"toursByHotels"の下にあるオブジェクトの配列を取る - このデータを取得して、同じ名前(ホテルの名前、つまりマリオットなど)を持つ各オブジェクトのツアーの合計を取得します。名前でオブジェクトを整理する
同じ名前の5つの新しい配列を作成する必要があるより簡単な方法はありますか?
var toursByHotel = [
{
"name": "Marriott",
"month": 1,
"tours": 10
},
{
"name": "Marriott",
"month": 2,
"tours": 15
},
{
"name": "Marriott",
"month": 3,
"tours": 8
},
{
"name": "Marriott",
"month": 4,
"tours": 12
},
{
"name": "Marriott",
"month": 5,
"tours": 18
},
{
"name": "Marriott",
"month": 6,
"tours": 25
},
{
"name": "Marriott",
"month": 7,
"tours": 40
},
{
"name": "Marriott",
"month": 8,
"tours": 33
},
{
"name": "Marriott",
"month": 9,
"tours": 25
},
{
"name": "Marriott",
"month": 10,
"tours": 21
},
{
"name": "Marriott",
"month": 11,
"tours": 18
},
{
"name": "Marriott",
"month": 12,
"tours": 14
},
{
"name": "Springhill",
"month": 1,
"tours": 10
},
{
"name": "Springhill",
"month": 2,
"tours": 15
},
{
"name": "Springhill",
"month": 3,
"tours": 8
},
{
"name": "Springhill",
"month": 4,
"tours": 12
},
{
"name": "Springhill",
"month": 5,
"tours": 18
},
{
"name": "Springhill",
"month": 6,
"tours": 25
},
{
"name": "Springhill",
"month": 7,
"tours": 40
},
{
"name": "Springhill",
"month": 8,
"tours": 33
},
{
"name": "Springhill",
"month": 9,
"tours": 25
},
{
"name": "Springhill",
"month": 10,
"tours": 21
},
{
"name": "Springhill",
"month": 11,
"tours": 18
},
{
"name": "Springhill",
"month": 12,
"tours": 14
},
{
"name": "Residence",
"month": 1,
"tours": 10
},
{
"name": "Residence",
"month": 2,
"tours": 15
},
{
"name": "Residence",
"month": 3,
"tours": 8
},
{
"name": "Residence",
"month": 4,
"tours": 12
},
{
"name": "Residence",
"month": 5,
"tours": 18
},
{
"name": "Residence",
"month": 6,
"tours": 25
},
{
"name": "Residence",
"month": 7,
"tours": 40
},
{
"name": "Residence",
"month": 8,
"tours": 33
},
{
"name": "Residence",
"month": 9,
"tours": 25
},
{
"name": "Residence",
"month": 10,
"tours": 21
},
{
"name": "Residence",
"month": 11,
"tours": 18
},
{
"name": "Residence",
"month": 12,
"tours": 14
},
{
"name": "Courtyard",
"month": 1,
"tours": 10
},
{
"name": "Courtyard",
"month": 2,
"tours": 15
},
{
"name": "Courtyard",
"month": 3,
"tours": 8
},
{
"name": "Courtyard",
"month": 4,
"tours": 12
},
{
"name": "Courtyard",
"month": 5,
"tours": 18
},
{
"name": "Courtyard",
"month": 6,
"tours": 25
},
{
"name": "Courtyard",
"month": 7,
"tours": 40
},
{
"name": "Courtyard",
"month": 8,
"tours": 33
},
{
"name": "Courtyard",
"month": 9,
"tours": 25
},
{
"name": "Courtyard",
"month": 10,
"tours": 21
},
{
"name": "Courtyard",
"month": 11,
"tours": 18
},
{
"name": "Courtyard",
"month": 12,
"tours": 14
},
{
"name": "Renaissance",
"month": 1,
"tours": 10
},
{
"name": "Renaissance",
"month": 2,
"tours": 15
},
{
"name": "Renaissance",
"month": 3,
"tours": 8
},
{
"name": "Renaissance",
"month": 4,
"tours": 12
},
{
"name": "Renaissance",
"month": 5,
"tours": 18
},
{
"name": "Renaissance",
"month": 6,
"tours": 25
},
{
"name": "Renaissance",
"month": 7,
"tours": 40
},
{
"name": "Renaissance",
"month": 8,
"tours": 33
},
{
"name": "Renaissance",
"month": 9,
"tours": 25
},
{
"name": "Renaissance",
"month": 10,
"tours": 21
},
{
"name": "Renaissance",
"month": 11,
"tours": 18
},
{
"name": "Renaissance",
"month": 12,
"tours": 14
}
];
それがこのコードのエラーの多くを取得... "e" が定義されていないと言います。 – Krang
@それはフィドルでうまく動作します。 –
- うん、それは実際にはフィドルで動作します。何らかの理由で私のコードで試してみると "結果が定義されていません"というメッセージが表示されます – Krang