2009-08-05 30 views
8

以下のコードスニペットを理解するのは難しいです。私はマキャニズムが示す機能を指すポインタを理解していますが、どこに混乱があるのか​​わかります。ポインタと配列のK&R Qsortの混乱

void qsort(void **v, int left, int right, int (*comp) (void *, void *)) 
{ 
    int i, last; 
    void swap(int **v, int i, int j); 

    if (left >= right) /* do nothing if array contains */ 
     return;   /* fewer than two elements */ 
    swap(v, left, (left + right)/2); /* move partition elem */ [1] 
    last = left;      /* to v[0] */ [2] 
    for (i = left + 1; i <= right; i++) /* partition */ [3] 
     if ((*comp) (v[i], v[left]) < 0) [4] 
      swap(v, ++last, i); [5] 
    swap(v, left, last);  /* restore partition elem */ [6] 
    qsort(v, left, last - 1); [7] 
    qsort(v, last + 1, right); [8] 

} 

誰かが私はこれのqsortを把握することはできませんので、読んでK & rはと言っながらただ、それはやっているものを私が読んエスキモーガイドを教えてくれ、特に示さライン、私にはこのルーチンを説明することができますqsortルーチンはごみであり、過度に複雑です。私はちょうどなぜこのように書かれているのか理解する必要があります。なぜなら、それは私には意味がないからです。

ありがとうございます。これを読んでいただきありがとうございます。

答えて

2

魔法の便利なGoogleキーワード:QuickSort

google:how quicksort worksがこの説明になります。http://www.angelfire.com/pq/jamesbarbetti/articles/sorting/001a_HowQuicksortWorks.htmの中でも。

本質的に、このコードでは、leftright境界の間のエレメントにquicksortのバリエーションを適用しています。

  1. スワップ1(left)最初と真ん中の要素:あなたが認識している回線については

    。それは "ピボット"になります。

  2. は、より大きい要素と小さい要素の境界を把握しています。ピボットが属する場所です。最初の1の後にすべての要素のための

  3. それはピボットより小さいだ場合、
  4. は、最初の大きな要素の前に移動します。

  5. ピボットを所定の位置に戻します。

  6. ピボットの前の要素にqsortを再帰的に適用します。 (より小さいもの)

  7. ピボットの後の要素に再帰的にqsortを適用します。 (大きなものは)

番号のリストにコードを自分でかけてみて、それがより理にかなっているかどうかを確認し、その後....

13

これは、コードの美しい作品です!

まず第一に、それはあなたがクイックソートの背後にある考え方を理解することが重要です。

1)番号のリストを取ります。

2)、1を選んX.

3)二つのリスト、Xより小さいすべての数字の1、そしてより大きなすべての番号のいずれかを行い、それを呼び出します。

4)Xより小さい数値をソートします.Xより大きい数値をソートします。

私たちが運が良ければXの値を選ぶと、Xより小さい数字のリストはXより大きい数字のリストと同じサイズになります。2 * N + 1 N個の数字の2つのリストを得る。毎回2つに分割することを望みますが、N個の数値をソートする必要があります。何回Nを2つに分けることができますか?それはLog(N)です。 したがって、N Log(N)回並べ替えます。これは素晴らしい!

コードがどのように機能するかについては、ここでは少しのスケッチと一緒に走り回りがあります。 、今E.

を指して、開始時に[DACBE]

、4右= D.を指し、0 =左:私たちはここに私たちの配列だ小さな配列:)

を選ぶだろうあなたのラベルで、コードを次

[1]スワップ(V、0,2)[DACBE] - > [CADBE]

我々は選択した値をスワップアウトしての開始時にそれを入れています配列。

[2]最後= 0

これは少し賢いです...私たちはあまり大きいとされたどの値を知っているので、カウンターを維持したい...あなたは、これが

の進行方法を見ていきます

[3](i = 1; I < = 4; iは++)用

リスト内のすべての残りの要素のために...

[4]((* COMP)(V [Iもし]、 'C')< 0)

iの値が 'C'よりも小さい場合...

[5]スワップ(v、++ last、i);

リストの先頭に置いてください!

のは3,4,5

ためのコードを実行させ、I = 1:

[CADBE]

IF( 'A' < 'C')

スワップ(」 A」、 'A')(AND INCREMENT LAST)

[CADBE] - !> [CADBE](変更なし)

最後= 1

I = 2:

[CADBE]

( 'D' < 'C')

が失敗した場合。進む。

I = 3:

[CADBE]

IF( 'B' < 'C')

スワップ( 'B'、 'D')および増分最後!

[CADBE] - > [CABDE](!lookitそれはソートです!)

最後= 2

I = 4:

[CABDE]

( 'E' の場合< 'C')

が失敗します。進む。

Ok、ace。 (C、B)スワップ( 'C'、 'B')スワップ( 'C'、 'B')スワップ [CABDE] - > [BACDE]

今、この魔法は...部分的にソートされています! BA < C < DE!

