いくつかのデータをLua呼び出し関数にプッシュ

Question

私は2つのファイルを持っています - 1つはLuaスクリプトとスクリプト自体を実行するものです。ここで

は、彼らは以下のとおりです。

host.cpp：

#include <lua.hpp> 
#include <iostream> 

using namespace std; 

int someHandler(lua_State *l) 
{ 
    int argc = lua_gettop(l); 

    for (int i = 0; i < argc; i++) 
    { 
     cout << "ARG[" << i + 1 << "] = " << lua_tostring(l, i + 1) << endl; 
    } 

    lua_pushstring(l, "m_pi"); 
    //lua_pop(l, argc - 1); 
    //lua_pushnumber(l, 3.14); 

    return argc; 
} 

int main() 
{ 
    lua_State *l = lua_open(); 
    luaL_openlibs(l); 

    lua_register(l, "moo", someHandler); 

    luaL_dofile(l, "script.lua"); 

    lua_close(l); 

    return 0; 
} 

script.lua：

res = moo("hello", "world"); 

print(moo()); 

for k, v in res do 
    print(k.." = "..v); 
end 

はg++ host.cpp -o host.elf -I/usr/include/lua5.1 -llua5.1でhost.cppをコンパイル。

host.elfの実行結果は次のとおりです。

ARG[1] = hello 
ARG[2] = world 
<\n> 

それがされるべきである：

ARG[1] = hello 
ARG[2] = world 
m_pi 

私は間違って何をしますか？

Answer 1

ライン・バイ・ラインの説明：C++へ

--This calls moo with two arguments 
--(ignore the assignment for now, we will come back to that) 
res = moo("hello", "world"); 

コントロール転送：

//the stack of l looks like this: ["hello", "world"] 
int someHandler(lua_State *l) 
{ 

    int argc = lua_gettop(l); //int argc = 2; 

    //This loop prints: 
    //"ARG[1] = hello\n" 
    //"ARG[2] = world\n" 
    for (int i = 0; i < argc; i++) 
    { 
     cout << "ARG[" << i + 1 << "] = " << lua_tostring(l, i + 1) << endl; 
    } 
    //This pushes "m_pi" on to the stack: 
    lua_pushstring(l, "m_pi"); 

    //The stack now looks like ["hello", "world", "m_pi"] 

    //Returns 2. 
    //Lua will treat this as a function which 
    //returns the top two elements on the stack (["world", "m_pi"]) 
    return argc; 
} 

コントロールLUAに戻ります：

--Assigns the first result ("world") to res, discards the other results ("m_pi") 
res = moo("hello", "world"); 

--Calls `moo` with zero arguments. 
--This time, `lua_gettop(l)` will evaluate to `0`, 
--so the for loop will not be entered, 
--and the number of results will be taken to be `0`. 
--The string pushed by `lua_pushstring(l, "m_pi")` will be discarded. 
--`moo()` returns no results, so `print` prints nothing. 
print(moo()); 

--WTF??: res = "world", which is a string, not an expression which evaluates to 
--a loop function, a state variable, and a element variable. 

--The for loop will raise in an error when it 
--attempts to call a copy of `res` (a string) 
for k, v in res do 
    print(k.." = "..v); 
end