bigintegerクラスを使用せずに長い整数を追加するプログラムを作成する必要があります。メソッドの戻り値の型が正しくありません
私は今、add
メソッドに取り組んでいますが、私は正しいと思いますが、メソッドの正しいデータ型を返すことに固執しており、修正方法がわかりません。ここで
は、これまでのところ、私の2クラスです:
メインクラス:
import java.util.Scanner;
public class testLargeInteger
{
public static void main(String[] args)
{
Scanner input = new Scanner(System.in);
String string1;
String string2;
int exp =0;
System.out.print("Enter the first integer: ");
//Store up the input string “string1” entered by the user from the keyboard.
string1 = input.next();
LargeInteger firstInt = new LargeInteger(string1);
System.out.print("Enter the second integer: ");
string2 = input.next();
//Store up the input string “string2” entered by the user from the keyboard.
LargeInteger secondInt = new LargeInteger(string2);
System.out.print("Enter the exponential integer: ");
//Store up the input integer “exp” entered by the user from the keyboard.
exp = input.nextInt();
LargeInteger sum = firstInt.add(secondInt);
System.out.printf ("First integer: %s \n", firstInt.display());
System.out.println("Second integer: " + secondInt.display());
System.out.println(" Exponent: " + exp);
System.out.printf (" Sum = %s \n", sum.display());
}
}
LargeInteger.class:
public class LargeInteger
{
private int[] intArray;
//convert the strings to array
public LargeInteger(String s)
{
intArray = new int[s.length()];
for (int i = 0; i < s.length(); i++)
intArray[i] = Character.digit(s.charAt(i), 10); // in base 10
}
//display the strings
public String display()
{
String result="";
for (int i = 0; i < intArray.length; i++)
result += intArray[i];
return result.toString();
}
//get first array
public int[] getIntArray()
{
return intArray;
}
public LargeInteger add(LargeInteger secondInt)
{
int[] otherValues = secondInt.getIntArray();
int maxIterations = Math.min(intArray.length, otherValues.length);
int currentResult; //to store result
int[] resultArray = new int[Math.max(intArray.length, otherValues.length) + 1];
int needToAdd = 0; //to store result should be added next step
for(int i = 0; i < maxIterations; i++)
{
currentResult = intArray[i] + otherValues[i];
resultArray[i] = currentResult % 10 + needToAdd; //if more than 9 its correct answer
needToAdd = currentResult/10; //this is what you need to add on next step
}
resultArray[Math.max(intArray.length, otherValues.length) + 1] = needToAdd;
return resultArray;
}
}
ありがとう作品:
は、その後、あなたのメソッドが返すことができます。 – Sackling