oracle blob imageをPHPまたはASPで表示

Question

Oracle 10gデータベースからBLOBイメージをロードしようとしています。私は.ASP VBと.PHPの両方で試しました。私はそれぞれに以下のメッセージを取得し、両方の例については

TABLE = STD_IMAGE 
Name       Null? Type 
------------------------------- -------- ---- 
IMG_ID_NO      NOT NULL NUMBER(10) 
IMG_IMAGE      NOT NULL BLOB 

ASPコード

<%@ LANGUAGE="VBSCRIPT" %> 
<%Option Explicit 
Dim Rs, sSQL, OBJdbConnection 
' Clear out the existing HTTP header information 
Response.Expires = 0 
Response.Buffer = TRUE 
Response.Clear 
'Change the HTTP header to reflect that an image is being passed. 
Response.ContentType = "image/jpg" 
Set OBJdbConnection = Server.CreateObject("ADODB.Connection") 
OBJdbConnection.Open "Provider=OraOLEDB.Oracle;Data Source=xxxxxx;User Id=xxxx;Password=xxxxx;" 
DIM itemID 
itemID = request.querystring("InventoryItemId") 
itemID = 25 
sSQL = "Select * from std_image where IMG_ID_NO=25" 
set rs = OBJdbConnection.Execute(sSql) 
If not rs.eof Then 
Response.BinaryWrite rs("IMG_IMAGE") 
Response.End 
End If 
CloseRecordset(rs)%> 
<%Set OBJDbConnection = nothing%> 

PHPコード

<?php 
$db ="(DESCRIPTION = 
(ADDRESS = 
    (PROTOCOL = TCP) 
    (HOST = xxxxxx) 
    (PORT = 1522) 
) 
    (CONNECT_DATA = (SID = xxxxx)) 
    )"; 

$odbc = ocilogon ('xxxxxx', 'xxxxxx', $db) or die("Could not connect to Oracle database!") or die (ocierror()); 

$sql = "SELECT IMG_IMAGE FROM std_image WHERE IMG_ID_NO = 25"; 
$stid = ociparse($odbc, $sql); 

ociexecute($stid); 
$row = oci_fetch_array($stid, OCI_ASSOC+OCI_RETURN_NULLS); 
if (!$row) { 
    header('Status: 404 Not Found'); 
} else { 
    $img = $row['IMG_IMAGE']->load(); 
    header("Content-type: image/jpg"); 
    print $img; 
} 
    ?> 

：

The image “http://localhost/test_ShowImage.asp” cannot be displayed because it contains errors. 
The image “http://localhost/test_getImage.php” cannot be displayed because it contains errors. 

Answer 1

私はあなたのコードを私の基礎として使っていました。私はPHP ADODBライブラリを使用しました。

include("settings.php"); //includes db connection 

$docid = $_REQUEST['document_id']; 

$sql = "SELECT DOCUMENT_FILE FROM ACCOUNTS_DOCUMENTS WHERE DOCUMENT_ID = ".$docid; 
$rs = $db->Execute($sql); 
header("Content-type: image/jpg"); 
print $rs->fields['DOCUMENT_FILE'];