私は最小の日付に基づいて行を戻すためにしようとしますが、Teradataの場合は、日付フィールドに

Question

select customer_id, street_address, city, state, zip 
from customer where min(date); 

Answer 1

を戻すわけではない：

select customer_id, street_address, city, state, zip from customer 
qualify row_number() over(partition customer_id order by date)=1 

その他のオプション：

select customer_id,street_address, city, state, zip from customer a 
inner join (select customer_id, min(date) as min_date from customer group by customer_id) b 
on a.customer_id=b.customer_id and a.date=b.min_date 

Answer 2

はあなたを検討していますこれをT-SQLで試してみてください。 CTEのために読んで

select 'a123' street_address, 'as' city,'ap' state, 123456 zip, cast(getdate()-10 as date) [day] into #temp 
insert into #temp values('b12','ad','aw',345478,cast(getdate()-1 as date)) 
insert into #temp values('c243','a2','a3',3458,cast(getdate()-12 as date)) 
insert into #temp values('e3d','a2','af',8324,cast(getdate()-13 as date)) 
insert into #temp values('f46','a3','ag',337,cast(getdate()-13 as date)) 
insert into #temp values('g23','a4','ah',0374,cast(getdate()-1 as date)) 
insert into #temp values('h12','af','aj',946,cast(getdate()-17 as date)) 
insert into #temp values('634','ad','a8',345,cast(getdate()-17 as date)) 

select * from #temp 

--Query to return min valued row 
;with q as (select min(day) minday from #temp) 
select street_address, city, state, zip from #temp t cross apply q where t.day=q.minday 

ブログ：すべてのRDBMSで動作する最も簡単な解決策のオン https://www.red-gate.com/simple-talk/sql/t-sql-programming/sql-server-cte-basics/

Answer 3

です：あなたは例が

CTE（共通テーブル式）を使用して試すことができます

select customer_id, street_address, city, state, zip 
from customer 
where date in (select min(date) from customer) 
;