これで、サブリストを並べ替えることができます。

[7] - > [BA] - > [AB]

よう

[BACDE] - > [ABCDE]

[8] - > [DE] - > [DE ]

ので

[ABCDE] - > [ABCDE]

、我々は完了です。

3

K & Rのクイックは素晴らしいコーディングの例ですが、クイックソートの仕組みの素晴らしい例ではありません。プレワップの目的は直感的ではなく、アイデンティティ・スワップは非効率的で混乱します。私はこれを明確にするプログラムを書いています。コードコメントはその問題を説明します。

私はコンパイルしてテストしましたが、Visual Studioではこのプレーンなバニラコンソールアプリケーションに問題はありません。

 
/***************************** QUICK.CPP *************************************** 
Author: David McCracken 
Updated: 2009-08-14 

Purpose: This illustrates the operation of the quicksort in K&R "The C 
Programming Language" (second edition p. 120). Many programmers are frustrated 
when they attempt to understand quicksort in general from this version, which 
was clearly not intended as a tutorial on quicksort but on the use of pointers 
to functions. My program modifies the original to work only on ints in order to 
focus on the sorting process. It can print the global list and recursive 
sublist at each change to trace the sorting decision process. My program also 
clarifies two confusing aspects, both involving unexplained swapping, of the 
original by comparing its operation to that of two further modified versions. 

One confusing thing that the original does is to swap an item with itself. 
The code (modified for ints only) is: 

last = left; 
for(i = left+1 ; i <= right ; i++) 
    if( v[i] < v[ left ]) 
     swap(v[ ++last ], v[ i ]); 
Note that left and v[ left ] are loop-invariant. v[ left ] is the pivot. 

A superfluous swap is performed on all values less than the pivot without an 
earlier value greater than the pivot. For example, given sublist (after 
preswap) 9,8,5,7,4,6, initially i = left + 1, selecting 8. Since this is less 
than 9, last is incremented to point to the same element as i (selecting 8) and 
a superfluous swap is performed. At the next iteration, last selects 8 while i 
selects 5 and 5 is swapped with itself. This continues to the end of the 
sublist. The sorting function krQuick2 is identical to krQuick but tests ++last 
against i to avoid superfluous swapping. This certainly yields better 
performance for practically no cost but, more importantly, helps to clarify 
just what the code is trying to do, which is to find and swap a value that is 
larger than the pivot with one that occurs later and is smaller than the pivot. 

A second source of confusion is the purpose of the preswap, where the midpoint 
value is swapped with the left-most. Since this is done without regard to 
value, it cannot decrease entropy. In fact, it does exactly the opposite in the 
very important case of a sublist that is already sorted, which normally makes 
quicksort perform badly. This action deliberately unsorts a sorted list and 
essentially does nothing to an unsorted one. This simple and cheap action 
substantially improves average and worst case performance, as demonstrated by 
the third variation, quick3, which just removes the preswap from krQuick2. 
quick3 demonstrates that the preswap is not required; in fact that any value 
can be chosen from the list to serve as the pivot. Only in the most unsorted 
cases does quick3 exhibit slightly better performance than krQuick2 by virture 
of skipping the preswap. With increasing initial order, the performance of 
krQuick2 steadily improves over quick3. 

Some confusion may also come from the testing of v[i] against v[left]. left and 
v[ left ] are loop-invariant. An optimizing compiler should recognize this and 
hoist the value out of the loop, but this loop-invariance is not immediately 
obvious to someone studying this as an example of quicksort. During the swap 
loop, v[left] serves only to hold the pivot value. An automatic could just as 
easily hold the value and its purpose would be more clear. However, the code is 
an example of indirection. We don't know what the list items are but we can be 
sure that any one of them can fit into v[ left ] and that the swap function can 
put it there. Thus, the one preswap operation does three things; it randomizes 
a sorted sublist; it conveniently copies the pivot to a place where it won't be 
subject to swapping; and it fills the hole in the loop left by extracting the 
pivot. It does all of this without even knowing what the elements are and with 
a function that we already have. This amazing programming feat is well worth 
studying but not in the interest of understanding quicksort. 

         HOW TO USE THIS PROGRAM 
There are three general variables, the function, the data to be sorted, and what 
to display. 

The simplified K&R original function, krQuick, is function 0. Function 1, 
krQuick2, is krQuick with identity swaps removed. Function 2, quick3, is 
krQuick2 without preswap. 

The data to be sorted can be any one of five builtin lists or all of them or 
a space-delimited list of decimal ints entered on the command line. 

The displayed information affords a trace of the function's operation. In all 
cases, the list is displayed before and after sorting, and executing statistics 
are reported. If SHOW_NOTHING then nothing else is reported. If SHOW_GLOBAL, 
the changing full list is displayed at each invocation of the recursive sort 
function. If SHOW_LOCAL1, the sublist passed to the function is displayed before 
it is modified. If SHOW_LOCAL, the sublist is displayed after each swap. If 
SHOW_INDEX, the indices involved in swapping and the values at those indices 
are shown before the swap occurs.These selections correspond to the SHOW_ enum 
and are culmulative flags. 

