エンティティフレームワーク永遠に残っている結合（パフォーマンスの問題）

Question

私はエンティティフレームワークとlinqを使って複数の左外部結合を実行していますが、エンティティフレームワークを通してクエリを実行するのに3秒かかります。

私は((System.Data.Objects.ObjectQuery)query).ToTraceString();を使用し、管理スタジオでsqlステートメントをテストし、即座に実行しました。

ここにlinqコードがあります。コメント欄で

var query = from Inventory in db.INVENTORies       

        join NewInventory in db.NEW_INVENTORY on Inventory.Barcode equals NewInventory.Barcode into lj_1       
        from q_NewInventory in lj_1.DefaultIfEmpty() 
        join Categories in db.Categorys on Inventory.CAT_ID equals Categories.CAT_ID into lj_2 
        from q_Categories in lj_2.DefaultIfEmpty() 
        join SCategories in db.StoneCategories on Inventory.TP_ID equals SCategories.TP_ID into lj_3 
        from q_SubCategory in lj_3.DefaultIfEmpty() 
        join qSupplier in db.Suppliers on Inventory.SUP_ID equals qSupplier.SUP_ID into lj_4 
        from q_Supplier in lj_4.DefaultIfEmpty() 
        join qStatus in db.Statuses on Inventory.ST_ID equals qStatus.ST_ID into lj_5 
        from q_Status in lj_5.DefaultIfEmpty() 
        join q_Locations in db.Locations on Inventory.LOC_ID equals q_Locations.LOC_ID into lj_7 
        from q_locations in lj_7.DefaultIfEmpty() 
        join q_Stone1 in db.Stones on Inventory.StoneID_1 equals q_Stone1.STONE_ID into lj_s1 
        from q_stone1 in lj_s1.DefaultIfEmpty() 
        join q_Stone2 in db.Stones on Inventory.StoneID_2 equals q_Stone2.STONE_ID into lj_s2 
        from q_stone2 in lj_s2.DefaultIfEmpty() 
        join q_Stone3 in db.Stones on Inventory.StoneID_3 equals q_Stone3.STONE_ID into lj_s3 
        from q_stone3 in lj_s3.DefaultIfEmpty() 
        join q_Stone4 in db.Stones on Inventory.StoneID_4 equals q_Stone4.STONE_ID into lj_s4 
        from q_stone4 in lj_s4.DefaultIfEmpty() 
        join q_Stone5 in db.Stones on Inventory.StoneID_5 equals q_Stone5.STONE_ID into lj_s5 
        from q_stone5 in lj_s5.DefaultIfEmpty() 
        join q_Stone6 in db.Stones on Inventory.StoneID_6 equals q_Stone6.STONE_ID into lj_s6 
        from q_stone6 in lj_s6.DefaultIfEmpty() 
        join q_Stone7 in db.Stones on Inventory.StoneID_7 equals q_Stone7.STONE_ID into lj_s7 
        from q_stone7 in lj_s7.DefaultIfEmpty() 
        join q_Stone8 in db.Stones on Inventory.StoneID_8 equals q_Stone8.STONE_ID into lj_s8 
        from q_stone8 in lj_s8.DefaultIfEmpty() 
        join qMasterInventory in db.MASTERINVENTORies on q_NewInventory.InvItemNo equals qMasterInventory.INVITEMNO into lj_6 
        from q_MasterInventory in lj_6.DefaultIfEmpty() 
        where Inventory.Barcode == _Barcode 

        select new 
        { 
         inv_InvID = Inventory.INV_ID, inv_Barcode = Inventory.Barcode, 
         inv_catID = Inventory.CAT_ID, inv_SubCatID = Inventory.TP_ID, inv_Price = Inventory.ITEM_PRICE, inv_Cost = Inventory.ITEM_COST, 
         inv_PricePoint = Inventory.PricePoint, inv_StatusID = Inventory.ST_ID, inv_StID = Inventory.ST_ID, inv_SupID = Inventory.SUP_ID, 
         inv_LocID = Inventory.LOC_ID, inv_LabSupplier = Inventory.LabSupplier, inv_LabStone1 = Inventory.LabStone1, inv_LabCategory = Inventory.LabCategory, 
         inv_LabExtra = Inventory.LabExtra, inv_LabMadeIn = Inventory.LabMadeIn, inv_Width = Inventory.ChainThickNess, inv_Size = Inventory.ChainSize, 
         inv_Stone1 = Inventory.StoneID_1,inv_Stone2 = Inventory.StoneID_2,inv_Stone3 = Inventory.StoneID_3,inv_Stone4 = Inventory.StoneID_4,inv_Stone5 = Inventory.StoneID_5,inv_Stone6 = Inventory.StoneID_6,inv_Stone7 = Inventory.StoneID_7,inv_Stone8 = Inventory.StoneID_8,inv_Stone9 = Inventory.StoneID_9,inv_Stone10 = Inventory.StoneID_10, 
         stat_Status = q_Status.DESCRIPTION, 
         cat_Category = q_Categories.DESCRIPTION, 
         subCat_SubCategory = q_SubCategory.DESCRIPTION, 
         sup_Supplier = q_Supplier.Name, 
         loc_Location = q_locations.DESCRIPTION, 

         mas_SKU = q_MasterInventory.INVITEMNO, 
         mas_GUID = q_MasterInventory.ItemGUID, 

         stone1 = q_stone1.DESCRIPTION, 
         stone2 = q_stone2.DESCRIPTION, 
         stone3 = q_stone3.DESCRIPTION, 
         stone4 = q_stone4.DESCRIPTION, 
         stone5 = q_stone5.DESCRIPTION, 
         stone6 = q_stone6.DESCRIPTION, 
         stone7 = q_stone7.DESCRIPTION, 
         stone8 = q_stone8.DESCRIPTION, 

        }; 

Answer 1

1. Guysはあなたは、T-SQLでそれを再記述する必要があると述べました。真実。 SQL to LINQ converter toolsのいずれかを試すことができます。

2. MS SQL Profilerを使用して、TSQLのパフォーマンスを確認し、改善してください。インデックスbut not too muchを追加する

3. てみてください:)

Answer 2

このクエリのデータベース・ビューを作成し、専用のエンティティを新しい読みにビューをマップします。その後、純粋なLINQの実行と新しい実行の違いを比較します。恐ろしいLINQクエリをSQLに変換することに問題があった場合は、この方法を使用することで回避できます。まだ遅い場合、問題は他の場所で発生します。