MySQLの - と結合されたテーブル

Question

上のクエリ私はかなり長いSQLクエリがあります。

SELECT *, content.contentID AS thisID 
FROM content 
LEFT JOIN link_keywords ON content.contentID = link_keywords.contentID 
LEFT JOIN link_countries ON content.contentID = link_countries.contentID 
LEFT JOIN link_sections ON content.contentID = link_sections.contentID 
WHERE status = '1' AND typeID = '1' 
GROUP BY contentID 
ORDER BY creationDate DESC 

を、私は戻って結果セットを取得し、私がやりたいことはどこから来ているsectionID（すべての結果を表示していますつまり、セクション3とセクション4の両方にあるすべての結果です。

次のクエリは何も返しません。おそらく、これは単一のsectionIDは3と4に等しい。私が必要とするのはcontent.contentIDで、sectionIDは3と4に等しい。

SELECT *, content.contentID AS thisID 
FROM content 
LEFT JOIN link_keywords ON content.contentID = link_keywords.contentID 
LEFT JOIN link_countries ON content.contentID = link_countries.contentID 
LEFT JOIN link_sections ON content.contentID = link_sections.contentID 
WHERE status = '1' AND typeID = '1' AND (sectionID = '3' AND sectionID = '4') 
GROUP BY contentID 
ORDER BY creationDate DESC 

Answer 1

あなたは副問い合わせを使用することができます。

SELECT *, content.contentID AS thisID 
FROM content 
LEFT JOIN link_keywords ON content.contentID = link_keywords.contentID 
LEFT JOIN link_countries ON content.contentID = link_countries.contentID 
LEFT JOIN link_sections ON content.contentID = link_sections.contentID 
WHERE status = '1' AND typeID = '1' AND 
     content.contentID IN (SELECT section3.contentID 
          FROM link_sections AS section3 
          WHERE sectionID = 3) AND 
     content.contentID IN (SELECT section4.contentID 
          FROM link_sections AS section4 
          WHERE sectionID = 4) 
GROUP BY contentID 
ORDER BY creationDate DESC 

Answer 2

これを試してください：あなたがする必要がどのような

SELECT 
    *, 
    content.contentID AS thisID 
FROM content 
    LEFT JOIN link_keywords 
    ON content.contentID = link_keywords.contentID 
    LEFT JOIN link_countries 
    ON content.contentID = link_countries.contentID 
    LEFT JOIN link_sections 
    ON content.contentID = link_sections.contentID 
WHERE 
(SELECT COUNT(contentID) AS counter FROM link_sections s2 WHERE s2.contentID=content.contentID AND (sectionID='3' OR sectionID='4') GROUP BY contentID)=2 
    AND STATUS = '1' 
    AND typeID = '1' 
    AND (sectionID = '3' 
     OR sectionID = '4') 
GROUP BY content.contentID 
ORDER BY creationDate DESC; 

Answer 3

は、セクションID =「3」で行を選択し、セクションID =「4」で行の結果を交差しています。