MySQL：複数のエントリの2つの日付の間の変更の割合を取得

Question

私のテーブルの2つの日付間の変更の割合を取得しようとしています。私は一緒にデータを次の形式にしましたが、日付の違いを得るために過去に移動することはできません。

電流出力：

+------------+---------+--------+ 
| day  | player | score | 
+------------+---------+--------+ 
| 2016-12-20 | player1 | 69253 | 
| 2016-12-15 | player1 | 61662 | 
| 2016-12-15 | player2 | 309180 | 
| 2016-12-20 | player2 | 318112 | 
| 2016-12-15 | player3 | 1525 | 
| 2016-12-20 | player3 | 1405 | 
+------------+---------+--------+ 

予想される出力：私は私のクエリに追加することができますどのような

SET @maxDate = (SELECT DATE(from_unixtime(max(timestamp) /1000)) from city_data); 
SET @minDate = date_sub(@maxDate, INTERVAL 5 day); 

SELECT 
    day, 
    player, 
    sum(score) as score 
FROM 
(
    SELECT 
     DATE(FROM_UNIXTIME(cd.timestamp/1000)) as day, 
     player, 
     score 
    FROM 
     city_data cd 
    WHERE 
     DATE(FROM_UNIXTIME(cd.timestamp/1000)) IN(@minDate, @maxDate) 
) t 
GROUP BY 
    day, player 

：

+---------+------------+------------+------------+----------+---------------+ 
| Player | startDate | endDate | startScore | endScore | percentChange | 
+---------+------------+------------+------------+----------+---------------+ 
| player1 | 2016-12-15 | 2016-12-20 |  61662 | 69253 |  0.8904 | 
| player2 | 2016-12-15 | 2016-12-20 |  309180 | 318112 |  0.9719 | 
| player3 | 2016-12-15 | 2016-12-20 |  1525 |  1405 |  -0.0854 | 
+---------+------------+------------+------------+----------+---------------+ 

私はこの時点に取得しています望ましいouを得るためにtput？私は私のクエリの結果が一時テーブルに入れてそこから使用できると仮定できると思いますか？

編集：要求ごと元のテーブルが（表は数万行で、これは単なる一例であることに注意）

---------------+--------------+-------+-----+ 
| timestamp | player | score | id | 
+---------------+--------------+-------+-----+ 
| 1477173600000 | player1  | 66 | 1 | 
| 1477173600000 | player1  | 654 | 2 | 
| 1477173600000 | player1  |  3 |  | 
| 1477173600000 | player2  | 238 | 4 | 
| 1477173600000 | player2  | 9123 | 5 | 
| 1477287798758 | player1  | 69 | 6 | 
| 1477287798758 | player1  | 678 | 7 | 
| 1477287798758 | player1  |  8 |  | 
| 1477287798758 | player2  | 698 | 9 | 
| 1477287798758 | player2  | 11000 | 10 | 
+---------------+--------------+-------+-----+ 

Answer 1

あなたが毎日のスコアの比較とそれに対する以前のものを5日間を必要とすると仮定すると、あなたはself joinを使用することができます。あなたは、この結果セットから特定の日付が必要な場合は

SELECT t1.player, 
     t2.dt as startdate, 
     t1.dt as enddate,   
     t2.score as startscore, 
     t1.score as endscore, 
     (t1.score-t2.score)/(1.0*t1.score) as pct_change 
FROM (select player,DATE(FROM_UNIXTIME(timestamp/1000)) as dt,sum(score) as score from city_data group by player,DATE(FROM_UNIXTIME(timestamp/1000))) t1 
JOIN (select player,DATE(FROM_UNIXTIME(timestamp/1000)) as dt,sum(score) as score from city_data group by player,DATE(FROM_UNIXTIME(timestamp/1000))) t2 
ON t1.player=t2.player AND DATE_SUB(t1.dt, INTERVAL 5 day) = t2.dt 

は、あなたがそれらをフィルタリングするwhere句を使用することができます。例えば、

SELECT * FROM (
SELECT t1.player, 
     t2.dt as startdate, 
     t1.dt as enddate,   
     t2.score as startscore, 
     t1.score as endscore, 
     (t1.score-t2.score)/(1.0*t1.score) as pct_change 
FROM (select player,DATE(FROM_UNIXTIME(timestamp/1000)) as dt,sum(score) as score from city_data group by player,DATE(FROM_UNIXTIME(timestamp/1000))) t1 
JOIN (select player,DATE(FROM_UNIXTIME(timestamp/1000)) as dt,sum(score) as score from city_data group by player,DATE(FROM_UNIXTIME(timestamp/1000))) t2 
ON t1.player=t2.player AND DATE_SUB(t1.dt, INTERVAL 5 day) = t2.dt 
) x 
WHERE startdate = date '2016-12-15' and enddate = date '2016-12-20' 

説明：1日あたり各プレイヤーのスコアの合計を取得するために、派生テーブルを使用してください。それを2倍にして、プレイヤーごとに毎日5日前に参加するようにします。その後、テーブルを参照し、同じ行になるように必要な値を選択します。

Answer 2

あなたは、この使用することができますどのように見えるかの例：

を

--Created test table 
create table t (day date, player varchar(100), score integer); 
insert into t values ('2016-12-20','player1', 69253); 
insert into t values ('2016-12-15','player1', 61662); 
insert into t values ('2016-12-15','player2', 309180); 
insert into t values ('2016-12-20','player2', 318112); 
insert into t values ('2016-12-15','player3', 1525); 
insert into t values ('2016-12-20','player3', 1405); 

そして

1. Find the `max` and `min` of day for each player -- table alias `t2` 
2. Join it twice with original table 
    1. First on player and min of day from t2 --> to get minimum score 
    2. Then on player and max of day from t2 --> to get maximum score 
3. then, do a group by to actually calculate min and max of score. 
4. find percentChange at the end. 

select t.*, (endScore-startScore)/endScore percentChange 
from (
select t1.player, t2.startDate, t2.endDate, min(t1.score) startScore, max(t3.score) endScore 
from t t1 
inner join 
(select player, min(day) startDate, max(day) endDate 
from t 
group by player) t2 
on t1.player = t2.player 
and t1.day = t2.startDate 
inner join t t3 
on t2.player = t3.player 
and t3.day = t2.endDate 
group by t1.player, t2.startDate, t2.endDate) t; 

は生成：

| player |     startDate |     endDate | startScore | endScore | percentChange | 
|---------|----------------------------|----------------------------|------------|----------|---------------| 
| player1 | December, 15 2016 00:00:00 | December, 20 2016 00:00:00 |  61662 | 69253 |  0.1096 | 
| player2 | December, 15 2016 00:00:00 | December, 20 2016 00:00:00 |  309180 | 318112 |  0.0281 | 
| player3 | December, 15 2016 00:00:00 | December, 20 2016 00:00:00 |  1525 |  1405 |  -0.0854 |