By default, all three functions are applied in succession to all five builtin 
data lists, with SHOW_NOTHING. This is useful for comparing the performance of 
the functions. For example, it shows that on the unordered list 11 0 10 1 9 2 8 
3 7 4 6 5 quick3 uses 37 compares and 30 swaps while krQuick2 uses 38 compares 
and 44 swaps. However, on the ordered list 0 1 2 3 4 5 6 7 8 9 10 11 quick3 
uses 66 compares and 22 swaps while krQuick2 uses 25 compares and 28 swaps. 

Command line arguments alter the content but not the order of operation. In all 
cases, each selected function is applied to all selected data lists. 
Command arguments are case-insensitive: F function selector, D data selector, 
and S show what map. Each is followed without space by a single character. 
F0, F1, F2, FA select function 0, 1, or 2 only or all functions. 
D0, D1, D2, D3, D4, DA select builtin data list 0, 1, 2, 3, or 4 only or all. 
S0 (default) shows no extra information. 
S1 (GLOBAL) shows the full list (without "GLOBAL" legend) at each invocation. 
S2 (LOCAL1) shows the sublist before processing. 
S3 (GLOBAL+LOCAL1) 
S4 (LOCAL) shows the sublist after each swap. It also shows the sublist before 
    processing. 
S8 (INDEX) shows indices but these would never be shown without at least LOCAL, 
    which can't be combined with 8 in the single-digit argument. 
SA (All) 
Note that the Local legend includes a numeric suffix to identify where in the 
point in the code that is reporting. 
The most useful S formats are S1, S5, and SA (S0 is default). 

After any F and S arguments, any space-delimited list of numbers will be taken 
as the data list. Any D argument is ignored. For example: 
quick 20 21 15 12 40 0 
applies all three functions to the data, reporting only the unsorted and sorted 
full lists and operational statistics. 
quick f0 sa 20 21 15 12 40 0 
applies only function 0 krQuick to the data, reporting everything. 

*******************************************************************************/ 

#include <stdio.h> 
#include <stdlib.h> 
#include <string.h> 
#include <ctype.h> 

// ======================== DATA AND DECLARATIONS =============================== 
#define DIM(A) (sizeof A/sizeof A[0]) 
typedef unsigned int UINT; 

enum { SHOW_NOTHING, SHOW_GLOBAL = 1, SHOW_LOCAL1 = 2, SHOW_LOCAL = 4, 
     SHOW_INDEX = 8, SHOW_ALL = 0xFF }; 

int showWhat = SHOW_NOTHING; 

int list0[] = { 4,0,2,5,1,3 }; 
int list1[] = { 0,1,2,3,4,5,6,7,8,9,10,11 }; 
int list2[] = { 11,10,9,8,7,6,5,4,3,2,1,0 }; 
int list3[] = { 11,9,7,5,3,1,0,2,4,6,8,10 }; 
int list4[] = { 11,0,10,1,9,2,8,3,7,4,6,5 }; 
static struct { int *list; int cnt; } lists[] = 
{ 
    { list0, DIM(list0)}, 
    { list1, DIM(list1)}, 
    { list2, DIM(list2)}, 
    { list3, DIM(list3)}, 
    { list4, DIM(list4)}, 
}; 

int total[ 1000 ]; 
int totalCnt; 
int *userData = 0; 
int userDataLen = 0; 

int recursion; // Current recursion level. 
int calls;  // Number of times the sort function is called. 
int depth;  // Maximum recursion level. 
int swaps;  // Count of swaps. 
int compares; // Count of list item compares. 
int totCalls; 
int totDepth; 
int totCompares; 
int totSwaps; 

void (*sortFunc)(int *list, int left, int right); 

char dArg = 'A'; // command line argument selects 0,1,2,3,4, or A 
int dataList; // If dArg is numeric, this is its int value. 

//============================== FUNCTIONS ===================================== 

// ------------------------------ indent -------------------------------------- 
// Print two spaces for each level of recursion to indent subsequent print 
// output. 
// ............................................................................ 
void indent(void) 
{ 
    for(int indent = 1 ; indent < recursion ; indent++) 
     printf(" "); 
} 

