Chrome拡張機能を使用してURLをデコードする

Question

サイトに表示されているエンコードされたURLをデコードするためにGoogle Chromeの小さな拡張機能を作成しようとしています。私はいくつかの時間前にJavaでコアメソッドを書き、誰もが持っていた場合はJavaScriptを

function decodeURL(Encoded) { 
var Length = Encoded.length; 
var Counter = 0; 
var Character; 
var Decoded = ""; 
for (Counter = 0; Counter < Length; Counter++) { 
    Character = Encoded.charAt(Counter); 
    if (Character === 37 && Encoded.charAt(Counter + 1) === 50 && Encoded.charAt(Counter + 2) === 70) { 
     Counter += 2; 
     Decoded += "/"; 
    } else if (Character === 37 && Encoded.charAt(Counter + 1) === 51 && Encoded.charAt(Counter + 2) === 65) { 
     Counter += 2; 
     Decoded += ":"; 
    } else if (Character === 37 && Encoded.charAt(Counter + 1) === 50 && Encoded.charAt(Counter + 2) === 49) { 
     Counter += 2; 
     Decoded += "!"; 
    } else if (Character === 37 && Encoded.charAt(Counter + 1) === 50 && Encoded.charAt(Counter + 2) === 50) { 
     Counter += 2; 
     Decoded += "\""; 
    } else if (Character === 37 && Encoded.charAt(Counter + 1) === 50 && Encoded.charAt(Counter + 2) === 51) { 
     Counter += 2; 
     Decoded += "#"; 
    } else if (Character === 37 && Encoded.charAt(Counter + 1) === 50 && Encoded.charAt(Counter + 2) === 52) { 
     Counter += 2; 
     Decoded += "$"; 
    } else if (Character === 37 && Encoded.charAt(Counter + 1) === 50 && Encoded.charAt(Counter + 2) === 53) { 
     Counter += 2; 
     Decoded += "%"; 
    } else if (Character === 37 && Encoded.charAt(Counter + 1) === 51 && Encoded.charAt(Counter + 2) === 68) { 
     Counter += 2; 
     Decoded += "="; 
    } else if (Character === 37 && Encoded.charAt(Counter + 1) === 51 && Encoded.charAt(Counter + 2) === 70) { 
     Counter += 2; 
     Decoded += "?"; 
    } else { 
     Decoded += Character; 
    } 
return Decoded; 

} }の代わりに復号化されたURLの

それは何も（エラーなしなしString）を返しません

に変換しようとしましたエラーが発生する可能性があるアイデアは、私は感謝するだろう。

Answer 1

JSのビ​​ルドイン機能を使用します。
encodeURI()とdecodeURI()

decodeURI("https://developer.mozilla.org/ru/docs/JavaScript_%D1%88%D0%B5%D0%BB%D0%BB%D1%8B"); 

に戻るので、 "https://developer.mozilla.org/ru/docs/JavaScript_шеллы"

独自の関数を作成する必要はありません。

Answer 2

forループの外で、あなたのリターンを移動

：

function decodeURL(Encoded) { 
    var Length = Encoded.length; 
    var Character; 
    var Decoded = ""; 
    for (var Counter = 0; Counter < Length; Counter++) { 
     Character = Encoded.charAt(Counter); 
     if (Character === 37 && Encoded.charAt(Counter + 1) === 50 && Encoded.charAt(Counter + 2) === 70) { 
      Counter += 2; 
      Decoded += "/"; 
     } else if (Character === 37 && Encoded.charAt(Counter + 1) === 51 && Encoded.charAt(Counter + 2) === 65) { 
      Counter += 2; 
      Decoded += ":"; 
     } else if (Character === 37 && Encoded.charAt(Counter + 1) === 50 && Encoded.charAt(Counter + 2) === 49) { 
      Counter += 2; 
      Decoded += "!"; 
     } else if (Character === 37 && Encoded.charAt(Counter + 1) === 50 && Encoded.charAt(Counter + 2) === 50) { 
      Counter += 2; 
      Decoded += "\""; 
     } else if (Character === 37 && Encoded.charAt(Counter + 1) === 50 && Encoded.charAt(Counter + 2) === 51) { 
      Counter += 2; 
      Decoded += "#"; 
     } else if (Character === 37 && Encoded.charAt(Counter + 1) === 50 && Encoded.charAt(Counter + 2) === 52) { 
      Counter += 2; 
      Decoded += "$"; 
     } else if (Character === 37 && Encoded.charAt(Counter + 1) === 50 && Encoded.charAt(Counter + 2) === 53) { 
      Counter += 2; 
      Decoded += "%"; 
     } else if (Character === 37 && Encoded.charAt(Counter + 1) === 51 && Encoded.charAt(Counter + 2) === 68) { 
      Counter += 2; 
      Decoded += "="; 
     } else if (Character === 37 && Encoded.charAt(Counter + 1) === 51 && Encoded.charAt(Counter + 2) === 70) { 
      Counter += 2; 
      Decoded += "?"; 
     } else { 
      Decoded += Character; 
     } 

    } 
    return Decoded; 
} 
console.log(decodeURL("???$$$?"));