb.toString(); 
    } catch (IllegalStateException e) { 

     e.printStackTrace(); 
    } catch (IOException e) { 

     e.printStackTrace(); 
    } 

    return null; 
} 

あなたのメインクラスからSendPostRequestクラスを呼び出すことができ、その後、あなたがインターフェイスを持つSendPostRequestクラスを実装する必要があり、

public class MainActivity extends Activity implements SendPostRequest.OnAsyncRequestComplete{ 

SendPostRequest service = new SendPostRequest(Your Parameter in Name Value Pair); 
service.execute(Your Url); 

@Override 
public void asyncResponse(String response) { 
    Log.e("Your Response",response);//Here is your response 
} 

}