// -------------------------------- show --------------------------------------- 
// Print the given int list according to the global control setting showWhat 
// and the given local identification. This may print nothing or the global 
// list or the local sublist. It may or may not print the legend GLOBAL or 
// LOCALx where x is the local ID, which tells at what point in the sort code 
// we are showing the sublist. 
// Returns: Nothing 
// Arguments: 
//- int *ia points to the int list. 
//- int cnt is the number of elements in the list. 
//- int local tells the local point in the sort routine if greater than 0. 0 
// indicates that this is global. In either case, format is controlled by 
// showWhat. If local is -1, the list is printed unconditionally and without 
// any legend. 
// Global: 
//- showWhat bitmapped control word 
//-- 0 (SHOW_NOTHING) This is the complete value, not a bit flag. 
//-- 1 (SHOW_GLOBAL) Print the list if local is 0. If any other bit is also 
// set, the GLOBAL legend is printed before the list. 
//-- 2 (SHOW_LOCAL1) Print the list only if local is 1. 
//-- 3 (SHOW_LOCAL) Print the list if local is 1 or greater. 
// 
// ...................... notes ............................................. 
//      SHOW_NOTHING 
// This exists because the callers don't test showWhat before calling. If we 
// only want to show the initial unsorted list and final sorted version then 
// SHOW_NOTHING blocks all print output from the sort function. The control 
// function calls show with local = -1 to print the list. 
// .......................................................................... 
void show(int *ia, int cnt, int local) 
{ 
    if(local >= 0) 
    { 
     switch(showWhat) 
     { 
     case SHOW_NOTHING: 
      return; 
     case SHOW_GLOBAL: // Only SHOW_GLOBAL 
      if(local > 0) 
       return;  // This is a local 
      break;   // Print list without legend. 
     default: // Some combination of SHOW_GLOBAL, SHOW_LOCAL1, SHOW_LOCAL 
      if(local == 0) // global 
      { 
       if((showWhat & SHOW_GLOBAL) == 0) 
        return; 
       printf("GLOBAL "); 
      } 
      else if(showWhat & SHOW_LOCAL || (showWhat & SHOW_LOCAL1 && local == 1)) 
      { 
       indent(); 
       printf("Local%d: ", local); 
      } 
      else 
       return; 
     } 
    } 
    for(int *end = ia + cnt ; ia < end ; ia++) 
     printf("%d ", *ia); 
    putchar('\n'); 
} 

// -------------------------------- swap --------------------------------------- 
void swap(int *p1, int *p2) 
{ 
    int temp = *p2; 
    *p2 = *p1; 
    *p1 = temp; 
    ++swaps; 
} 

// ------------------------------ krQuick -------------------------------------- 
// K&R's quick function modified to handle only integers and to use inline 
// numeric comparison instead of an indirect comp function. 
// ............................................................................. 
void krQuick(int *list, int left, int right) 
{ 
    int i, last; 

    ++calls; 
    if(recursion > depth) 
     depth = recursion; // At first call recursion = 0 and depth is 0, i.e. no recursion yet. 
    ++recursion; 
    show(total, totalCnt, 0); // GLOBAL 
    show(list + left, right - left + 1, 1); // LOCAL 
    if(left < right) 
    { 
     swap(list + left, list + (left + right)/2); 
     ++swaps; 
     show(list + left, right - left + 1, 2); 
     last = left; 
     for(i = left + 1 ; i <= right ; i++) 
     { 
      ++compares; 
      if(list[ i ] < list[ left ]) 
      { 
       if(showWhat & SHOW_INDEX) 
       { 
        indent(); 
        printf("i=%d @i=%d left=%d @left=%d last=%d\n", 
         i, list[i], left, list[ left ], last); 
       } 
       swap(list + ++last, list + i); 
       show(list + left, right - left + 1, 3); 
       ++swaps; 
      } 
     } 
     swap(list + left, list + last); 
     show(list + left, right - left + 1, 4); 
     ++swaps; 
     krQuick(list, left, last - 1); 
     krQuick(list, last + 1, right); 
    } 
    --recursion; 
} 

// ------------------------------- krQuick2 ------------------------------------ 
// K&R's quick function modified as in krQuick plus elimination of identity 
// swaps. 
// ............................................................................. 
void krQuick2(int *list, int left, int right) 
{ 
    int i, last; 

    ++calls; 
    if(recursion > depth) 
     depth = recursion; // At first call recursion = 0 and depth is 0, i.e. no recursion yet. 
    ++recursion; 
    show(total, totalCnt, 0); // GLOBAL 
    show(list + left, right - left + 1, 1); // LOCAL 
    if(left < right) 
    { 
     swap(list + left, list + (left + right)/2); 
     ++swaps; 
     show(list + left, right - left + 1, 2); 
     last = left; 
     for(i = left + 1 ; i <= right ; i++) 
     { 
      ++compares; 
      if(list[ i ] < list[ left ] && ++last != i) 
      { 
       if(showWhat & SHOW_INDEX) 
       { 
        indent(); 
        printf("i=%d @i=%d left=%d @left=%d last=%d\n", 
         i, list[i], left, list[ left ], last); 
       } 
       swap(list + last, list + i); 
       show(list + left, right - left + 1, 3); 
       ++swaps; 
      } 
     } 
     swap(list + left, list + last); 
     show(list + left, right - left + 1, 4); 
     ++swaps; 
     krQuick2(list, left, last - 1); 
     krQuick2(list, last + 1, right); 
    } 
    --recursion; 
} 

// ------------------------------------ quick3 --------------------------------- 
// krQuick2 modified to not do the preswap. In the K&R original, the purpose of 
// the preswap is to introduce randomness into a presorted sublist. The sorting 
// result is not changed by eliminating this but the performance degrades with 
// more compares and swaps in all cases between average and worst. Only near the 
// best case does eliminating the preswap improve performance. 
// ............................................................................ 
void quick3(int *list, int left, int right) 
{ 
    int i, last; 

