XMLのLINQクエリ

Question

または(app-type="applicant-inventor" and designation="us-only")という名前のapplicant要素の名前と住所を取得したいとします。

LINQを使用してクエリを実行する方法を教えてください。あなたはこれを試すことが

<applicants> 
    <applicant designation="all-except-us" app-type="applicant" sequence="1"> 
    <addressbook> 
     <name name-type="legal">Hello LIGHTING CO., LTD.</name> 
     <address> 
      <address-1>Myanmar</address-1> 
     </address> 
    </addressbook> 
    <nationality> 
     <country>CN</country> 
    </nationality> 
    <residence> 
     <country>CN</country> 
    </residence> 
    </applicant> 
    <applicant designation="us-only" app-type="applicant-inventor" sequence="2"> 
    <addressbook> 
     <name name-type="natural">Henry </name> 
     <address> 
      <address-1>Chicago 380892</address-1> 
     </address> 
    </addressbook> 
    <nationality> 
     <country>CN</country> 
    </nationality> 
    <residence> 
     <country>CN</country> 
    </residence> 
    </applicant> 
    <applicant designation="us-only" app-type="applicant-inventor" sequence="3"> 
    <addressbook lang="EN"> 
     <name name-type="natural">Gho Chi</name> 
     <address> 
      <address-1>Thai 310012</address-1> 
     </address> 
    </addressbook> 
    <nationality> 
     <country>CN</country> 
    </nationality> 
    <residence> 
     <country>CN</country> 
    </residence> 
    </applicant> 
</applicants> 

Answer 1

var query = from c in xdoc.Descendants("applicant") 
       where (c.Attribute("app-type").Value=="applicant" || 
       c.Attribute("app-type").Value=="applicant-inventor") && 
       c.Attribute("designation").Value=="us-only" 
       select c.Descendants("addressbook"); 

：

<addressbook> 
    <name name-type="natural">Henry </name> 
    <address> 
    <address-1>Chicago 380892</address-1> 
    </address> 
</addressbook> 

しかし、あなたは、おそらくのようなアドレスを構築したいと思いますこれは（より多くの作業が必要ですが、これがアイデアです）

var query = from c in xdoc.Descendants("applicant") 
      where (c.Attribute("app-type").Value=="applicant" || 
      c.Attribute("app-type").Value=="applicant-inventor") && 
      c.Attribute("designation").Value=="us-only" 
      select new { 
      Name= c.Descendants("addressbook").Descendants("name").First().Value, 
      Address=c.Descendants("addressbook").Descendants("address").First().Value, 
      Country = c.Descendants("residence").Descendants("country").First().Value 
      }; 

Answer 2

、

var result = from ele in xmlDoc.Descendants("applicant") 
    where ((string)ele.Attribute("app-type")) == "applicant" || 
    (((string)ele.Attribute("app-type")) == "applicant-inventor" && 
      ((string)ele.Attribute("designation")) == "us-only") 
        select ele; 

この形式上のアドレスを返しますクエリの上

Answer 3

私は複雑な答えが好きです。

XPathSelectで使用したXPathの代わりに...

use System.Xml.XPath; //Contains extensions for LINQ to XML 
.... 
var resultList = XPathSelectElements(XNode, String); 
... 
var resultElement = XPathSelectElement(XNode, String); 
//This can only select an element, not an attribute. 

申請要素アプリ型=「申請者」または（アプリ型=「申請者・発明者」と呼称=「私たち専用」）

var xpath = "/applicant[app-type=applicant or (app-type=\"applicant-inventor\" and designation=us-only)]/addressbook"; 
var resultList = XPathSelectElements(root, xpath); 

var nameAndAddress = 
    from el in resultList 
    select new { 
     addresses = el.Element("Address").Elements() 
     name = (string)el.Elements("name").FirstOrFDefault() 
    };