Androidで電話番号を指定して連絡先の名前を取得する

Question

連絡先の電話番号を指定して連絡先の名前を取得しようとしています。私は1.6で動作させることができないため、すべてのAPIバージョンで動作するはずの関数を作ったが、問題を見ることができないかもしれない。

文字列のAPI定数を置き換えているため、推奨されない警告の問題はありません。

public String getContactName(final String phoneNumber) 
{ 
    Uri uri; 
    String[] projection; 

    if (Build.VERSION.SDK_INT >= 5) 
    { 
     uri = Uri.parse("content://com.android.contacts/phone_lookup"); 
     projection = new String[] { "display_name" }; 
    } 
    else 
    { 
     uri = Uri.parse("content://contacts/phones/filter"); 
     projection = new String[] { "name" }; 
    } 

    uri = Uri.withAppendedPath(uri, Uri.encode(phoneNumber)); 
    Cursor cursor = this.getContentResolver().query(uri, projection, null, null, null); 

    String contactName = ""; 

    if (cursor.moveToFirst()) 
    { 
     contactName = cursor.getString(0); 
    } 

    cursor.close(); 
    cursor = null; 

    return contactName; 
} 

Answer 1

sdkのバージョンを比較する代わりに反射を使用します。

public String getContactName(final String phoneNumber) 
{ 
    Uri uri; 
    String[] projection; 
    mBaseUri = Contacts.Phones.CONTENT_FILTER_URL; 
    projection = new String[] { android.provider.Contacts.People.NAME }; 
    try { 
     Class<?> c =Class.forName("android.provider.ContactsContract$PhoneLookup"); 
     mBaseUri = (Uri) c.getField("CONTENT_FILTER_URI").get(mBaseUri); 
     projection = new String[] { "display_name" }; 
    } 
    catch (Exception e) { 
    } 


    uri = Uri.withAppendedPath(mBaseUri, Uri.encode(phoneNumber)); 
    Cursor cursor = this.getContentResolver().query(uri, projection, null, null, null); 

    String contactName = ""; 

    if (cursor.moveToFirst()) 
    { 
     contactName = cursor.getString(0); 
    } 

    cursor.close(); 
    cursor = null; 

    return contactName; 
} 

Answer 2

これは、最新バージョンでは正常に動作するようです：

private String getContactName(Context context, String number) { 

    String name = null; 

    // define the columns I want the query to return 
    String[] projection = new String[] { 
      ContactsContract.PhoneLookup.DISPLAY_NAME, 
      ContactsContract.PhoneLookup._ID}; 

    // encode the phone number and build the filter URI 
    Uri contactUri = Uri.withAppendedPath(ContactsContract.PhoneLookup.CONTENT_FILTER_URI, Uri.encode(number)); 

    // query time 
    Cursor cursor = context.getContentResolver().query(contactUri, projection, null, null, null); 

    if(cursor != null) { 
     if (cursor.moveToFirst()) { 
      name =  cursor.getString(cursor.getColumnIndex(ContactsContract.PhoneLookup.DISPLAY_NAME)); 
      Log.v(TAG, "Started uploadcontactphoto: Contact Found @ " + number);    
      Log.v(TAG, "Started uploadcontactphoto: Contact name = " + name); 
     } else { 
      Log.v(TAG, "Contact Not Found @ " + number); 
     } 
     cursor.close(); 
    } 
    return name; 
} 

Answer 3

private String getContactNameFromNumber(String number) { 
Uri uri = Uri.withAppendedPath(PhoneLookup.CONTENT_FILTER_URI, Uri.encode(number)); 


Cursor cursor = context.getContentResolver().query(uri, new String[]{PhoneLookup.DISPLAY_NAME},null,null,null); 
if (cursor.moveToFirst()) 
{ 
    name = cursor.getString(cursor.getColumnIndex(PhoneLookup.D 

Answer 4

public static String getContactName(Context context, String phoneNumber) 
{ 
    ContentResolver cr = context.getContentResolver(); 
    Uri uri = Uri.withAppendedPath(PhoneLookup.CONTENT_FILTER_URI, Uri.encode(phoneNumber)); 
    Cursor cursor = cr.query(uri, new String[]{PhoneLookup.DISPLAY_NAME}, null, null, null); 
    if (cursor == null) 
    { 
     return null; 
    } 
    String contactName = null; 
    if(cursor.moveToFirst()) 
    { 
     contactName = cursor.getString(cursor.getColumnIndex(PhoneLookup.DISPLAY_NAME)); 
    } 

    if(cursor != null && !cursor.isClosed()) { 
     cursor.close(); 
    } 

    return contactName; 
}