    ++calls; 
    if(recursion > depth) 
     depth = recursion; // At first call recursion = 0 and depth is 0, i.e. no recursion yet. 
    ++recursion; 
    show(total, totalCnt, 0); // GLOBAL 
    show(list + left, right - left + 1, 1); // LOCAL 
    if(left < right) 
    { 
     last = left; 
     for(i = left + 1 ; i <= right ; i++) 
     { 
      ++compares; 
      if(list[ i ] < list[ left ] && ++last != i) 
      { 
       if(showWhat & SHOW_INDEX) 
       { 
        indent(); 
        printf("i=%d @i=%d left=%d @left=%d last=%d\n", 
         i, list[i], left, list[ left ], last); 
       } 
       swap(list + last, list + i); 
       show(list + left, right - left + 1, 3); 
       ++swaps; 
      } 
     } 
     swap(list + left, list + last); 
     show(list + left, right - left + 1, 4); 
     ++swaps; 
     quick3(list, left, last - 1); 
     quick3(list, last + 1, right); 
    } 
    --recursion; 
} 

static struct { void (*func)(int *list, int left, int right) ; char *name ; } sortFuncs[] = 
{ 
    { krQuick, (char*)"krQuick" }, 
    { krQuick2, (char*)"krQuick2 (no identity swaps)" }, 
    { quick3, (char*)"quick3 (no preswaps)" } 
}; 

// ------------------------------------ sortOne -------------------------------- 
// Set up performance counters, invoke the currently selected sort on the current 
// data list, and print the performance (for this one case of selected function 
// applied to selected data list). 
// ............................................................................. 
void sortOne(void) 
{ 
    recursion = 0; 
    calls = 0; 
    depth = 0; 
    swaps = 0; 
    compares = 0; 
    show(total, totalCnt, -1); 
    sortFunc(total, 0, totalCnt - 1); 
    show(total, totalCnt, -1); 
    printf("Calls = %d, depth = %d, compares = %d, swaps = %d\n", 
     calls, depth, compares, swaps); 
    printf("---------------------------------\n"); 
} 

// ---------------------------- sortOneSet ------------------------------------- 
// Purpose: Apply the currently selected sort function to one data list. 
void sortOneSet(int idx) 
{ 
    if(idx < 0) 
    { 
     totalCnt = userDataLen; 
     memcpy(total, userData, totalCnt * sizeof(int)); 
    } 
    else 
    { 
     totalCnt = lists[ idx ].cnt; 
     memcpy(total, lists[ idx ].list, totalCnt * sizeof(int)); 
    } 
    sortOne(); 
    totCalls += calls; 
    totDepth += depth; 
    totCompares += compares; 
    totSwaps += swaps; 
} 

// ------------------------- testOneFunc --------------------------------------- 
// Purpose: Apply the selected function to one or all data lists. 
// Returns: Nothing 
// Arguments: int sel is 0,1,or 2, selecting krQuick, krQuick2, or quick3. 
// Globals: char dArg is the data list selector command line argument. It is '0', 
// '1', '2', or 'A'. 'A' selects all data lists. Otherwise, int dataList is the 
// int value of dArg, which has already been translated for us by the command 
// line processor. 
// ............................................................................. 
void testOneFunc(int sel) 
{ 
    totCalls = 0; 
    totDepth = 0; 
    totCompares = 0; 
    totSwaps = 0; 
    sortFunc = sortFuncs[ sel ].func; 
    printf("====== %s ======\n", sortFuncs[ sel ].name); 

    if(userDataLen != 0) 
     sortOneSet(-1); 
    else if(dArg == 'A') 
    { 
     for(UINT idx = 0 ; idx < DIM(lists) ; idx++) 
      sortOneSet(idx); 
     printf("Total: calls = %d, depth = %d, compares = %d, swaps = %d\n", 
      totCalls, totDepth, totCompares, totSwaps); 
    } 
    else 
     sortOneSet(dataList); 
} 

// --------------------------------- main -------------------------------------- 
// Purpose: Process command line arguments, set up show (print output) and data 
// list selectors, and invoke testOneFunc either once for the selected function 
// or for each of the three functions. 
// ............................................................................. 
int main(int argc, char **argv) 
{ 
    char *cp; 
    char fArg = 'A'; // function selector 0,1,2,A 
    UINT idx; 

    showWhat = SHOW_NOTHING; 
    dArg = 'A'; 
    for(int cnt = 1 ; cnt < argc ; cnt++) 
    { 
     cp = argv[ cnt ]; 
     switch(toupper(*cp)) 
     { 
     case 'F': 
      fArg = toupper(cp[1]); 
      break; 
     case 'D': 
      dArg = toupper(cp[1]); 
      if(dArg != 'A') 
      { 
       dataList = dArg - '0'; 
       if(dataList < 0 || dataList >= (int)DIM(lists)) 
       { 
        printf("Error: bad data list selector %c\n", dArg); 
        return 1; 
       } 
      } 
      break; 
     case 'S': // show selector matches bit-mapped showWhat or N or A 
      ++cp; 
      if(*cp != 0 || toupper(*cp) != 'N') 
      { 
       if(toupper(*cp) == 'A') 
        showWhat = SHOW_ALL; 
       else 
        showWhat = atoi(cp); 
      } 
      break; 
     default: 
      if(!isdigit(*cp)) 
      { 
       printf("Error: There is no option %c\n", *cp); 
       return 1; 
      } 
      for(idx = 0 ; idx < DIM(total) && cnt < argc ; idx++, cnt++) 
       total[ idx ] = atoi(argv[ cnt ]); 
      userData = (int*)malloc(sizeof(int) * idx); 
      if(userData == 0) 
      { 
       printf("Error: Unable to allocate memory for data list\n"); 
       return 2; 
      } 
      memcpy(userData, total, sizeof(int) * idx); 
      userDataLen = idx; 
     } 
    } 
    switch(fArg) 
    { 
    case 'A': 
     for(UINT sfi = 0 ; sfi < DIM(sortFuncs) ; sfi++) 
      testOneFunc(sfi); 
     break; 
    case '0': 
    case '1': 
    case '2': 
     testOneFunc(fArg - '0'); 
     break; 
    default: 
     printf("Error: bad function selector %c\n", fArg); 
     return 1; 
    } 
    return 0; 
} 
 
