Java：再度プレイするかどうかをユーザーに確認しますか？

Question

私はロックペーパーのはさみゲームを作っています。コンピューターやユーザーがベスト2/3を選んだら、ゲームをもう一度やりたいのであればプロンプトが表示されます。 "はい"の場合はプログラムが再起動し、 "いいえ"の場合はsystem.exitと推測されます。

どうすればよいですか？

public static void main(String[] args) { 
    Random r = new Random(); 
    int gameCount = 0; 
    int computerWins = 0; 
    int playerWins = 0; 
    int rock, paper, scissors; 
    rock = 1; 
    paper = 2; 
    scissors = 3; 
    int playerChoice = 0; 
    int computerChoice; 

    System.out.println("Welcome to Rock Paper Scissors! Best 2 out of 3!"); 

    //While the game count is less than 3, the loop will repeat 
    while (gameCount < 3) { 
     computerChoice = r.nextInt(3) + 1; 
     System.out.println("Enter \"Rock\", \"Paper\", or \"Scissors\""); 
     String USER_Input = userInput.next(); 
     if (USER_Input.equalsIgnoreCase("Rock")) { 
      playerChoice = 1; 
     } 
     if (USER_Input.equalsIgnoreCase("Paper")) { 
      playerChoice = 2; 
     } 
     if (USER_Input.equalsIgnoreCase("Scissors")) { 
      playerChoice = 3; 
     } 
     //If player enters anything besides rock, paper, or scissors 
     if (playerChoice <= 0 || playerChoice > 3) { 
      System.out.println("That wasn't an option"); 
      computerWins++; 
      gameCount++; 
      System.out.println("Not a valid input! Computer Wins!\n" + 
        "Player has won " +playerWins + " times and the computer " + 
        "has won " + computerWins + " times"); 

      //The game goes on, and the winners are added up! 
     } else if (playerChoice == 1 && computerChoice == 2) { 
      computerWins++; 
      gameCount++; 
      System.out.println("Rock v Paper! Computer Wins!\n" + 
        "Player has won " + playerWins + " times and the computer " + 
        "has won " + computerWins + " times"); 
     } else if (playerChoice == 2 && computerChoice == 1) { 
      playerWins++; 
      gameCount++; 
      System.out.println("Paper v Rock! Player Wins!\n" + 
        "Player has won " + playerWins + " times and the computer " + 
        "has won " + computerWins + " times"); 
     } else if (playerChoice == 2 && computerChoice == 3) { 
      computerWins++; 
      gameCount++; 
      System.out.println("Paper v Scissors! Computer Wins!\n" + 
        "Player has won " + playerWins + " times and the computer " + 
        "has won " + computerWins + " times"); 
     } else if (playerChoice == 3 && computerChoice == 2) { 
      playerWins++; 
      gameCount++; 
      System.out.println("Scissors v Paper! Player Wins!\n" + 
        "Player has won " + playerWins + " times and the computer " + 
        "has won " + computerWins + " times"); 
     } else if (playerChoice == 3 && computerChoice == 1) { 
      computerWins++; 
      gameCount++; 
      System.out.println("Scissors v Rock! Computer Wins!\n" + 
        "Player has won " + playerWins + " times and the computer " + 
        "has won " + computerWins + " times"); 
     } else if (playerChoice == 1 && computerChoice == 3) { 
      playerWins++; 
      gameCount++; 
      System.out.println("Rock v Scissors! Player Wins!\n" + 
        "Player has won " + playerWins + " times and the computer " + 
        "has won " + computerWins + " times"); 
     } else if (playerChoice == 1 && computerChoice == 1) { 
      gameCount++; 
      System.out.println("Rock v Rock! Tie!\n" + 
        "Player has won " + playerWins + " times and the computer " + 
        "has won " + computerWins + " times"); 
     } else if (playerChoice == 2 && computerChoice == 2) { 
      gameCount++; 
      System.out.println("Paper v Paper! Tie!\n" + 
        "Player has won " + playerWins + " times and the computer " + 
        "has won " + computerWins + " times"); 
     } else if (playerChoice == 3 && computerChoice == 3) { 
      gameCount++; 
      System.out.println("Paper v Paper! Tie!\n" + 
        "Player has won " + playerWins + " times and the computer " + 
        "has won " + computerWins + " times"); 
     } 

     //Check if game count reaches max games then chooses a winner 
     if (gameCount == 3 && computerWins > playerWins || computerWins == 2) { 
      System.out.println("The Computer Wins!"); 
      break; 
     } else if (gameCount == 3 && computerWins < playerWins || playerWins ==2) { 
      System.out.println("The Player Wins!"); 
     } else if (gameCount == 3 && computerWins == playerWins) { 
      System.out.println("The game is a tie!"); 
     } 
    } 
} 

Answer 1

ロジック全体がmain（） - メソッド内にあります。 while（）部分をplay（）のような新しいメソッドに移動することをお勧めします。

メインで

（）あなたのメッセージを促すと、キーボードからの入力を読んで新しいしばらく（）を実装します。

public static void main(String args[]) { 
     Scanner inputScanner = new Scanner(System.in); 
     String userInput = ""; 
     do { 
      play(); 
      System.out.print("Do you want to play again ([Y]/n)? "); 
      userInput = inputScanner.nextLine(); 
      System.out.println(userInput); 
     } while (userInput.equals("Y") || userInput.equals("")); 
} 

HTH、SiSの

Answer 2

可能な解決策は、ゲームを配置することです別のwhileループ（gameCountのものを包み込む）とwhileループ内で、変数のswitch文を作成して、gameContinueとします。ゲームの終わりに、ユーザは続行するか否かを知らせるプロンプトを受け取る。彼らの答えに基づいて、あなたは変数gameContinueの値を変更してそこに行きます。