JSコール機能は、

Question

を並べ替えの配列を次の点を考慮

var array1 = [true, false]; 
var array2 = [1, 2]; 
var array3 = ["a", "b", "c"]; 

私は、すべての引数の組み合わせで私の機能myFunc(arg1, arg2, arg3)を呼びたいです。しかし、私は "foreach"地獄を避けたい。

cartesianCall(array1, array2, array3, myFunc); 

理想的アレイ（myFuncという引数）の変数countに：

それはので、私はいくつかのようにそれを呼び出すことができ、私、ということができる可能性書き込み機能ですか？

EDIT： ので、関数が呼び出されます：あなたはパラメータなしで機能しargumentsキーワードを使用し

myFunc(true, 1, "a"); 
myFunc(true, 1, "b"); 
myFunc(true, 1, "c"); 
myFunc(true, 2, "a"); 
myFunc(true, 2, "b"); 
myFunc(true, 2, "c"); 
myFunc(false, 1, "a"); 
myFunc(false, 1, "b"); 
myFunc(false, 1, "c"); 
myFunc(false, 2, "a"); 
myFunc(false, 2, "b"); 
myFunc(false, 2, "c"); 

Answer 1

http://jsfiddle.net/trevordixon/zEqKy/

function cartesianCall(func, args) { 
    var combos = allCombos.apply(this, args); 

    for (var i = 0; i < combos.length; i++) { 
     func.apply(null, combos[i]); 
    } 
} 

function allCombos(first) { 
    var isArray = toString.call(first) === "[object Array]"; 
    if (!isArray) first = [first]; // Convert non-array to an array with the value 
            // as the only element 
    else if (first.length === 0) first = [undefined]; // Convert empty array to an 
                 // array with undefined as 
                 // the only element 

    if (arguments.length === 1) return first; // base case for recursion 

    var result = [], 
     rest = allCombos.apply(this, Array.prototype.slice.call(arguments, 1)); 

    for (var i = 0; i < first.length; i++) { 
     for (var j = 0; j < rest.length; j++) { 
      result.push([first[i]].concat(rest[j])); 
     } 
    } 

    return result; 
} 

次に、このようにそれを使用します：

枚の

function printArgs() { console.log('Called with arguments:', arguments); } 

cartesianCall(printArgs, [ 
    [true, false], 
    undefined, 
    [1, 2], 
    [], 
    'a string', 
    ['a', 'b', 'c'] 
]); 

プリント：空の配列がundefinedと同じように扱われる

Called with arguments: [true, undefined, 1, undefined, "a string", "a"] 
Called with arguments: [true, undefined, 1, undefined, "a string", "b"] 
Called with arguments: [true, undefined, 1, undefined, "a string", "c"] 
Called with arguments: [true, undefined, 2, undefined, "a string", "a"] 
Called with arguments: [true, undefined, 2, undefined, "a string", "b"] 
Called with arguments: [true, undefined, 2, undefined, "a string", "c"] 
Called with arguments: [false, undefined, 1, undefined, "a string", "a"] 
Called with arguments: [false, undefined, 1, undefined, "a string", "b"] 
Called with arguments: [false, undefined, 1, undefined, "a string", "c"] 
Called with arguments: [false, undefined, 2, undefined, "a string", "a"] 
Called with arguments: [false, undefined, 2, undefined, "a string", "b"] 
Called with arguments: [false, undefined, 2, undefined, "a string", "c"] 

注意。

Answer 2

が宣言：

function cartesianCall() { 
    for (var i = 0; i < arguments.length; i++) { 
    // do something with arguments[i] 
    } 
}