今日、毎週、毎月、および2つの日付の間にmysqlデータベースを使用してグラフを作成します

Question

私のデータベースにはmysqlを使用しています。私はテーブルに分析の詳細を作成しました。そのデータをグラフに表示したい。私は特定のリンクのクリックとデータベースに保存された日時のデータを作成しました。 表は、私は今日のために時間に基づいて、毎週平日（日曜日、月曜日、火曜日...土曜日）の代わりに、時間の同様

hour | click 
--------------- 
1 | 0 
2 | 0 
3 | 0 
4 | 0 
5 | 2 
6 | 0 
7 | 1 
8 | 1 
9 | 1 
10 | 0 
11 | 1 
12 | 0 
13 | 0 
14 | 0 
15 | 0 
16 | 0 
17 | 0 
18 | 1 
19 | 0 
20 | 1 
21 | 0 
22 | 0 
23 | 0 
24 | 0 

のようなデータを表示したい

id | datetime 
------------- 
1 | 2016-04-18 05:26:36 
2 | 2016-04-18 07:26:36 
3 | 2016-04-18 09:26:36 
4 | 2016-04-18 11:26:36 
5 | 2016-04-18 08:26:36 
6 | 2016-04-18 05:26:36 
7 | 2016-04-18 20:26:36 
8 | 2016-04-18 18:26:36 

のようなものです毎月の番号（1,2,3,4,5 ...... 28/29/30/31）

今日のリストのクエリを使用しましたが、データが存在する時間の名前のみが表示されます。その時間に値がない場合は、0のフィルですべての時間リストが必要です。

私はこのクエリを使用しています。

SELECT DISTINCT(hour(`beacon_date_time`)) as hour,COUNT(*) from beaconanalytics WHERE DATE_FORMAT(`beacon_date_time`,'%Y-%m-%d') BETWEEN DATE_FORMAT(DATE_SUB(NOW(), INTERVAL 1 DAY),'%Y-%m-%d') AND DATE_FORMAT(NOW(),'%Y-%m-%d') GROUP by hour(`beacon_date_time`) 

私は7日のためにクエリを使用していますが、それはまた、残りの日のためのショー0のデータベースではない一日の記録を与えています。

これはクエリです。

SELECT dayname(`beacon_date_time`) as hour,COUNT(*) from beaconanalytics WHERE DATE_FORMAT(`beacon_date_time`,'%Y-%m-%d') BETWEEN DATE_FORMAT(DATE_SUB(NOW(), INTERVAL 7 DAY),'%Y-%m-%d') AND DATE_FORMAT(NOW(),'%Y-%m-%d') GROUP by dayname(`beacon_date_time`) 

Answer 1

少し奇妙に見える、これを試してみてください。毎週のためにこれを試してみてください

SELECT tmp.hour, sum(tmp.click) AS click 
FROM 
    (SELECT DISTINCT 
    (hour(`beacon_date_time`)) AS hour, 
    COUNT(*) AS click 
    FROM beaconanalytics 
    WHERE DATE_FORMAT(`beacon_date_time`, '%Y-%m-%d') BETWEEN DATE_FORMAT(DATE_SUB(NOW(), INTERVAL 1 DAY), 
                     '%Y-%m-%d') AND DATE_FORMAT(NOW(), '%Y-%m-%d') 
    GROUP BY hour(`beacon_date_time`) 
    UNION 
    SELECT 1 AS hour, 0 AS click FROM dual 
    UNION 
    SELECT 2 AS hour, 0 AS click FROM dual 
    UNION 
    SELECT 3 AS hour, 0 AS click FROM dual 
    UNION 
    SELECT 4 AS hour, 0 AS click FROM dual 
    UNION 
    SELECT 5 AS hour, 0 AS click FROM dual 
    UNION 
    SELECT 6 AS hour, 0 AS click FROM dual 
    UNION 
    SELECT 7 AS hour, 0 AS click FROM dual 
    UNION 
    SELECT 8 AS hour, 0 AS click FROM dual 
    UNION 
    SELECT 9 AS hour, 0 AS click FROM dual 
    UNION 
    SELECT 10 AS hour, 0 AS click FROM dual 
    UNION 
    SELECT 11 AS hour, 0 AS click FROM dual 
    UNION 
    SELECT 12 AS hour, 0 AS click FROM dual 
    UNION 
    SELECT 13 AS hour, 0 AS click FROM dual 
    UNION 
    SELECT 14 AS hour, 0 AS click FROM dual 
    UNION 
    SELECT 15 AS hour, 0 AS click FROM dual 
    UNION 
    SELECT 16 AS hour, 0 AS click FROM dual 
    UNION 
    SELECT 17 AS hour, 0 AS click FROM dual 
    UNION 
    SELECT 18 AS hour, 0 AS click FROM dual 
    UNION 
    SELECT 19 AS hour, 0 AS click FROM dual 
    UNION 
    SELECT 20 AS hour, 0 AS click FROM dual 
    UNION 
    SELECT 21 AS hour, 0 AS click FROM dual 
    UNION 
    SELECT 22 AS hour, 0 AS click FROM dual 
    UNION 
    SELECT 23 AS hour, 0 AS click FROM dual 
    UNION 
    SELECT 24 AS hour, 0 AS click FROM dual) tmp 
GROUP BY tmp.hour 

）;）

SELECT tmp.dayname, sum(tmp.click) AS click 
FROM 
    (SELECT dayname(`beacon_date_time`) as dayname,COUNT(*) AS click from beaconanalytics WHERE DATE_FORMAT(`beacon_date_time`,'%Y-%m-%d') BETWEEN DATE_FORMAT(DATE_SUB(NOW(), INTERVAL 7 DAY),'%Y-%m-%d') AND DATE_FORMAT(NOW(),'%Y-%m-%d') GROUP by dayname(`beacon_date_time`) 
    UNION 
    SELECT 'Monday' AS dayname, 0 AS click FROM dual 
    UNION 
    SELECT 'Tuesday' AS dayname, 0 AS click FROM dual 
    UNION 
    SELECT 'Wednesday' AS dayname, 0 AS click FROM dual 
    UNION 
    SELECT 'Thursday' AS dayname, 0 AS click FROM dual 
    UNION 
    SELECT 'Friday' AS dayname, 0 AS click FROM dual 
    UNION 
    SELECT 'Saturday' AS dayname, 0 AS click FROM dual 
    UNION 
    SELECT 'Sunday' AS dayname, 0 AS click FROM dual 
) tmp 
GROUP BY tmp.dayname 

Answer 2

SELECT days.daynum, IF(count.c IS NULL, 0, count.c) from 
     (
     SELECT t*10+u daynum 
     FROM 
      (SELECT 0 t UNION SELECT 1 UNION SELECT 2 UNION SELECT 3) A, 
      (SELECT 0 u UNION SELECT 1 UNION SELECT 2 UNION SELECT 3 
      UNION SELECT 4 UNION SELECT 5 UNION SELECT 6 UNION SELECT 7 
      UNION SELECT 8 UNION SELECT 9) B 
     ORDER BY daynum 
     ) as days 
     LEFT JOIN 
     (
     SELECT DISTINCT(hour(`beacon_date_time`)) as hour,COUNT(*) as c from beaconanalytics WHERE DATE_FORMAT(`beacon_date_time`,'%Y-%m-%d') BETWEEN DATE_FORMAT(DATE_SUB(NOW(), INTERVAL 1 DAY),'%Y-%m-%d') AND DATE_FORMAT(NOW(),'%Y-%m-%d') GROUP by hour(`beacon_date_time`) 
     ) as count ON count.hour = days.daynum ORDER BY days.daynum