appceleratorチタンsql left joinが動作しません。

Question

私はAPPCELERATOR TITANIUMで働いています。私は妙にいくつかのSQLクエリは、例えば次のように正常に動作していないされているデータベースを使用してい

：

db.execute("SELECT Location_Diners.Dining_Time,Location_Diners.First_Name,Location_Diners.Last_Name,Location_Diners.PartySize,Location_Diners.Diner_ID,Location_Diners.DinerStatusColor_ID,Location_Diners.Notes,Location_Diners.Diner_ID,Location_SeatedDiners.Table_ID FROM Location_Diners LEFT JOIN Location_SeatedDiners ON Location_Diners.Diner_ID=Location_SeatedDiners.Diner_ID"); 

これは私がここに私を助けてください取得していますエラーです.....

2011-12-21 11:47:29.416 abc[5254:ac03] [ERROR] A SQLite database error occurred on database '/Users/../iPhone Simulator/4.3.2/Applications/C377123C-7A2A-4FDF-9314-428713C885FD/Library/Application Support/database.sql': Error Domain=com.plausiblelabs.pldatabase Code=3 "An error occured parsing the provided SQL statement." UserInfo=0x6ad4330 {com.plausiblelabs.pldatabase.error.vendor.code=1, NSLocalizedDescription=An error occured parsing the provided SQL statement., com.plausiblelabs.pldatabase.error.query.string=SELECT Location_Diners.Dining_Time,Location_Diners.First_Name,Location_Diners.Last_Name,Location_Diners.PartySize,Location_Diners.Diner_ID,Location_Diners.DinerStatusColor_ID,Location_Diners.Notes,Location_Diners.Diner_ID,Location_SeatedDiners.Table_ID FROM Location_Diners LEFT JOIN Location_SeatedDiners ON Location_Diners.Diner_ID=Location_SeatedDiners.Diner_ID, com.plausiblelabs.pldatabase.error.vendor.string=no such table: Location_Diners} (SQLite #1: no such table: Location_Diners) (query: 'SELECT Location_Diners.Dining_Time,Location_Diners.First_Name,Location_Diners.Last_Name,Location_Diners.PartySize,Location_Diners.Diner_ID,Location_Diners.DinerStatusColor_ID,Location_Diners.Notes,Location_Diners.Diner_ID,Location_SeatedDiners.Table_ID FROM Location_Diners LEFT JOIN Location_SeatedDiners ON Location_Diners.Diner_ID=Location_SeatedDiners.Diner_ID') 
[ERROR] invalid SQL statement. Error Domain=com.plausiblelabs.pldatabase Code=3 "An error occured parsing the provided SQL statement." UserInfo=0x6ad4330 {com.plausiblelabs.pldatabase.error.vendor.code=1, NSLocalizedDescription=An error occured parsing the provided SQL statement., com.plausiblelabs.pldatabase.error.query.string=SELECT Location_Diners.Dining_Time,Location_Diners.First_Name,Location_Diners.Last_Name,Location_Diners.PartySize,Location_Diners.Diner_ID,Location_Diners.DinerStatusColor_ID,Location_Diners.Notes,Location_Diners.Diner_ID,Location_SeatedDiners.Table_ID FROM Location_Diners LEFT JOIN Location_SeatedDiners ON Location_Diners.Diner_ID=Location_SeatedDiners.Diner_ID, com.plausiblelabs.pldatabase.error.vendor.string=no such table: Location_Diners} in -[TiDatabaseProxy execute:] (TiDatabaseProxy.m:136) 

任意のヘルプは高く評価され................

Answer 1

ねえPrateek私はあなたがLEFT OUTER JOINを使うべきだと思います。 チェックは、この、

What joins does SQLite support?

このLEFTによるとは= LEFT OUTER JOINを登録しようが、キーワードLEFT OUTERはSQLite3のではサポートに登録しよう。見られるように

Answer 2

はhereあなたはこのようなLEFT OUTER JOIN実行する必要があります。

SELECT Location_Diners.Dining_Time, 
    Location_Diners.First_Name, 
    Location_Diners.Last_Name, 
    Location_Diners.PartySize, 
    Location_Diners.Diner_ID, 
    Location_Diners.DinerStatusColor_ID, 
    Location_Diners.Notes, 
    Location_Diners.Diner_ID, 
    Location_SeatedDiners.Table_ID 
FROM Location_Diners 
LEFT OUTER JOIN Location_SeatedDiners ON Location_Diners.Diner_ID=Location_SeatedDiners.Diner_ID