Results of quick 
This uses all defaults, which is most useful for comparing the performance 
of the three different functions. 

====== krQuick ====== 
4 0 2 5 1 3 
0 1 2 3 4 5 
Calls = 7, depth = 2, compares = 8, swaps = 20 
--------------------------------- 
0 1 2 3 4 5 6 7 8 9 10 11 
0 1 2 3 4 5 6 7 8 9 10 11 
Calls = 15, depth = 3, compares = 25, swaps = 48 
--------------------------------- 
11 10 9 8 7 6 5 4 3 2 1 0 
0 1 2 3 4 5 6 7 8 9 10 11 
Calls = 17, depth = 5, compares = 30, swaps = 62 
--------------------------------- 
11 9 7 5 3 1 0 2 4 6 8 10 
0 1 2 3 4 5 6 7 8 9 10 11 
Calls = 13, depth = 5, compares = 33, swaps = 56 
--------------------------------- 
11 0 10 1 9 2 8 3 7 4 6 5 
0 1 2 3 4 5 6 7 8 9 10 11 
Calls = 15, depth = 6, compares = 38, swaps = 60 
--------------------------------- 
Total: calls = 67, depth = 21, compares = 134, swaps = 246 
====== krQuick2 (no identity swaps) ====== 
4 0 2 5 1 3 
0 1 2 3 4 5 
Calls = 7, depth = 2, compares = 8, swaps = 16 
--------------------------------- 
0 1 2 3 4 5 6 7 8 9 10 11 
0 1 2 3 4 5 6 7 8 9 10 11 
Calls = 15, depth = 3, compares = 25, swaps = 28 
--------------------------------- 
11 10 9 8 7 6 5 4 3 2 1 0 
0 1 2 3 4 5 6 7 8 9 10 11 
Calls = 17, depth = 5, compares = 30, swaps = 52 
--------------------------------- 
11 9 7 5 3 1 0 2 4 6 8 10 
0 1 2 3 4 5 6 7 8 9 10 11 
Calls = 13, depth = 5, compares = 33, swaps = 46 
--------------------------------- 
11 0 10 1 9 2 8 3 7 4 6 5 
0 1 2 3 4 5 6 7 8 9 10 11 
Calls = 15, depth = 6, compares = 38, swaps = 44 
--------------------------------- 
Total: calls = 67, depth = 21, compares = 134, swaps = 186 
====== quick3 (no preswaps) ====== 
4 0 2 5 1 3 
0 1 2 3 4 5 
Calls = 7, depth = 3, compares = 10, swaps = 10 
--------------------------------- 
0 1 2 3 4 5 6 7 8 9 10 11 
0 1 2 3 4 5 6 7 8 9 10 11 
Calls = 23, depth = 11, compares = 66, swaps = 22 
--------------------------------- 
11 10 9 8 7 6 5 4 3 2 1 0 
0 1 2 3 4 5 6 7 8 9 10 11 
Calls = 23, depth = 11, compares = 66, swaps = 22 
--------------------------------- 
11 9 7 5 3 1 0 2 4 6 8 10 
0 1 2 3 4 5 6 7 8 9 10 11 
Calls = 15, depth = 7, compares = 46, swaps = 54 
--------------------------------- 
11 0 10 1 9 2 8 3 7 4 6 5 
0 1 2 3 4 5 6 7 8 9 10 11 
Calls = 19, depth = 6, compares = 37, swaps = 30 
--------------------------------- 
Total: calls = 87, depth = 38, compares = 225, swaps = 138 

******************************************************************************* 

Results of quick f0 s5 d1 
S5 format is best for displaying how the sublist changes during sorting. Since 
LOCAL is displayed only after a swap, superfluous identity swaps (many in this 
example) are readily apparent. 

