SQL Serverを使用して変数にエイリアスを持つcaseステートメントを割り当てる方法

Question

下のコードで、CASEステートメントの結果を変数に代入しようとしています。私はそれが働いているが、私の問題は、私のCASEステートメントは、列名のエイリアスを持っているが、

また、その列にGRAND TOTALを取得するために変数をSUMにする必要があります。私はSQL Server 2014で作業しています。

私は解決策を見つけることができず、誰かが方向性/助けを提供できることを期待していました。前もって感謝します。ここで

が私のSQLコードです：あなたは値を代入しているときのような可変

SELECT DISTINCT a1.SCHYEAR, a1.LocationName as LOCATIONNAME, a1.GRADE, a1.[RACE/ETHNICITY], 
    @504Count=(
    CASE 
     WHEN a1.StudentPermID IN (SELECT DISTINCT t4.Permnum FROM #504 t4) THEN COUNT(a1.StudentPermID) 
    END)AS '504', 
    @Non504SPEDCount =(
    CASE 
     WHEN a1.STID NOT IN (SELECT DISTINCT t1.STID FROM #speds t1) THEN COUNT(a1.STID) 
     WHEN a1.StudentPermID NOT IN (SELECT DISTINCT t3.Permnum FROM #504 t3) THEN COUNT(a1.StudentPermID) 
    END) AS 'Non-504/Non-SPED', 
    @SPEDCount=(
    CASE 
     WHEN a1.STID IN (SELECT DISTINCT t2.STID FROM #speds t2) THEN COUNT(a1.STID) 
    END) AS 'SPED', 
    a1.STID, a1.StudentPermID as PERMNUM, COUNT('504'), COUNT('Non-SPED'), COUNT('SPED'), 
    SUM(@504Count + @Non504SPEDCount + @SPEDCount) AS 'Grand Total' 
    FROM #allStudents a1 
    GROUP BY a1.SCHYEAR, a1.LocationName, a1.GRADE, a1.[RACE/ETHNICITY], a1.STID, a1.StudentPermID 
    ORDER BY a1.SCHYEAR, a1.LocationName, a1.GRADE, a1.[RACE/ETHNICITY], a1.STID, a1.StudentPermID 

Answer 1

は、このコードを試してみてください、

SELECT DISTINCT a1.SCHYEAR, a1.LocationName as LOCATIONNAME, a1.GRADE, a1.[RACE/ETHNICITY], 
    @504Count=(
    CASE 
     WHEN a1.StudentPermID IN (SELECT DISTINCT t4.Permnum FROM #504 t4) THEN COUNT(a1.StudentPermID) 
    END), 
    @Non504SPEDCount =(
    CASE 
     WHEN a1.STID NOT IN (SELECT DISTINCT t1.STID FROM #speds t1) THEN COUNT(a1.STID) 
     WHEN a1.StudentPermID NOT IN (SELECT DISTINCT t3.Permnum FROM #504 t3) THEN COUNT(a1.StudentPermID) 
    END), 
    @SPEDCount=(
    CASE 
     WHEN a1.STID IN (SELECT DISTINCT t2.STID FROM #speds t2) THEN COUNT(a1.STID) 
    END), 
    a1.STID, a1.StudentPermID as PERMNUM, COUNT('504'), COUNT('Non-SPED'), COUNT('SPED'), 
    SUM(@504Count + @Non504SPEDCount + @SPEDCount) AS 'Grand Total' 
    FROM #allStudents a1 
    GROUP BY a1.SCHYEAR, a1.LocationName, a1.GRADE, a1.[RACE/ETHNICITY], a1.STID, a1.StudentPermID 
    ORDER BY a1.SCHYEAR, a1.LocationName, a1.GRADE, a1.[RACE/ETHNICITY], a1.STID, a1.StudentPermID 

Answer 2

に必須ではありません

SELECT DISTINCT 
    a1.SCHYEAR, a1.LocationName as LOCATIONNAME, a1.GRADE, 
    a1.[RACE/ETHNICITY], 
    @504Count = (CASE 
        WHEN a1.StudentPermID IN (SELECT DISTINCT t4.Permnum FROM #504 t4) 
         THEN COUNT(a1.StudentPermID) 
       END), 
    @Non504SPEDCount = (CASE 
          WHEN a1.STID NOT IN (SELECT DISTINCT t1.STID FROM #speds t1) 
          THEN COUNT(a1.STID) 
          WHEN a1.StudentPermID NOT IN (SELECT DISTINCT t3.Permnum FROM #504 t3) 
          THEN COUNT(a1.StudentPermID) 
         END), 
    @SPEDCount = (CASE 
        WHEN a1.STID IN (SELECT DISTINCT t2.STID FROM #speds t2) 
         THEN COUNT(a1.STID) 
        END), 
    a1.STID, a1.StudentPermID as PERMNUM, @504Count as '504', 
    @Non504SPEDCount as 'Non-504/Non-SPED', @SPEDCount as 'SPED', 
    SUM(@504Count + @Non504SPEDCount + @SPEDCount) AS 'Grand Total' 
FROM 
    #allStudents a1 
GROUP BY 
    a1.SCHYEAR, a1.LocationName, a1.GRADE, a1.[RACE/ETHNICITY], a1.STID, 
    a1.StudentPermID 
ORDER BY 
    a1.SCHYEAR, a1.LocationName, a1.GRADE, a1.[RACE/ETHNICITY], a1.STID, 
    a1.StudentPermID