@Thientvse は、これは私がコード化されたコードです...それは正しい出力を与える...あなたは私のコードが正しいかどうかを教えてくださいすることができ、それは、このシナリオ
import java.util.ArrayList;
import java.util.Scanner;
public class Game {
public static int combinationCounts(int input1){
ArrayList<String> mainalternatestring = new ArrayList<String>();
ArrayList<String> mainverticalstring = new ArrayList<String>();
String sb = "ABC#DEF#GHI# J ";
String a=null,b=null,c=null,nw=null;
int mainindex = 0,counter,totalcount=10,index=0,mainindex_duplicate=0,count=1;
if(input1 > 1 && input1 <= 4){
while(mainindex != 11){
int level = 0;
counter = 0;
count=1;
char[] strtoworkon = new char[sb.length()];
index=0;
if(mainindex != 0)
mainindex = mainindex+1;
for(int j = mainindex; count!= (sb.length()-mainindex) ; j++){
if(level == input1)
break;
if(sb.charAt(j) == '#'){
level++;
if (counter == 0){
mainindex_duplicate = j;
counter = 1;
}
}
if(level <= input1){
strtoworkon[index] = sb.charAt(j);
index++;
}
count++;
}
mainindex = mainindex_duplicate;
// for sideways combinations
for(int m = 0; m <= strtoworkon.length; m++){
c = null;
if(strtoworkon[m] == ' ')
break;
if(!String.valueOf(strtoworkon).substring(m, m+(input1)).contains("#")){
c = String.valueOf(strtoworkon).substring(m, m+(input1));
if(!c.matches(".*[A-Z].*"))
break;
if(!mainalternatestring.contains(c))
mainalternatestring.add(c);
}
}
//for vertical combinations
nw = "#" + (String.valueOf(strtoworkon));
int counter1=0;
while(counter1 != 3){
c="";
for(int n = 0; n<= strtoworkon.length; n++){
if(nw.charAt(n) == '#'){
Character test = nw.charAt(n+counter1);
a = Character.toString(strtoworkon[n+counter1]).trim();
if(a.contains("#"))
break;
c = a+c;
c.trim();
}
}
if(!mainverticalstring.contains(c) && c.length() == input1)
mainverticalstring.add(c);
counter1++;
}
if(mainindex == 11)
break;
}
totalcount = totalcount + (2*mainalternatestring.size()) + (2*mainverticalstring.size());
}
return totalcount;
}
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
int output = 0;
int ip1 = Integer.parseInt(in.nextLine().trim());
output = combinationCounts(ip1);
System.out.println(String.valueOf(output));
}
}
のためのすべてのテストケースを満たすかどうか
あなたはこれまでに何を試しましたか? – Kiki
私は以下のコードを書きました – Rashmi