最初から最後まで1つずつリンクされたリストを印刷する

Question

最初から最後まで1つずつリストを単独で印刷します。

例：

1-> 2-> 3-> 4-> 5-> 6

期待出力：

1,6,2,5,3,4

Answer 1

チェックしてください！

#include<bits/stdc++.h> 
using namespace std; 

struct Node 
{ 
    int data; 
    struct Node *next; 
}; 

Node* newNode(int key) 
{ 
    Node *temp = new Node; 
    temp->data = key; 
    temp->next = NULL; 
    return temp; 
} 

void reverselist(Node **head) 
{ 
    Node *prev = NULL, *curr = *head, *next; 

    while (curr) 
    { 
     next = curr->next; 
     curr->next = prev; 
     prev = curr; 
     curr = next; 
    } 

    *head = prev; 
} 

void printlist(Node *head) 
{ 
    while (head != NULL) 
    { 
     cout << head->data << " "; 
     if(head->next) cout << "-> "; 
     head = head->next; 
    } 
    cout << endl; 
} 

void arrange(Node **head) 
{ 
    Node *slow = *head, *fast = slow->next; 
    while (fast && fast->next) 
    { 
     slow = slow->next; 
     fast = fast->next->next; 
    } 

    Node *head1 = *head; 
    Node *head2 = slow->next; 
    slow->next = NULL; 
    reverselist(&head2); 
    *head = newNode(0); 
    Node *curr = *head; 
    while (head1 || head2) 
    { 
     if (head1) 
     { 
      curr->next = head1; 
      curr = curr->next; 
      head1 = head1->next; 
     } 

     if (head2) 
     { 
      curr->next = head2; 
      curr = curr->next; 
      head2 = head2->next; 
     } 
    } 
    *head = (*head)->next; 
} 

int main() 
{ 
    Node *head = newNode(1); 
    head->next = newNode(2); 
    head->next->next = newNode(3); 
    head->next->next->next = newNode(4); 
    head->next->next->next->next = newNode(5); 
    printlist(head);  
    arrange(&head); 
    printlist(head);  
    return 0; 
}