zval *をオブジェクトに変換する方法は？

Question

は私が持っている：私はこれを解決するために

PHP_METHOD(Car, cls_ref) 
{ 
    Car *car; 
    //Car2 *obj11; 
    Car2 *car2; 
    zval* obj11; 
    zend_class_entry ce2 = zend_fetch_class("Car2", sizeof("Car2")-1, ZEND_FETCH_CLASS_DEFAULT TSRMLS_CC); 


    if (zend_parse_parameters(ZEND_NUM_ARGS() TSRMLS_CC, "O", &obj11,ce2) == FAILURE) { 
     RETURN_NULL(); 
    } 

    car_object *obj = (car_object *)zend_object_store_get_object(
     getThis() TSRMLS_CC); 
    /* car2_object *objj = (car2_object *)zend_object_store_get_object(
     getThis() TSRMLS_CC); 
     car2=(objj->car2); 
    */ 
    car = obj->car; 
    if (car != NULL) { 
     //cout<<"in car 2 ref"<<endl; 

     //car2->reference(s); 
    // (car->cls_ref((Car2&)car2)); 
    car->cls_ref((Car2&)obj11); 
    } 

} 

where void Car::cls_ref(Car2 &obj){...} 

。エラーが発生しました：

error: cannot convert ‘Car2*’ to ‘zval*’ in initialization /home/vehicles.cc:191: error: conversion from ‘zend_class_entry*’ to non-scalar type ‘zend_class_entry’ requested `(the errors are at the point where i intialize obj11 and at ce2=..)

Answer 1

zvalをobjectに変換するには、convert_to_object_ex（value）APIを使用します。ここで、valueは** zval型です。

-gaurav