====== krQuick ====== 
0 1 2 3 4 5 6 7 8 9 10 11 
GLOBAL 0 1 2 3 4 5 6 7 8 9 10 11 
Local1: 0 1 2 3 4 5 6 7 8 9 10 11 
Local2: 5 1 2 3 4 0 6 7 8 9 10 11 
Local3: 5 1 2 3 4 0 6 7 8 9 10 11 
Local3: 5 1 2 3 4 0 6 7 8 9 10 11 
Local3: 5 1 2 3 4 0 6 7 8 9 10 11 
Local3: 5 1 2 3 4 0 6 7 8 9 10 11 
Local3: 5 1 2 3 4 0 6 7 8 9 10 11 
Local4: 0 1 2 3 4 5 6 7 8 9 10 11 
GLOBAL 0 1 2 3 4 5 6 7 8 9 10 11 
    Local1: 0 1 2 3 4 
    Local2: 2 1 0 3 4 
    Local3: 2 1 0 3 4 
    Local3: 2 1 0 3 4 
    Local4: 0 1 2 3 4 
GLOBAL 0 1 2 3 4 5 6 7 8 9 10 11 
    Local1: 0 1 
    Local2: 0 1 
    Local4: 0 1 
GLOBAL 0 1 2 3 4 5 6 7 8 9 10 11 
     Local1: 
GLOBAL 0 1 2 3 4 5 6 7 8 9 10 11 
     Local1: 1 
GLOBAL 0 1 2 3 4 5 6 7 8 9 10 11 
    Local1: 3 4 
    Local2: 3 4 
    Local4: 3 4 
GLOBAL 0 1 2 3 4 5 6 7 8 9 10 11 
     Local1: 
GLOBAL 0 1 2 3 4 5 6 7 8 9 10 11 
     Local1: 4 
GLOBAL 0 1 2 3 4 5 6 7 8 9 10 11 
    Local1: 6 7 8 9 10 11 
    Local2: 8 7 6 9 10 11 
    Local3: 8 7 6 9 10 11 
    Local3: 8 7 6 9 10 11 
    Local4: 6 7 8 9 10 11 
GLOBAL 0 1 2 3 4 5 6 7 8 9 10 11 
    Local1: 6 7 
    Local2: 6 7 
    Local4: 6 7 
GLOBAL 0 1 2 3 4 5 6 7 8 9 10 11 
     Local1: 
GLOBAL 0 1 2 3 4 5 6 7 8 9 10 11 
     Local1: 7 
GLOBAL 0 1 2 3 4 5 6 7 8 9 10 11 
    Local1: 9 10 11 
    Local2: 10 9 11 
    Local3: 10 9 11 
    Local4: 9 10 11 
GLOBAL 0 1 2 3 4 5 6 7 8 9 10 11 
     Local1: 9 
GLOBAL 0 1 2 3 4 5 6 7 8 9 10 11 
     Local1: 11 
0 1 2 3 4 5 6 7 8 9 10 11 
Calls = 15, depth = 3, compares = 25, swaps = 48 

******************************************************************************** 

Results of quick f0 sa d1 
This is the same as the previous example but shows the additional detail of index 
values that lead to the swapping decision. However, the clutter tends to obscure 
what is actually happening to the sublist. 

====== krQuick ====== 
0 1 2 3 4 5 6 7 8 9 10 11 
GLOBAL 0 1 2 3 4 5 6 7 8 9 10 11 
Local1: 0 1 2 3 4 5 6 7 8 9 10 11 
Local2: 5 1 2 3 4 0 6 7 8 9 10 11 
i=1 @i=1 left=0 @left=5 last=0 
Local3: 5 1 2 3 4 0 6 7 8 9 10 11 
i=2 @i=2 left=0 @left=5 last=1 
Local3: 5 1 2 3 4 0 6 7 8 9 10 11 
i=3 @i=3 left=0 @left=5 last=2 
Local3: 5 1 2 3 4 0 6 7 8 9 10 11 
i=4 @i=4 left=0 @left=5 last=3 
Local3: 5 1 2 3 4 0 6 7 8 9 10 11 
i=5 @i=0 left=0 @left=5 last=4 
Local3: 5 1 2 3 4 0 6 7 8 9 10 11 
Local4: 0 1 2 3 4 5 6 7 8 9 10 11 
GLOBAL 0 1 2 3 4 5 6 7 8 9 10 11 
    Local1: 0 1 2 3 4 
    Local2: 2 1 0 3 4 
    i=1 @i=1 left=0 @left=2 last=0 
    Local3: 2 1 0 3 4 
    i=2 @i=0 left=0 @left=2 last=1 
    Local3: 2 1 0 3 4 
    Local4: 0 1 2 3 4 
GLOBAL 0 1 2 3 4 5 6 7 8 9 10 11 
    Local1: 0 1 
    Local2: 0 1 
    Local4: 0 1 
GLOBAL 0 1 2 3 4 5 6 7 8 9 10 11 
     Local1: 
GLOBAL 0 1 2 3 4 5 6 7 8 9 10 11 
     Local1: 1 
GLOBAL 0 1 2 3 4 5 6 7 8 9 10 11 
    Local1: 3 4 
    Local2: 3 4 
    Local4: 3 4 
GLOBAL 0 1 2 3 4 5 6 7 8 9 10 11 
     Local1: 
GLOBAL 0 1 2 3 4 5 6 7 8 9 10 11 
     Local1: 4 
GLOBAL 0 1 2 3 4 5 6 7 8 9 10 11 
    Local1: 6 7 8 9 10 11 
    Local2: 8 7 6 9 10 11 
    i=7 @i=7 left=6 @left=8 last=6 
    Local3: 8 7 6 9 10 11 
    i=8 @i=6 left=6 @left=8 last=7 
    Local3: 8 7 6 9 10 11 
    Local4: 6 7 8 9 10 11 
GLOBAL 0 1 2 3 4 5 6 7 8 9 10 11 
    Local1: 6 7 
    Local2: 6 7 
    Local4: 6 7 
GLOBAL 0 1 2 3 4 5 6 7 8 9 10 11 
     Local1: 
GLOBAL 0 1 2 3 4 5 6 7 8 9 10 11 
     Local1: 7 
GLOBAL 0 1 2 3 4 5 6 7 8 9 10 11 
    Local1: 9 10 11 
    Local2: 10 9 11 
    i=10 @i=9 left=9 @left=10 last=9 
    Local3: 10 9 11 
    Local4: 9 10 11 
GLOBAL 0 1 2 3 4 5 6 7 8 9 10 11 
     Local1: 9 
GLOBAL 0 1 2 3 4 5 6 7 8 9 10 11 
     Local1: 11 
0 1 2 3 4 5 6 7 8 9 10 11 
Calls = 15, depth = 3, compares = 25, swaps = 48 
0
あなたのコードにバグがあります

