$ _POSTのプロパティを関数にどのように渡しますか？

Question

データベースの詳細を更新する関数にプロパティを渡したいと思います。私は、フォームに選択されたすべての列を関数に渡す必要があります。率直に言って、私は何をすべきかわかりません。

私のコードは次のとおりです：

if (isset($_POST["updateWineButton"])) { 

    $wineID = $_POST["wineID"]; 
    $wineCountryID = $_POST["wineCountryID"]; 
    $wineSizeID = $_POST["wineSizeID"]; 
    $wineRatingID = $_POST["wineRatingID"]; 
    $wineColourID = $_POST["wineColourID"]; 
    $packageID = $_POST["packageID"]; 
    $wineCategoryID = $_POST["wineCategoryID"]; 
    $wineCode = $_POST["wineCode"]; 
    $price = $_POST["price"]; 
    $description = $_POST["description"]; 
    $wineRating = $_POST["wineRating"]; 
    $wineIMG = $_POST["wineIMG"]; 

    updateWine($updateWine); 
    $status = "$description has been updated."; 
} 

更新ワイン機能

function updateWine($wineUpdate) 
{ 
    global $pdo; 
    $statement = $pdo->prepare("UPDATE WINE SET wineID=?, wineCountryID=?, wineSizeID=?, wineRatingID, wineColourID=?, 
          packageID=?, wineCategoryID=?, wineCode=?, price=?, description=?, wineRating=?, wineIMG=? 
          WHERE wineID=?"); 

    $statement->execute([$wineUpdate->wineID, 
     $wineUpdate->wineCountryID, 
     $wineUpdate->wineSizeID, 
     $wineUpdate->wineRatingID, 
     $wineUpdate->wineColourID, 
     $wineUpdate->packageID, 
     $wineUpdate->wineCategoryID, 
     $wineUpdate->wineCode, 
     $wineUpdate->price, 
     $wineUpdate->description, 
     $wineUpdate->wineRatingID, 
     $wineUpdate->wineIMG]); 

    $statement->fetch(); 
} 

Answer 1

私はあなたがこのような何かをしたい、正しく理解していれば、

if (isset($_POST["updateWineButton"])) { 
    $result = updateWine($_POST); 
    if($result){ 
    $status = "$description has been updated."; 
    }else{ 
    $status = "An error occurred."; 
    } 
} 

//your function woud then look like ... 

function updateWine($postdata){ 
    $wineID = $postdata["wineID"]; 
    $wineCountryID = $postdata["wineCountryID"]; 
    $wineSizeID = $postdata["wineSizeID"]; 
    $wineRatingID = $postdata["wineRatingID"]; 
    $wineColourID = $postdata["wineColourID"]; 
    $packageID = $postdata["packageID"]; 
    $wineCategoryID = $postdata["wineCategoryID"]; 
    $wineCode = $postdata["wineCode"]; 
    $price = $postdata["price"]; 
    $description = $postdata["description"]; 
    $wineRating = $postdata["wineRating"]; 
    $wineIMG = $postdata["wineIMG"]; 
    //udpate your database with the above values 
    //check if update is successful 
    return true; 
    //else if there was an error 
    return false; 
} 

Answer 2

次のようなものあなたのために働くはずです：

function updateWine() 
{ 
    global $pdo; 

    $keys = [ 
     "wineID", "wineCountryID", "wineSizeID", "wineRatingID", "wineColourID", "packageID", "wineCategoryID", 
     "wineCode", "price", "description", "wineRating", "wineIMG", 
    ]; 

    $results = []; 

    foreach ($keys as $index) { 
     if (isset($_POST[$index])) { 
      $results[$index] = $_POST[$index]; 
     } 
    } 

    $statement = $pdo->prepare("UPDATE WINE SET " . implode('=?, ', array_keys($results)) . "=? WHERE wineID =?"); 

    $statement->execute(array_merge(array_values($results), [$_POST['wineID']])); 

    $statement->fetch(); 
} 

if (isset($_POST["updateWineButton"]) && isset($_POST['wineID'])) { 
    updateWine(); 
} 

希望します。