、最後の行:

qsort(v, left, last - 1); [7] 
qsort(v, last + 1, right); [8] 

は次のようになります。

qsort(v, left, last - 1, comp); [7] 
qsort(v, last + 1, right, comp); [8] 

または私は何かが足りないのですか?

さらに、標準ライブラリの名前を再利用するのは悪い方法です。特に、新しい関数がlib内の署名とは異なる署名を持っていると、 標準ライブラリの関数のqsortは、このプロトタイプがあります:あなたのプログラムが少し大きい(複数のオブジェクトファイル)がある場合、これは面白いバグを与えることができます

void qsort(void *base, size_t nel, size_t width, int (*compar)(const void *, const void *)); 

を。標準のqsort関数を呼び出す別のモジュールを想像してください。ただし、互換性のあるシグネチャではあるが別のセマンティックで再定義したので、予期しないバグが発生します。

0

こんにちは、私は87ページの例をしました。これから誰かが理解できるかもしれません。しかし、このコードのために行く前に、quicksort

/** 
* qsort.c 
* Quick sort using recursion 
*/ 

#include <stdio.h> 

void qsort(int v[], int left, int right); 

int main() 
{ 
    int v[] = {9, 3, 4, 6, 7, 3, 1}; 
    qsort(v, 0, 6); 

    int i; 

    for (i = 0; i < 7; i++) 
     printf(" %d ", v[i]); 

    printf("\n"); 

    return 0; 
} 

void qsort(int v[], int left, int right) 
{ 
    int i, last; /* last is pivot */ 

    void swap(int v[], int i, int j); 

    if (left >= right) 
     return; 

    swap(v, left, (left + right)/2); // swap mid element to front 
    last = left;      // set this position as pivot 

    for (i = left + 1; i <= right; i++) { 
     /*loop through every other element 
      swap elements less than pivot i.e bigger to right, smaller to left 
     */ 

     if (v[i] < v[left]) 
      swap(v, ++last, i);  // when swapping lesser element, record 
            // where our pivot moves 
     /* 
      we don't swap elements that are bigger than pivot, and are to right. 
      However we swap elements those are less than pivot. 
      With ++pivot we are essentially going to find out, where our 
      pivot will fit to be at the position, where all the elements 
      before it are less than it and all after it greater. 
     */ 
    } 

    // swap left(our pivot) to last(where pivot must go 
    // i.e all elements before pivot are less than it 
    // and all elements above it are greater 
    // remember they are lesser and greater 
    // but may not be sorted still 
    // this is called partition 
    swap(v, left, last); 

    // Do same(qsort) for all the elements before our pivot 
    // and above our pivot 
    qsort(v, left, last - 1); // last is our pivot position 
    qsort(v, last + 1, right); 

    // Each of above two qsort will use middle element as pivot and do 
    // what we did above, because same code will be executed by recursive 
    // functions 

}          

void swap(int v[], int i, int j) 
{ 
    int temp; 

    temp = v[i]; 
    v[i] = v[j]; 
    v[j] = temp; 
} 

最も重要な部分は、ピボット(他に自由に移動する一方で、場所であなたの1フィートを置く)でご覧ください。中間の要素をピボットとして選択し、それを前面に持ってきて他のすべての要素と比較します。それらが私たちのピボットよりも小さい場合、私たちはそれらを入れ替えて、ピボットの位置だけを増やします(ピボットの要素が最初に存在するので注意してください)。ループが終了すると、最初にピボット要素がこの場所(ピボット位置)に移動します。ループの後、ピボットの前のすべての要素がピボットより小さくなり、ピボットの上のすべての要素がピボットよりも大きくなります。最初のループではソートされません。したがって、ピボットの下のすべての要素とピボットの上のすべての要素に、同じソートアルゴリズムを再帰的に適用してソートする必要があります。